Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Without referring to tables, predict which of the following has the higher enthalpy in each case: (a) 1 \(\mathrm{mol} \mathrm{CO}_{2}(s)\) or 1 \(\mathrm{mol} \mathrm{CO}_{2}(g)\) at the same temperature, ( b) 2 \(\mathrm{mol}\) of hydrogen atoms or 1 \(\mathrm{mol}\) of \(\mathrm{H}_{2},(\mathbf{c}) 1 \mathrm{mol} \mathrm{H}_{2}(g)\) and 0.5 \(\mathrm{mol} \mathrm{O}_{2}(g)\) at \(25^{\circ} \mathrm{C}\) or 1 \(\mathrm{mol} \mathrm{H}_{2} \mathrm{O}(g)\) at \(25^{\circ} \mathrm{C},(\mathbf{d}) 1 \mathrm{mol} \mathrm{N}_{2}(g)\) at \(100^{\circ} \mathrm{C}\) or 1 \(\mathrm{mol} \mathrm{N}_{2}(g)\) at \(300^{\circ} \mathrm{C}\) .

Short Answer

Expert verified
(a) 1 mol of CO₂(g) has higher enthalpy than 1 mol of CO₂(s). (b) 2 mol of hydrogen atoms have higher enthalpy than 1 mol of H₂. (c) 1 mol H₂(g) and 0.5 mol O₂(g) have higher enthalpy than 1 mol H₂O(g) at 25°C. (d) 1 mol of N₂(g) at 300°C has a higher enthalpy than 1 mol of N₂(g) at 100°C.

Step by step solution

01

Case (a): 1 mol CO₂(s) or 1 mol CO₂(g) at the same temperature

When comparing a solid and a gas at the same temperature, the gas usually has higher enthalpy. The reason is that, in the gas state, particles have higher kinetic energy due to their increased freedom of movement. Therefore, 1 mol of CO₂(g) has higher enthalpy than 1 mol of CO₂(s).
02

Case (b): 2 mol of hydrogen atoms or 1 mol of H₂

Here, we can consider the fact that a covalent bond exists in H₂, which requires energy to break. In other words, forming a bond in H₂ releases energy, making the molecule's enthalpy lower. Therefore, 2 mol of hydrogen atoms have higher enthalpy than 1 mol of H₂.
03

Case (c): 1 mol H₂(g) and 0.5 mol O₂(g) at 25°C or 1 mol H₂O(g) at 25°C

In this case, we can use enthalpy of formation concept. The enthalpy of formation of H₂O(g) is negative, meaning that its formation releases energy. Conversely, breaking the bonds in H₂O(g) requires energy. Therefore, 1 mol H₂(g) and 0.5 mol O₂(g) have higher enthalpy since they have not yet formed into H₂O(g).
04

Case (d): 1 mol N₂(g) at 100°C or 1 mol N₂(g) at 300°C

In this case, we are comparing the same substance at two different temperatures. The higher the temperature, the more kinetic energy and, consequently, enthalpy is possessed by the particles. Therefore, 1 mol of N₂(g) at 300°C has a higher enthalpy than 1 mol of N₂(g) at 100°C.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

CO2 Phase Changes
When discussing the phase changes of carbon dioxide (\[ ext{CO}_2 \]), it's important to understand that this compound can exist in solid, liquid, and gaseous states under different conditions. However, we're focusing on the solid (\[ ext{CO}_2(s) \]) and gaseous (\[ ext{CO}_2(g) \]) phases. At the same temperature, the gaseous state of \[ ext{CO}_2 \] has a higher enthalpy than the solid state.

To explain this, we need to dive into the nature of molecules in each phase. In the gaseous state, CO₂ molecules move more freely due to higher kinetic energy. This freedom of motion is attributed to the higher energy level, meaning that more heat (enthalpy) is present in the gas form. In contrast, in the solid state, molecules are tightly packed and vibrate in fixed positions, resulting in lower kinetic energy and, consequently, lower enthalpy.

  • Gases usually have higher enthalpies compared to solids.
  • Kinetic energy, which translates to movement, greatly influences enthalpy.
Enthalpy of Formation
The concept of enthalpy of formation is crucial when considering chemical reactions, particularly when discussing the stability and energy content of compounds. It refers to the heat change associated with the formation of one mole of a compound from its elements in their standard states.

For example, when we look at the formation of water (\[ ext{H}_2 ext{O} \]) from hydrogen (\[ ext{H}_2 \]) and oxygen (\[ ext{O}_2 \]):\[ ext{H}_2(g) + 0.5 ext{O}_2(g) ightarrow ext{H}_2 ext{O}(g)\]The enthalpy of formation of water (\[ ext{H}_2 ext{O}(g) \]) is negative. This means that energy is released when water forms, making it more stable and lower in energy compared to its gaseous reactants. Thus, reactants like \[ ext{H}_2(g) \] and \[ ext{O}_2(g) \] have a higher enthalpy than the product, \[ ext{H}_2 ext{O}(g) \].

  • Enthalpy of formation helps determine the energy absorbed or released during formation.
  • Negative enthalpy of formation implies stability and energy release.
Kinetic Energy and Temperature
Kinetic energy and temperature are deeply interconnected concepts in thermodynamics. Essentially, kinetic energy refers to the energy a body possesses due to its motion, which contributes significantly to a system's temperature.

In the context of gases, temperature is a direct measure of the average kinetic energy of the particles. As temperature increases, so does the kinetic energy, making the gas particles move faster and collide more frequently. This increase in motion not only raises the temperature but also the enthalpy, since enthalpy includes energy related to temperature.

For example, consider the comparison of nitrogen gas (\[ ext{N}_2 \]) at two different temperatures:
  • At 100°C, \[ ext{N}_2(g) \] has less kinetic energy compared to \[ ext{300°C} \].
  • At 300°C, \[ ext{N}_2(g) \] particles move more vigorously, leading to higher kinetic energy and enthalpy.
This illustrates that higher temperatures correlate with an increase in both kinetic energy and enthalpy.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Burning methane in oxygen can produce three different carbon-containing products: soot (very fine particles of graphite), CO(g), and \(\mathrm{CO}_{2}(g) .\) (a) Write three balanced equations for the reaction of methane gas with oxygen to produce these three products. In each case assume that \(\mathrm{H}_{2} \mathrm{O}(l)\) is the only other product. (b) Determine the standard enthalpies for the reactions in part (a).(c) Why, when the oxygen supply is adequate, is \(\mathrm{CO}_{2}(g)\) the predominant carbon-containing product of the combustion of methane?

(a) What is meant by the term fuel value? (b) Which is a greater source of energy as food, 5 g of fat or 9 g of carbohydrate? (c) The metabolism of glucose produces \(\mathrm{CO}_{2}(g)\) and \(\mathrm{H}_{2} \mathrm{O}(l) .\) How does the human body expel these reaction products?

A 1.800 -g sample of phenol \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right)\) was burned in a bomb calorimeter whose total heat capacity is 11.66 \(\mathrm{kJ} /^{\circ} \mathrm{C}\) The temperature of the calorimeter plus contents increased from 21.36 to \(26.37^{\circ} \mathrm{C}\) (a) Write a balanced chemical equation for the bomb calorimeter reaction. (b) What is the heat of combustion per gram of phenol? Per mole of phenol?

When solutions containing silver ions and chloride ions are mixed, silver chloride precipitates $$\mathrm{Ag}^{+}(a q)+\mathrm{Cl}^{-}(a q) \longrightarrow \mathrm{AgCl}(s) \quad \Delta H=-65.5 \mathrm{kJ}$$ (a) Calculate \(\Delta H\) for the production of 0.450 mol of AgCl by this reaction. (b) Calculate \(\Delta H\) for the production of 9.00 \(\mathrm{g}\) of AgCl. (c) Calculate \(\Delta H\) when \(9.25 \times 10^{-4} \mathrm{mol}\) of AgCl dissolves in water.

Ozone, \(\mathrm{O}_{3}(g),\) is a form of elemental oxygen that plays an important role in the absorption of ultraviolet radiation in the stratosphere. It decomposes to \(\mathrm{O}_{2}(g)\) at room temperature and pressure according to the following reaction: $$2 \mathrm{O}_{3}(g) \longrightarrow 3 \mathrm{O}_{2}(g) \quad \Delta H=-284.6 \mathrm{kJ}$$ (a) What is the enthalpy change for this reaction per mole of \(\mathrm{O}_{3}(g) ?\) (b) Which has the higher enthalpy under these conditions, 2 \(\mathrm{O}_{3}(g)\) or 3 \(\mathrm{O}_{2}(g) ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free