Consider the decomposition of liquid benzene, \(\mathrm{C}_{6}
\mathrm{H}_{6}(l),\) to gaseous acetylene, \(\mathrm{C}_{2} \mathrm{H}_{2}(g) :\)
$$\mathrm{C}_{6} \mathrm{H}_{6}(l) \longrightarrow 3 \mathrm{C}_{2}
\mathrm{H}_{2}(g) \quad \Delta H=+630 \mathrm{kJ}$$ (a) What is the enthalpy
change for the reverse reaction? (b) What is \(\Delta H\) for the formation of 1
mol of acetylene? (c) Which is more likely to be thermodynamically favored,
the forward reaction or the reverse reaction? (d) If \(\mathrm{C}_{6}
\mathrm{H}_{6}(g)\) were consumed instead of \(\mathrm{C}_{6}
\mathrm{H}_{6}(l),\) would you expect the magnitude of \(\Delta H\) to increase,
decrease, or stay the same? Explain.