Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A 4.36 -g sample of an unknown alkali metal hydroxide is dissolved in 100.0 \(\mathrm{mL}\) of water. An acid-base indicator is added, and the resulting solution is titrated with 2.50 \(\mathrm{M} \mathrm{HCl}(a q)\) solution. The indicator changes color, signaling that theequivalence point has been reached, after 17.0 \(\mathrm{mL}\) of the hydrochloric acid solution has been added. (a) What is the molar mass of the metal hydroxide? (b) What is the identity of the alkalimetal cation: \(\mathrm{Li}^{+}, \mathrm{Na}^{+}, \mathrm{K}^{+}, \mathrm{Rb}^{+},\) or \(\mathrm{Cs}^{+} ?\)

Short Answer

Expert verified
The molar mass of the unknown alkali metal hydroxide (MOH) is approximately 40 g/mol. Based on the comparison with the molar masses of the known alkali metal hydroxides, the identity of the alkali metal cation is Na⁺ (sodium).

Step by step solution

01

Find the moles of HCl

: We are given the concentration (2.50 M) and volume (17.0 mL) of the HCl solution. To find the moles of HCl, we can use the formula: moles = concentration × volume Since the volume is given in milliliters, we need to convert it to liters by dividing by 1000. \(moles_{HCl} = (2.50 \, \mathrm{M}) \times (17.0 \, \mathrm{mL} \times \frac{1 \, \mathrm{L}}{1000 \, \mathrm{mL}}) \)
02

Find the moles of MOH

: At the equivalence point, the moles of HCl and MOH are equal (1:1 ratio). Therefore, \(moles_{MOH} = moles_{HCl}\).
03

Calculate the molar mass of MOH

: We are given the mass of MOH (4.36 g), and we found the moles of MOH in step 2. To calculate the molar mass, use the formula: \(molar \, mass_{MOH} = \frac{mass_{MOH}}{moles_{MOH}}\). Substitute the known values in the formula and calculate the molar mass.
04

Identify the alkali metal cation

: Compare the calculated molar mass of MOH with the molar masses of known alkali metal hydroxides (LiOH, NaOH, KOH, RbOH, and CsOH). The cation with the closest molar mass to the calculated molar mass will be the identity of the alkali metal cation in the unknown hydroxide.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
Understanding the molar mass of a substance is crucial for various chemical calculations. Molar mass is the mass of one mole of a substance and is usually expressed in grams per mole (g/mol). It is the sum of the atomic masses of all atoms in a molecule. To calculate the molar mass, you will use the formula:
\[\begin{equation}\text{Molar Mass} = \frac{\text{Total Mass of Compound}}{\text{Number of Moles}}\text{.}\end{equation}\]In an acid-base titration scenario, after finding the number of moles of the titrant (in this case, HCl), you can then compute the molar mass of the unknown substance by dividing the mass of the unknown by the number of moles of the titrant, assuming a 1:1 ratio at the equivalence point.

When the substance is an unknown alkali metal hydroxide, the process includes the additional step of obtaining the substance's mass first, which then enables you to proceed with the calculation. It is important to convert the volume of solutions to liters and note that all substances involved in calculations are pure, without impurities, for accurate molar mass determination.
Alkali Metal Hydroxide Identification
In the context of acid-base titrations, identifying an unknown alkali metal hydroxide involves comparing the calculated molar mass of the metal hydroxide with the known molar masses of common alkali metal hydroxides: LiOH, NaOH, KOH, RbOH, and CsOH. Each alkali metal has a distinctive molar mass.

Once you have the molar mass from the titration data, you check which known alkali metal hydroxide's molar mass closely matches your calculated value. Careful measurement and calculation are vital in this step to avoid misidentification. An alkali metal hydroxide is composed of an alkali metal cation and the hydroxide anion, and their combined atomic/ionic masses give the molar mass of the hydroxide.
Stoichiometry
Stoichiometry is the quantitative relationship between reactants and products in a chemical reaction. In a titration, stoichiometry helps you understand the proportions in which reactants combine. In the case of acid-base titrations, the reaction typically occurs with a 1:1 mole ratio. Therefore, the moles of acid (HCl, in our example) will equal the moles of the base (MOH) at the equivalence point.

Understanding stoichiometry allows you to make predictions about the outcome of a reaction and calculate unknown concentrations, which is particularly important when working with solutions in a titration experiment. It provides the foundation for understanding the equivalence point and is especially significant in determining the concentration of an unknown solution through titration.
Equivalence Point
The equivalence point in a titration is the moment when the quantity of titrant added is stoichiometrically equivalent to the quantity of substance present in the sample. For acid-base titrations, this is when moles of acid equal moles of base. A pH indicator or a pH meter can signal when the equivalence point is reached through a change in color or a specific pH measurement, respectively.

The significance of the equivalence point extends beyond indicating when stoichiometric amounts of reactants have been mixed. It enables chemists to calculate unknown concentrations, as seen in the process of identifying an unknown alkali metal hydroxide. Correctly interpreting the equivalence point is critical for accurate titrimetric analysis and subsequent calculations, such as molar mass determination and substance identification.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You make 1.000 L of an aqueous solution that contains 35.0 \(\mathrm{g}\) of sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right) .\) (a) What is the molarity of sucrose in this solution? (b) How many liters of water would you have to add to this solution to reduce the molarity you calculated in part (a) by a factor of two?

Ritalin is the trade name of a drug, methylphenidate, used to treat attention- deficit/hyperactivity disorder in young adults. The chemical structure of methylphenidate is (a) Is Ritalin an acid or a base? An electrolyte or a nonelectrolyte? (b) A tablet contains a 10.0 -mg dose of Ritalin. Assuming all the drug ends up in the bloodstream and the average man has a total blood volume of 5.0 \(\mathrm{L}\) , calculate the initial molarity of Ritalin in a man's bloodstream. (c) Ritalin has a half-life of 3 hours in the blood, which means that after 3 hours the concentration in the blood has decreased by half of its initial value. For the man in part (b), what is the concentration of Ritalin in his blood after 6 hours?

(a) You have a stock solution of 14.8 \(\mathrm{M} \mathrm{NH}_{3}\) . How many milliliters of this solution should you dilute to make 1000.0 \(\mathrm{mL}\) of 0.250 \(\mathrm{MNH}_{3} ?(\mathbf{b})\) you take a 10.0 -mL portion of the stock solution and dilute it to a total volume of \(0.500 \mathrm{L},\) what will be the concentration of the final solution?

Write balanced molecular and net ionic equations for the reactions of (a) hydrochloric acid with nickel, (b) dilute sulfuric acid with iron, (c) hydrobromic acid with magnesium, (d) acetic acid, \(\mathrm{CH}_{3} \mathrm{COOH},\) with zinc.

You know that an unlabeled bottle contains an aqueous solution of one of the following: \(A g N O_{3},\) CaCl \(_{2},\) or \(A l_{2}\left(S O_{4}\right)_{3}\) . A friend suggests that you test a portion of the solution with \(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}\) and then with NaCl solutions. According to your friend's logic, which of these chemical reactions could occur, thus helping you identify the solution in the bottle? (a) Barium sulfate could precipitate. (b) Silver chloride could precipitate. (c) silver sulfate could precipitate. (d) More than one, but not all, of the reactions described in answers a-c could occur. (e) All three reactions described in answers a-c could occur.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free