Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Classify each of the following aqueous solutions as a nonelectrolyte, weak electrolyte, or strong electrolyte: (a) \(\mathrm{LiClO}_{4}\), (b) \(\mathrm{HClO}\), (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) (propanol), \((\mathbf{d}) \mathrm{HClO}_{3}\) (e) \(\mathrm{CuSO}_{4}\), \((\mathbf{f}) \mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\) (sucrose).

Short Answer

Expert verified
The classifications of the given aqueous solutions are as follows: a. \(\mathrm{LiClO}_{4}\): Strong electrolyte b. \(\mathrm{HClO}\): Weak electrolyte c. \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{OH}\) (propanol): Nonelectrolyte d. \(\mathrm{HClO}_{3}\): Strong electrolyte e. \(\mathrm{CuSO}_{4}\): Strong electrolyte f. \(\mathrm{C}_{12}\mathrm{H}_{22}\mathrm{O}_{11}\) (sucrose): Nonelectrolyte

Step by step solution

01

Identify compound types for each solution

First, let us identify the compound types/formulas for each solution: a. \(\mathrm{LiClO}_4\) (lithium perchlorate) - Ionic salt b. \(\mathrm{HClO}\) (hypochlorous acid) - Weak acid c. \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{OH}\) (propanol) - Covalent compound d. \(\mathrm{HClO}_{3}\) (chloric acid) - Strong acid e. \(\mathrm{CuSO}_4\) (copper sulfate) - Ionic salt f. \(\mathrm{C}_{12}\mathrm{H}_{22}\mathrm{O}_{11}\) (sucrose) - Covalent compound
02

Classify solutions based on compound types

Using the information found in Step 1, we can now classify each solution: a. \(\mathrm{LiClO}_{4}\): As an ionic salt, this compound will fully dissociate into its constituent ions, making it a strong electrolyte. b. \(\mathrm{HClO}\): As a weak acid, this compound will partially dissociate into ions, making it a weak electrolyte. c. \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{OH}\) (propanol): As a covalent compound, this compound will not dissociate into ions, making it a nonelectrolyte. d. \(\mathrm{HClO}_{3}\): As a strong acid, this compound will fully dissociate into its constituent ions, making it a strong electrolyte. e. \(\mathrm{CuSO}_{4}\): As an ionic salt, this compound will fully dissociate into its constituent ions, making it a strong electrolyte. f. \(\mathrm{C}_{12}\mathrm{H}_{22}\mathrm{O}_{11}\) (sucrose): As a covalent compound, this compound will not dissociate into ions, making it a nonelectrolyte.
03

Provide final classifications

From the classifications found in Step 2, we can provide the final classifications: a. \(\mathrm{LiClO}_{4}\): Strong electrolyte b. \(\mathrm{HClO}\): Weak electrolyte c. \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{OH}\) (propanol): Nonelectrolyte d. \(\mathrm{HClO}_{3}\): Strong electrolyte e. \(\mathrm{CuSO}_{4}\): Strong electrolyte f. \(\mathrm{C}_{12}\mathrm{H}_{22}\mathrm{O}_{11}\) (sucrose): Nonelectrolyte

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Compounds
Ionic compounds are substances composed of positive and negative ions held together by electrostatic forces, known as ionic bonds. These compounds, such as lithium perchlorate (\texttt{LiClO\(_4\)}) and copper sulfate (\texttt{CuSO\(_4\)}), are typically formed when a metal reacts with a nonmetal.

When ionic compounds dissolve in water, they dissociate into their constituent ions. This process enhances the solution's ability to conduct electricity, as the free ions move to the electrodes when an electric potential is applied. Hence, solutions containing dissolved ionic compounds are classified as strong electrolytes due to their high solution conductivity.
Acid-Base Chemistry
Acid-base chemistry is a fundamental concept involving the donation and acceptance of protons (hydrogen ions). Acids, like hypochlorous acid (\texttt{HClO}) and chloric acid (\texttt{HClO\(_3\)}), are proton donors, while bases are proton accepters. Acids are further classified as strong or weak based on their dissociation in water.

Strong acids, like chloric acid, dissociate completely, releasing a large number of hydrogen ions, hence being strong electrolytes. In contrast, weak acids, such as hypochlorous acid, only partially dissociate, leading to fewer free ions and classifying them as weak electrolytes. This partial dissociation characterizes weak acid solutions with moderate solution conductivity.
Solution Conductivity
Solution conductivity refers to the ability of an aqueous solution to conduct an electric current. It is a critical property that stems from the presence of free ions within the solution. Ionic compounds and strong acids, when dissolved in water, break down into cations and anions that can move freely, allowing for the flow of electricity.

For instance, lithium perchlorate and copper sulfate are strong electrolytes, providing high solution conductivity due to their full dissociation in water. Similarly, chloric acid is a strong acid that completely ionizes, resulting in a high concentration of ions and strong conductivity. However, weak acids like hypochlorous acid have fewer ions, resulting in lower conductivity.
Covalent Compounds
Covalent compounds, such as propanol (\texttt{CH\(_3\)CH\(_2\)CH\(_2\)OH}) and sucrose (\texttt{C\(_{12}\)H\(_{22}\)O\(_{11}\)}), are formed by sharing electrons between atoms, creating covalent bonds. Unlike ionic compounds, covalent compounds do not usually dissociate into ions in a solution.

As a result, they do not contribute to the solution's conductivity, classifying them as nonelectrolytes. This means that solutions containing covalent compounds like propanol and sucrose do not conduct electricity well, as there are no free ions to carry the current. Understanding the nature of covalent compounds helps us predict and explain the electrical properties of various solutions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the following are redox reactions? For those that are, indicate which element is oxidized and which is reduced. For those that are not, indicate whether they are precipitation or neutralization reactions.\begin{equation} \begin{array}{c}{\text { (a) } \mathrm{P}_{4}(s)+10 \mathrm{HClO}(a q)+6 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow} \\\ \quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad{\quad 4 \mathrm{H}_{3} \mathrm{PO}_{4}(a q)+10 \mathrm{HCl}(a q)}\end{array} \end{equation} \begin{equation} \begin{array}{l}\quad\quad\quad\quad\quad\quad{\text { (b) } \mathrm{Br}_{2}(l)+2 \mathrm{K}(s) \longrightarrow 2 \mathrm{KBr}(s)} \\\\\quad\quad\quad\quad\quad\quad {\text { (c) } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}(l)+3 \mathrm{O}_{2}(g) \longrightarrow 3 \mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{CO}_{2}(g)}\end{array} \end{equation} \begin{equation} \begin{array}{r}\quad\quad\quad\quad{\text { (d) } \mathrm{ZnCl}_{2}(a q)+2 \mathrm{NaOH}(a q) \longrightarrow \mathrm{Zn}(\mathrm{OH})_{2}(s)+} \\ {2 \mathrm{NaCl}(a q)}\end{array} \end{equation}

Indicate the concentration of each ion or molecule present in the following solutions: (a) 0.25\(M\) NaNO \(_{3}\) , (b) \(1.3 \times 10^{-2} M \mathrm{MgSO}_{4},(\mathbf{c}) 0.0150 M \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6},(\mathbf{d})\) a mixture of 45.0 \(\mathrm{mL}\) of 0.272 \(\mathrm{M} \mathrm{NaCl}\) and 65.0 \(\mathrm{mL}\) of 0.0247 \(\mathrm{M}\) \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3} .\) Assume that the volumes are additive.

An aqueous solution of an unknown solute is tested with litmus paper and found to be acidic. The solution is weakly conducting compared with a solution of NaCl of the same concentration. Which of the following substances could the unknown be: KOH, \(\mathrm{NH}_{3}, \mathrm{HNO}_{3}, \mathrm{KClO}_{2}, \mathrm{H}_{3} \mathrm{PO}_{3}, \mathrm{CH}_{3} \mathrm{COCH}_{3}(\) acetone)?

(a) Which will have the highest concentration of potassium ion: \(0.20 M \mathrm{KCl}, 0.15 M \mathrm{K}_{2} \mathrm{CrO}_{4},\) or 0.080\(M \mathrm{K}_{3} \mathrm{PO}_{4} ?\) (b) Which will contain the greater number of moles of potassium ion: 30.0 \(\mathrm{mL}\) of 0.15 \(\mathrm{M} \mathrm{K}_{2} \mathrm{CrO}_{4}\) or 25.0 \(\mathrm{mL}\) of 0.080 \(\mathrm{M} \mathrm{K}_{3} \mathrm{PO}_{4} ?\)

Antacids are often used to relieve pain and promote healing in the treatment of mild ulcers. Write balanced net ionic equations for the reactions between the aqueous HCl in the stomach and each of the following substances used in various antacids: (a) \(\mathrm{Al}(\mathrm{OH})_{3}(\mathrm{s}),\) (b) \(\mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{s})\), \((\mathbf{c}) \mathrm{MgCO}_{3}(s)\), \((\mathbf{d}) \mathrm{NaAl}\left(\mathrm{CO}_{3}\right)(\mathrm{OH})_{2}(s),\) (e) \(\mathrm{CaCO}_{3}(\mathrm{s}).\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free