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What is the molecular formula of each of the following compounds? $$ \begin{array}{l}{\text { (a) empirical formula } \mathrm{HCO}_{2} \text { , molar mass }=90.0 \mathrm{g} / \mathrm{mol}} \\ {\text { (b) empirical formula } \mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}, \text { molar mass }=88.0 \mathrm{g} / \mathrm{mol}}\end{array} $$

Short Answer

Expert verified
The molecular formulas for the given compounds are: (a) H2C2O4 (b) C4H8O2

Step by step solution

01

Calculate the molar mass of the empirical formula

First, we need to figure out the molar mass of the given empirical formulas. This can be done by adding the molar masses of the constituent elements. For (a): empirical formula = HCO2. Therefore, molar mass = (1*1.01)+(1*12.01)+(2*16.00) \(=\) 1.01 + 12.01 + 32.00 \(=\) 45.02 g/mol. For (b): empirical formula = C2H4O. Therefore, molar mass = (2*12.01)+(4*1.01)+(1*16.00) \(=\) 24.02 + 4.04 + 16.00 \(=\) 44.06 g/mol.
02

Determine the value of n

With the molar mass of empirical formulas, we can now calculate the value of n by dividing the molar mass of the molecular compound by the molar mass of the empirical formula. For (a): \(n = \frac{90.0 \mathrm{g/mol}}{45.02 \mathrm{g/mol}} = 2\) For (b): \(n = \frac{88.0 \mathrm{g/mol}}{44.06 \mathrm{g/mol}} = 2\)
03

Calculate the molecular formula

Now that we have the value of n, we can calculate the molecular formulas by multiplying the empirical formulas by n. For (a): molecular formula = (empirical formula) * n = (HCO2) * 2 = H2C2O4 For (b): molecular formula = (empirical formula) * n = (C2H4O) * 2 = C4H8O2
04

Provide the molecular formulas

The molecular formulas for the given compounds are as follows: (a) H2C2O4 (b) C4H8O2

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Empirical Formula
Imagine the empirical formula as the simplified blueprint of a compound's composition. It represents the lowest whole number ratio of the elements within a molecule. For instance, the empirical formula for glucose is CH2O, which reflects that for every carbon atom, there are two hydrogen atoms and one oxygen atom. This does not necessarily reflect the total number of atoms in the molecule, but rather the simple ratio that defines the proportion of elements.

To determine an empirical formula, one usually starts with the percent composition of each element, which can often be found from laboratory analyses. From there, the percent values are converted into moles, and the mole ratio of the elements is reduced to the simplest whole-number terms. This fundamental step is crucial as it lays the groundwork for determining the actual molecular formula of the compound.
Molar Mass Calculation
Calculating molar mass is like getting the total weight of all atoms within a compound. It requires adding the mass of each individual atom, as indicated in the periodic table, multiplied by the number of times that atom appears in the formula. This sum gives you the mass of one mole of the compound, which is measured in grams per mole (g/mol).

For educational clarity, let's say we have an empirical formula of C3H6O3. The molar masses for carbon, hydrogen, and oxygen are approximately 12.01 g/mol, 1.01 g/mol, and 16.00 g/mol, respectively. Therefore, the molar mass of C3H6O3 would be calculated as follows:
  • (3 * 12.01 g/mol) for Carbon
  • (6 * 1.01 g/mol) for Hydrogen
  • (3 * 16.00 g/mol) for Oxygen
  • Summing these gives the molar mass of the compound.
The precision of this step is critical, as it affects subsequent calculations in finding the molecular formula.
Molecular Compound
A molecular compound is comprised of molecules formed by atoms of two or more different elements. The molecular formula provides a full account of the specific number of each type of atom in a molecule, representing the actual structure rather than just a ratio like the empirical formula. For example, the molecular formula for acetic acid is C2H4O2, indicating two carbon atoms, four hydrogen atoms, and two oxygen atoms per molecule.

To deduce the molecular formula when given the empirical formula and molar mass, we use a factor (\(n\)) which is determined by dividing the molar mass of the molecular compound by the molar mass of the empirical formula. Multiplying the empirical formula by this factor gives us the true molecular formula, revealing the actual number of atoms present in a single molecule of the compound. This distinction is not just a nuance; it affects the physical and chemical properties and the behavior of the substance in various reactions.

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Most popular questions from this chapter

Write a balanced chemical equation for the reaction that occurs when (a) \(\mathrm{Mg}(s)\) reacts with \(\mathrm{Cl}_{2}(g) ;\) (b) barium carbonate decomposes into barium oxide and carbon dioxide gas when heated; (c) the hydrocarbon styrene, \(\mathrm{C}_{8} \mathrm{H}_{8}(l),\) is combusted in air; (d) dimethylether, \(\mathrm{CH}_{3} \mathrm{OCH}_{3}(g),\) is combusted in air.

Propenoic acid, \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}_{2},\) is a reactive organic liquid that is used in the manufacturing of plastics, coatings, and adhesives. An unlabeled container is thought to contain this liquid. A 0.275 -g sample of the liquid is combusted to produce 0.102 gof water and 0.374 g carbon dioxide. Is the unknown liquid propenoic acid? Support your reasoning with calculations.

Determine the empirical and molecular formulas of each of the following substances: (a) Styrene, a compound used to make Styrofoam' cups and insulation, contains 92.3\(\% \mathrm{C}\) and 7.7\(\% \mathrm{H}\) by mass and has a molar mass of 104 \(\mathrm{g} / \mathrm{mol} .\) (b) Caffeine, a stimulant found in coffee, contains 49.5\(\% \mathrm{C}\) , \(5.15 \% \mathrm{H}, 28.9 \% \mathrm{N},\) and 16.5\(\% \mathrm{O}\) by mass and has a molar mass of 195 \(\mathrm{g} / \mathrm{mol} .\) (c) Monosodium glutamate (MSG), a flavor enhancer in certain foods, contains \(35.51 \% \mathrm{C}, 4.77 \% \mathrm{H}, 37.85 \% \mathrm{O}\) , \(8.29 \% \mathrm{N},\) and 13.60\(\% \mathrm{Na}\) , and has a molar mass of 169 \(\mathrm{g} / \mathrm{mol} .\)

When a mixture of 10.0 g of acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\) and 10.0 \(\mathrm{g}\) of oxygen \(\left(\mathrm{O}_{2}\right)\) is ignited, the resulting combustion reaction produces \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) . (a) Write the balanced chemical equation for this reaction. (b) Which is the limiting reactant? (c) How many grams of \(\mathrm{C}_{2} \mathrm{H}_{2}, \mathrm{O}_{2}, \mathrm{CO}_{2},\) and \(\mathrm{H}_{2} \mathrm{O}\) are present after the reaction is complete?

The fizz produced when an Alka-Seltzer tablet is dissolved in water is due to the reaction between sodium bicarbonate \(\left(\mathrm{NaHCO}_{3}\right)\) and citric acid \(\left(\mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}\right) :\) $$ \begin{aligned} 3 \mathrm{NaHCO}_{3}(a q)+\mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}(a q) & \longrightarrow \\ & 3 \mathrm{CO}_{2}(g)+3 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Na}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}(a q) \end{aligned} $$ In a certain experiment 1.00 g of sodium bicarbonate and 1.00 g of citric acid are allowed to react. (a) Which is the limiting reactant? (b) How many grams of carbon dioxide form? (c) How many grams of the excess reactant remain after the limiting reactant is completely consumed?

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