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Introduced the idea of structural isomerism, with 1 -propanol and 2 -propanol as examples. Determine which of these properties would distinguish these two substances: (a) boiling point, (b) combustion analysis results, (c) molecular weight, (d) density at a given temperature and pressure. You can check on the properties of these two compounds in Wolfram Alpha (http://www. wolframalpha.com/) or the CRC Handbook of Chemistry and Physics.

Short Answer

Expert verified
The properties that can distinguish between 1-propanol and 2-propanol are (a) boiling points and (d) densities at a given temperature and pressure, as these properties differ due to their different structures. Combustion analysis results (b) and molecular weights (c) will not be helpful as both isomers have the same molecular formula (C3H8O).

Step by step solution

01

Understand the isomers

1-propanol and 2-propanol are structural isomers, which means they have the same molecular formula (C3H8O) but different structures. 1-propanol structure: CH3-CH2-CH2OH 2-propanol structure: CH3-CHOH-CH3 Now we need to compare their properties.
02

Compare boiling points

The boiling point depends on the intermolecular forces in the substance. Since 1-propanol and 2-propanol have different structures, they will likely have different boiling points. You can find the specific boiling points in the CRC Handbook or using Wolfram Alpha.
03

Compare combustion analysis results

Combustion analysis is used to determine the empirical formula of a compound by analyzing the amount of oxygen, carbon, and hydrogen in it. Both 1-propanol and 2-propanol have the same molecular formula (C3H8O) and, thus, the same empirical formula, so their combustion analysis results will not be able to distinguish between them.
04

Compare molecular weights

Since 1-propanol and 2-propanol have the same molecular formula (C3H8O), they will have the same molecular weight. Therefore, comparing their molecular weight will not help distinguish between them.
05

Compare densities

The density of a substance depends on its mass and volume. It is usually temperature- and pressure-dependent. Since 1-propanol and 2-propanol have different structures, their densities at the same temperature and pressure can differ. You can find the specific density values in the CRC Handbook or using Wolfram Alpha. In summary, to distinguish between 1-propanol and 2-propanol, we can use either (a) boiling points or (d) densities at a given temperature and pressure, as these properties differ between the two isomers. Combustion analysis results and molecular weights will not be helpful in distinguishing between them.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boiling Point
Understanding boiling point is crucial when studying structural isomers like 1-propanol and 2-propanol. Intuitively, the boiling point is the temperature at which a liquid turns into vapor. This shift from liquid to gas happens when the vapor pressure of the liquid equals the atmospheric pressure. For isomers, boiling points can vary significantly, even with the same molecular formula, due to differences in their intermolecular forces.

In the case of 1-propanol and 2-propanol, their boiling point differences arise from their molecular shape, which affects the strength of these forces. 1-propanol typically has a higher boiling point because it has a linear structure allowing for stronger hydrogen bonding between molecules compared to the more branched structure of 2-propanol. This means that more energy (in the form of heat) is needed to break these interactions and cause 1-propanol to vaporize. This property is one way we can differentiate between these two isomers.

Practical Implications

In practical applications, knowing the boiling point can be essential for the distillation process, which separates liquids based on their boiling points. It's also a key factor in solvent selection for chemical reactions or extractions.
Combustion Analysis
Combustion analysis is a method used in chemistry to determine the composition of a substance by burning it and analyzing the resulting products. This type of analysis provides information on the empirical formula of the compound, which represents the simplest whole-number ratio of the elements within a molecule.

For structural isomers, such as 1-propanol and 2-propanol, combustion analysis would yield the same results. Both compounds contain the same number and types of atoms, and therefore their combustion will produce equivalent amounts of carbon dioxide and water. This process, however, will not differentiate between isomers because it does not take molecular structure into account. It's more beneficial for determining the unknown formulas of compounds or checking the purity of a substance.

Industry Applications

Combustion analysis has industrial applications in environmental monitoring and quality control, ensuring that fuels and other substances combust efficiently and produce minimal pollutants.
Molecular Weight
Molecular weight, also called molecular mass, is the sum of the atomic weights of all atoms in a molecule. It's represented in units of atomic mass units (amu) or grams per mole (g/mol). For compounds with the same molecular formula, like our isomers 1-propanol and 2-propanol, the molecular weight will be identical because they contain the same number of each type of atom.

One might wonder why molecular weight cannot distinguish between structural isomers. The answer is simple: molecular weight is only a measure of mass and does not reflect the arrangement of atoms within the molecule. Thus, despite the functional differences that result from structural isomerism, the molecular weight remains the same.

Significance in Chemistry

The concept of molecular weight is essential for stoichiometric calculations in chemical reactions, allowing chemists to quantify the amount of reactants and products involved.
Density
Density is a property of matter that relates mass to volume and is usually expressed in grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³). For chemists, density is an especially important property when dealing with liquids and solids. It is sensitive to temperature and pressure but also to the molecular structure of a substance.

In the discussion of structural isomers like 1-propanol and 2-propanol, density becomes a distinguishing feature, much like boiling point. Their different molecular geometries lead to distinct packing efficiencies when the molecules are arranged in a liquid state. Typically, more linear molecules can pack more tightly, and hence, have a higher density. This principle means that even though the isomers have identical molecular formulas, they will likely have different densities at a given temperature and pressure.

Applications in Everyday Life

Density has several practical uses, such as in the design of objects that need to float or sink in fluids, and in the food industry, where it can determine the proper concentration of ingredients like syrups and brines.

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Most popular questions from this chapter

What is the molecular formula of each of the following compounds? $$ \begin{array}{l}{\text { (a) empirical formula } \mathrm{HCO}_{2} \text { , molar mass }=90.0 \mathrm{g} / \mathrm{mol}} \\ {\text { (b) empirical formula } \mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}, \text { molar mass }=88.0 \mathrm{g} / \mathrm{mol}}\end{array} $$

When hydrocarbons are burned in a limited amount of air, both CO and \(\mathrm{CO}_{2}\) form. When 0.450 g of a particular hydrocarbon was burned in air, 0.467 \(\mathrm{g}\) of \(\mathrm{CO}, 0.733 \mathrm{g}\) of \(\mathrm{CO}_{2},\) and 0.450 \(\mathrm{g}\) of \(\mathrm{H}_{2} \mathrm{O}\) were formed. (a) What is the empirical formula of the compound? (b) How many grams of O \(_{2}\) were used in the reaction? (c) How many grams would have been required for complete combustion?

Calcium hydride reacts with water to form calcium hydroxide and hydrogen gas. (a) Write a balanced chemical equation for the reaction. (b) How many grams of calcium hydride are needed to form 4.500 g of hydrogen?

Determine the formula weights of each of the following compounds: (a) nittrous oxide, \(\mathrm{N}_{2} \mathrm{O}\) , known as laughing gas and used as an anesthetic in dentistry; (b) benzoic acid; \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\) a substance used as a food preservative; \((c) \mathrm{Mg}(\mathrm{OH})_{2},\) the active ingredient in milk of magnesia; (d) urea, \(\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO},\) a compound used as a nitrogen fertilizer; (e) isopentyl acetate, \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{C}_{5} \mathrm{H}_{11},\) responsible for the odor of bananas.

When a mixture of 10.0 g of acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\) and 10.0 \(\mathrm{g}\) of oxygen \(\left(\mathrm{O}_{2}\right)\) is ignited, the resulting combustion reaction produces \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) . (a) Write the balanced chemical equation for this reaction. (b) Which is the limiting reactant? (c) How many grams of \(\mathrm{C}_{2} \mathrm{H}_{2}, \mathrm{O}_{2}, \mathrm{CO}_{2},\) and \(\mathrm{H}_{2} \mathrm{O}\) are present after the reaction is complete?

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