Chapter 21: Problem 80
Methyl acetate \(\left(\mathrm{CH}_{3} \mathrm{COOCH}_{3}\right)\) is formed by the reaction of acetic acid with methyl alcohol. If the methyl alcohol is labeled with oxygen-18, the oxygen-18 ends up in the methyl acetate: \(\begin{array}{l}{\text { (a) Do the } \mathrm{C}-\mathrm{OH} \text { bond of the acid and the } \mathrm{O}-\mathrm{H} \text { bond }} \\ {\text { of the alcohol break in the reaction, or do the } \mathrm{O}-\mathrm{H} \text { bond }} \\ {\text { of the acid and the } \mathrm{C}-\mathrm{OH} \text { bond of the alcohol break? }}\end{array}\) \(\begin{array}{l}{\text { (b) Imagine a similar experiment using the radioisotope }^{3} \mathrm{H} \text { , }} \\ {\text { which is called tritium and is usually denoted T. Would the }} \\ {\text { reaction between } \mathrm{CH}_{3} \mathrm{COH} \text { and } \mathrm{TOCH}_{3} \text { provide the same }} \\ {\text { information about which bond is broken as does the above }} \\ {\text { experiment with } \mathrm{H}^{18} \mathrm{OCH}_{3} ?}\end{array}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.