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Classify each of the following reactions as one of the four possible types summarized in Table \(19.3 :\) (i) spontanous at all temperatures; (ii) not spontaneous at any temperature; (iii) spontaneous at low \(T\) but not spontaneous at high \(T ;\) (iv) spontaneous at high T but not spontaneous at low \(T .\) $$ \begin{array}{c}{\text { (a) } \mathrm{N}_{2}(g)+3 \mathrm{F}_{2}(g) \longrightarrow 2 \mathrm{NF}_{3}(g)} \\ {\Delta H^{\circ}=-249 \mathrm{kJ} ; \Delta S^{\circ}=-278 \mathrm{J} / \mathrm{K}}\\\\{\text { (b) } \mathrm{N}_{2}(g)+3 \mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{NCl}_{3}(g)} \\\ {\Delta H^{\circ}=460 \mathrm{kJ} ; \Delta S^{\circ}=-275 \mathrm{J} / \mathrm{K}} \\ {\text { (c) } \mathrm{N}_{2} \mathrm{F}_{4}(g) \longrightarrow 2 \mathrm{NF}_{2}(g)} \\ {\Delta H^{\circ}=85 \mathrm{kJ} ; \Delta S^{\circ}=198 \mathrm{J} / \mathrm{K}}\end{array} $$

Short Answer

Expert verified
Reaction (a) is spontaneous at low temperatures but not at high temperatures (Type iii). Reaction (b) is not spontaneous at any temperature (Type ii). Reaction (c) is spontaneous at high temperatures but not at low temperatures (Type iv).

Step by step solution

01

Reaction (a)

For reaction (a), \[\Delta H^{\circ} = -249\mathrm{kJ}, \Delta S^{\circ} = -278\mathrm{J}/\mathrm{K}\] Both \(\Delta H\) and \(\Delta S\) are negative. Therefore, the reaction will be spontaneous at low temperatures but not at high temperatures. So, Reaction (a) is of Type (iii).
02

Reaction (b)

For reaction (b), \[\Delta H^{\circ} = 460\mathrm{kJ}, \Delta S^{\circ} = -275\mathrm{J}/\mathrm{K}\] \(\Delta H\) is positive and \(\Delta S\) is negative. So, \(\Delta G = \Delta H - T\Delta S\) is always positive, as both terms are positive. Therefore, the reaction is not spontaneous at any temperature. Thus, Reaction (b) is of Type (ii).
03

Reaction (c)

For reaction (c), \[\Delta H^{\circ} = 85\mathrm{kJ}, \Delta S^{\circ} = 198\mathrm{J}/\mathrm{K}\] \(\Delta H\) is positive, and \(\Delta S\) is positive. Therefore, the reaction will be spontaneous at high temperatures but not at low temperatures. So, Reaction (c) is of Type (iv). In summary: - Reaction (a) is Type (iii): spontaneous at low \(T\), not spontaneous at high \(T\) - Reaction (b) is Type (ii): not spontaneous at any temperature - Reaction (c) is Type (iv): not spontaneous at low \(T\), spontaneous at high \(T\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamics
Thermodynamics is a branch of physics concerned with heat and temperature and their relation to energy and work. It defines macroscopic variables, such as internal energy, entropy, and pressure, that partly describe a body of matter or radiation. It is predicated on the four laws of thermodynamics, which convey empirical facts regarding physical systems at the macroscopic scale.

Within the context of chemical reactions, thermodynamics helps us to determine whether a process is spontaneous—meaning it happens without external intervention. It is important to understand that 'spontaneity' in thermodynamics does not imply that the reaction occurs quickly; rather, it only describes the direction in which the reaction is thermodynamically favored to proceed.
Gibbs Free Energy
Gibbs free energy, symbolized as \( G \), is a thermodynamic quantity that measures the maximum or reversible work that may be performed by a thermodynamic system at a constant temperature and pressure. The change in Gibbs free energy, denoted as \( \Delta G \), is defined by the equation \( \Delta G = \Delta H - T\Delta S \), where \( \Delta H \) is the change in enthalpy, \( T \) is the temperature in Kelvin, and \( \Delta S \) is the change in entropy.

When \( \Delta G \) is negative, the process or reaction is spontaneous. If \( \Delta G \) is positive, the reaction is non-spontaneous. Therefore, we can use the signs of both \( \Delta H \) and \( \Delta S \) to predict the spontaneity of a reaction at a given temperature.
Entropy
Entropy, denoted as \( S \), is a measure of the disorder or randomness in a system. The second law of thermodynamics states that the total entropy of an isolated system can never decrease over time. This means that the entropy of the universe, which is considered an isolated system, tends to increase with time.

Detailed explanation of entropy includes its statistical interpretation: in a given macrostate, the entropy is proportional to the number of microstates available. Thus, the higher the number of microstates or configurations that a system can assume, the higher its entropy. Changes in entropy, \( \Delta S \) can significantly influence whether a process is spontaneous. An increase in entropy (\( \Delta S > 0 \) ) often favors the spontaneity of a process, particularly when coupled with a decrease in the system's enthalpy.
Enthalpy
Enthalpy, represented as \( H \), is a concept used in thermodynamics to reflect the total heat content of a system. It’s a measure of energy in a thermodynamic system. It is the sum of the internal energy added to the product of the pressure and volume of the system. \( H = U + pV \).

In reactions where the pressure is constant, the change in enthalpy, \( \Delta H \) correlates with heat absorbed or released. A negative \( \Delta H \) indicates exothermic reactions where heat is released. Conversely, a positive \( \Delta H \) involves endothermic reactions, implying that the reaction absorbs heat from its surroundings. Understanding enthalpy changes allows chemists to predict heat flow during chemical reactions, which is essential for process control and safety.

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Most popular questions from this chapter

Trouton's rule states that for many liquids at their normal boiling points, the standard molar entropy of vaporization is about \(88 \mathrm{J} / \mathrm{mol}-\mathrm{K}\) (a) Estimate the normal boiling point of bromine, \(\mathrm{Br}_{2},\) by determining \(\Delta H_{\mathrm{vap}}^{\circ}\) for \(\mathrm{Br}_{2}\) using data from Appendix C. Assume that \(\Delta H_{\text { vap }}^{\circ}\) remains constant with temperature and that Trouton's rule holds. (b) Look up the normal boiling point of \(B r_{2}\) in a chemistry handbook or at the WebElements website (www..webelements.com) and compare it to your calculation. What are the possible sources of error, or incorrect assumptions, in the calculation?

The \(K_{b}\) for methylamine \(\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)\) at \(25^{\circ} \mathrm{C}\) is given in Appendix \(\mathrm{D}\) . (a) Write the chemical equation for the equilibrium that corresponds to \(K_{b}\) . (b) By using the value of \(K_{b},\) calculate \(\Delta G^{\circ}\) for the equilibrium in part (a). (c) What is the value of \(\Delta G\) at equilibrium? (d) What is the value of \(\Delta G\) when \(\left[\mathrm{H}^{+}\right]=6.7 \times 10^{-9} M,\left[\mathrm{CH}_{3} \mathrm{NH}_{3}^{+}\right]=2.4 \times 10^{-3} \mathrm{M}\) and \(\left[\mathrm{CH}_{3} \mathrm{NH}_{2}\right]=0.098 \mathrm{M} ?\)

A certain reaction has \(\Delta H^{\circ}=+23.7 \mathrm{kJ}\) and \(\Delta S^{\circ}=\) \(+52.4 \mathrm{J} / \mathrm{K}\) . (a) Is the reaction exothermic or endothermic? (b) Does the reaction lead to an increase or decrease in the randomness or disorder of the system?(c) Calculate \(\Delta G^{\circ}\) for the reaction at 298 \(\mathrm{K}\) . (d) Is the reaction spontaneous at 298 \(\mathrm{K}\) under standard conditions?

Consider the decomposition of barium carbonate: $$ \mathrm{BaCO}_{3}(s) \rightleftharpoons \mathrm{BaO}(s)+\mathrm{CO}_{2}(g) $$ Using data from Appendix \(\mathrm{C}\) , calculate the equilibrium pressure of \(\mathrm{CO}_{2}\) at (a) 298 \(\mathrm{K}\) and \((\mathbf{b}) 1100 \mathrm{K} .\)

In chemical kinetics, the entropy of activation is the entropy change for the process in which the reactants reach the activated complex. Predict whether the entropy of activation for a bimolecular process is usually positive or negative.

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