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Lactic acid \(\left(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}\right)\) has one acidic hydrogen. A 0.10 \(\mathrm{M}\) solution of lactic acid has a pH of \(2.44 .\) Calculate \(K_{a} .\)

Short Answer

Expert verified
The acid dissociation constant (\(K_a\)) for lactic acid is approximately \(1.34 \times 10^{-4}\).

Step by step solution

01

Finding the \(\mathrm{H}^+\) concentration

We are given that a 0.10 M solution of lactic acid has a pH of 2.44. We can use the pH formula to find the concentration of hydrogen ions in the solution: \[pH = -\log [\mathrm{H}^+]\] Plugging in the pH value: \[2.44 = -\log [\mathrm{H}^+]\] Now, let's solve for the \(\mathrm{H}^+\) concentration: \[[\mathrm{H}^+] = 10^{-2.44}\] This gives us: \[[\mathrm{H}^+] \approx 3.65 \times 10^{-3} \, \mathrm{M}\]
02

Setting up the equilibrium equation

Lactic acid (denoted as \(\mathrm{HLa}\)) dissociates into hydrogen ions and lactate ions, as shown by the equilibrium reaction below: \[\mathrm{HLa} \rightleftharpoons \mathrm{H}^+ + \mathrm{La}^-\] The equilibrium constant for this reaction (\(K_a\)) can be represented as follows: \[K_a = \frac{[\mathrm{H}^+][\mathrm{La}^-]}{[\mathrm{HLa}]}\]
03

Finding the concentrations of lactic acid and lactate ions at equilibrium

We know the initial concentration of lactic acid (\([\mathrm{HLa}]_{\text{initial}} = 0.10\) M) and the change in concentration of \(\mathrm{H}^+\) ions during the dissociation (\([\mathrm{H}^+]_{\text{change}} = 3.65 \times 10^{-3}\) M). Since lactic acid loses one proton for each hydrogen ion produced, the change in lactate ion concentration is equal to the change in hydrogen ion concentration. Thus, we can find the concentrations of lactic acid and lactate ions at equilibrium by using the initial concentration and the change in concentration: \[ \begin{array}{c|c|c|c} & \mathrm{Initial} & \mathrm{Change} & \mathrm{Equilibrium}\\ \hline \mathrm{HLa} & 0.1 & -3.65 \times 10^{-3} & 0.1 - 3.65 \times 10^{-3}\\ \mathrm{H}^+ & 0 & 3.65 \times 10^{-3} & 3.65 \times 10^{-3} \\ \mathrm{La}^- & 0 & 3.65 \times 10^{-3} & 3.65 \times 10^{-3} \end{array} \]
04

Calculating \(K_a\) using the equilibrium concentrations

Now we can plug the equilibrium concentrations into the equilibrium constant expression: \[K_a = \frac{[\mathrm{H}^+][\mathrm{La}^-]}{[\mathrm{HLa}]}\] Substitute the equilibrium concentrations: \[K_a = \frac{(3.65 \times 10^{-3})(3.65 \times 10^{-3})}{(0.1 - 3.65 \times 10^{-3})}\] Now, perform the calculations: \[K_a \approx 1.34 \times 10^{-4}\] So, the acid dissociation constant (\(K_a\)) for lactic acid is approximately \(1.34 \times 10^{-4}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

pH Calculation
The pH scale is a measure of the acidity or basicity of an aqueous solution. It can be calculated using the formula:
\[pH = -\text{log}[H^+]\].
The hydrogen ion concentration (\([H^+]\)) is inversely related to pH: low pH values correspond to high concentrations of hydrogen ions, indicative of an acidic solution, while high pH values indicate lower concentrations of hydrogen ions and a basic solution. Calculating pH involves taking the negative logarithm of the hydrogen ion concentration in molarity. For instance, if a 0.10 M solution of an acid has a pH of 2.44, this reflects a hydrogen ion concentration of: \[[H^+] = 10^{-2.44} \approx 3.65 \times 10^{-3} M\].
Understanding this relationship can help students navigate chemistry problems that involve finding the strength of acids or bases in solution.
Chemical Equilibrium
In the context of acid and base reactions, chemical equilibrium is the state where the rate of the forward reaction (acid dissociating into ions) equals the rate of the reverse reaction (ions recombining into the acid). This balance does not mean the reactants and products are in equal concentration, but rather that their concentrations have stabilized at a constant ratio.
The equilibrium constant (\(K\)) for a reaction is the ratio of the concentrations of the products raised to the power of their coefficients to the concentrations of the reactants raised to the power of their coefficients as shown in a balanced chemical reaction. For the dissociation of an acid, which releases hydrogen ions, the equilibrium constant is denoted as \(K_a\). It’s crucial to grasp that when the value of \(K_a\) is high, the acid is strong as it dissociates more in water; conversely, a low \(K_a\) values indicate a weaker acid.
Dissociation of Acids
The dissociation of acids in water is a fundamental concept in acid-base chemistry. When an acid dissociates, it donates a hydrogen ion (\(H^+\)), yielding a conjugate base. The extent to which an acid dissociates in a solution is determined by its \(K_a\), the acid dissociation constant. An acid like lactic acid, \(CH_3CH(OH)COOH\), will dissociate in water to produce hydronium ions (\(H^+\)) and its conjugate base, lactate ions (\(La^-\)).
The equilibrium concentration of each species can be represented in an ICE (Initial, Change, Equilibrium) table, allowing for the calculation of the \(K_a\) value by finding the ratio of the product of the equilibrated concentrations of products over the concentration of the undissociated acid. The strength of the acid is related to how much it dissociates, which is an important concept for predicting the behavior of acids in various chemical reactions and in different environments.
Lactic Acid
Lactic acid, a carboxylic acid represented by the formula \(CH_3CH(OH)COOH\), is known for its role in various biological processes, such as lactic acid fermentation. In an aqueous solution, lactic acid can donate a hydrogen ion (\(H^+\)) from its carboxyl group, turning into its conjugate base, lactate (\(La^-\)). This simple structure of lactic acid having one acidic hydrogen allows it to act as a monocarboxylic acid.
The acid dissociation constant (\(K_a\)) for lactic acid can be experimentally determined from its pH in solution and gives insight into its acid strength. Lactic acid's \(K_a\) value is typically lower than that of strong acids, signifying that it does not completely dissociate in water, making it a weak acid. Understanding properties of weak acids like lactic acid is essential in fields ranging from biochemistry to food science.

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Most popular questions from this chapter

Calculate \(\left[\mathrm{OH}^{-}\right]\) and \(\mathrm{pH}\) for each of the following strong base solutions: \((\mathbf{a}) 0.182 \mathrm{M} \mathrm{KOH},(\mathbf{b}) 3.165 \mathrm{g}\) of \(\mathrm{KOH}\) in 500.0 mL of solution, ( c ) 10.0 \(\mathrm{mL}\) of 0.0105 \(\mathrm{MCa}(\mathrm{OH})_{2}\) diluted to \(500.0 \mathrm{mL},(\mathbf{d})\) a solution formed by mixing 20.0 \(\mathrm{mL}\) of 0.015 \(M \mathrm{Ba}(\mathrm{OH})_{2}\) with 40.0 \(\mathrm{mL}\) of \(8.2 \times 10^{-3} \mathrm{M} \mathrm{NaOH}.\)

(a) Which of the following is the stronger Bronsted-Lowry acid, HBrO or HBr? (b) Which is the stronger Bronsted-Lowry base, \(F^{-}\) or \(C l^{-}\) ?

Arrange the following 0.10\(M\) solutions in order of increasing acidity: (i) \(\mathrm{NH}_{4} \mathrm{NO}_{3},(\mathrm{ii}) \mathrm{NaNO}_{3},(\mathrm{iii}) \mathrm{CH}_{3} \mathrm{COONH}_{4},(\mathrm{iv})\) \(\mathrm{NaF},(\mathrm{v}) \mathrm{CH}_{3} \mathrm{COONa}.\)

Indicate whether each of the following statements is true or false. For each statement that is false, correct the statement to make it true. (a) Acid strength in a series of \(\mathrm{H}-\) A molecules increases with increasing size of \(\mathrm{A} .\) (b) For acids of the same general structure but differing electronegativities of the central atoms, acid strength decreases with increasing electronegativity of the central atom.(c) The strongest acid known is HF because fluorine is the most electronegative element.

(a) Give the conjugate base of the following Bronsted-Lowry acids: (i) \(\mathrm{HIO}_{3},(\mathbf{i} \mathbf{i}) \mathrm{NH}_{4}^{+} .(\mathbf{b})\) Give the conjugate acid of the following Bronsted-Lowry bases: (i) \(\mathrm{O}^{2-},(\mathbf{i} \mathbf{i}) \mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)

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