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(a) Write a chemical equation that illustrates the auto-ionization of water. (b) Write the expression for the ion-product constant for water \(K_{w}\) . (c) If a solution is described as basic, which of the following is true: (i) \(\left[\mathrm{H}^{+}\right]>\left[\mathrm{OH}^{-}\right],\) (ii) \(\left[\mathrm{H}^{+}\right]=\left[\mathrm{OH}^{-}\right],\) or (iii) \(\left[\mathrm{H}^{+}\right]<\left[\mathrm{OH}^{-}\right] ?\)

Short Answer

Expert verified
The short answer to the question is: (a) The chemical equation for the auto-ionization of water is: \[\mathrm{2\,H_2O\, \leftrightarrow\, H_3O^+ + OH^{-}}\] (b) The expression for the ion-product constant for water (\(K_w\)) is: \[K_w = [\mathrm{H^+}][\mathrm{OH^{-}}]\] (c) In a basic solution, the correct relationship between H⁺ and OH⁻ concentrations is (iii): \([\mathrm{H^+}] < [\mathrm{OH^{-}}]\]

Step by step solution

01

Part (a): Auto-Ionization of Water Chemical Equation

The auto-ionization of water is a process in which two water molecules spontaneously react to form a hydronium ion (H₃O⁺) and a hydroxide ion (OH⁻). The chemical equation for the auto-ionization of water is given by: \[\mathrm{2\,H_2O\, \leftrightarrow\, H_3O^+ + OH^{-}}\]
02

Part (b): Ion-Product Constant for Water \(K_w\) Expression

The ion-product constant for water (\(K_w\)) is the equilibrium constant for the auto-ionization of water, representing the product of the concentrations of hydronium ions (H₃O⁺ or simply H⁺) and hydroxide ions (OH⁻) at a particular temperature (25°C, for instance). The expression for \(K_w\) is given by: \[K_w = [\mathrm{H^+}][\mathrm{OH^{-}}]\] At 25°C, the value of \(K_w\) is approximately \(1.0 \times 10^{-14}\).
03

Part (c): H⁺ and OH⁻ Concentrations in a Basic Solution

Basic solutions are defined by their pH being higher than 7, meaning that they have a lower concentration of H⁺ (hydronium or hydrogen ions) compared to OH⁻ (hydroxide ions). Hence, the correct relationship between H⁺ and OH⁻ concentrations in a basic solution is: \([\mathrm{H^+}] < [\mathrm{OH^{-}}]\) Therefore, the correct answer is (iii).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ion-Product Constant for Water
Have you ever wondered why even the purest water has a pH very close to 7? This all comes down to a process known as the auto-ionization of water. Water, H2O, can act as both an acid and a base. This means that some water molecules donate protons (H+) while others accept them, forming hydronium (H3O+) and hydroxide (OH-) ions.

Now, let's focus on the ion-product constant for water, often symbolized as 'Kw'. This is a special type of equilibrium constant that applies to the auto-ionization of water. In chemical terms, it's the product of the molar concentrations of H+ and OH- ions in pure water. At room temperature, which is often taken as 25°C, this constant has a value of approximately 1.0 x 10-14. It’s crucial to note that this value changes with temperature but remains constant at a given temperature.

Why is Kw Important?

Understanding Kw is fundamental in chemistry because it ties directly to the concept of pH. It is also used to determine whether a solution is acidic or basic without the need to test the pH. Both students and chemists use this constant to make essential calculations about the composition and properties of aqueous solutions.
Kw Expression
The ion-product constant for water (Kw) isn't just a number; it is an expression that reveals much about the intrinsic properties of water. The expression for Kw is written as:

�Here’s the fascinating part: this value remains remarkably constant in all aqueous solutions, regardless of the presence of acids or bases. This gives us a powerful tool for understanding the balance of H+ and OH- ions.

Taking a glance at the molecular level, we learn that in pure water at equilibrium, the concentration of H+ and OH- ions is equal, which means both are at concentrations of 1.0 x 10-7 mol/L. These concentrations multiply to give us the ion-product constant for water, Kw.

pH and pOH Relationships
Diving deeper into the world of acidity, bases, and neutrality requires us to understand the pH and pOH scales. These scales offer us a straightforward way to express the acidity or basicity of a solution.

Simply put, the pH is a measure of the hydrogen ion concentration in a solution, while pOH measures the hydroxide ion concentration. The math behind it is pretty elegant – pH is the negative logarithm of the hydrogen ion concentration, and pOH is the negative logarithm of the hydroxide ion concentration.

These scales go hand in hand due to the Kw expression, which has a crucial relationship with pH and pOH: namely,

�pH + pOH = 14 (at 25°C)

This means if one knows either the pH or pOH of a solution, the other can be easily calculated, provided the temperature is known since this relationship is temperature dependent.

When referring to basic solutions, such as in the exercise, a pH greater than 7 means that the pOH is less than 7, confirming that the hydroxide ion concentration is greater than that of the hydrogen ions. Understanding the relationship between pH and pOH not only helps students solve chemistry problems but also allows scientists and industries to maintain the proper conditions for various chemical processes.

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Most popular questions from this chapter

Write the chemical equation and the \(K_{a}\) expression for the ionization of each of the following acids in aqueous solution. First show the reaction with \(\mathrm{H}^{+}(a q)\) as a product and then with the hydronium ion: (a) \(\mathrm{HBrO}_{2},\) (b) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{COOH} .\)

(a) Given that \(K_{a}\) for acetic acid is \(1.8 \times 10^{-5}\) and that for hypochlorous acid is \(3.0 \times 10^{-8}\) , which is the stronger acid? (b) Which is the stronger base, the acetate ion or the hypochlorite ion? (c) Calculate \(K_{b}\) values for \(C H_{3} C O O^{-}\) and \(C 1 O^{-}.\)

(a) Give the conjugate base of the following Bronsted-Lowry acids: (i) HCOOH, (ii) \(\mathrm{HPO}_{4}^{2-} .\) (b) Give the conjugate acid of the following Bronsted-Lowry bases: (i) SO \(_{4}^{2-}\) (ii) \(\mathrm{CH}_{3} \mathrm{NH}_{2} .\)

Ammonia, \(\mathrm{NH}_{3},\) acts as an Arrhenius base, a Bronsted-Lowry base, and a Lewis base, in aqueous solution. Write out the reaction \(\mathrm{NH}_{3}\) undergoes with water and explain what properties of ammonia correspond to each of the three definitions of "base."

Consider the base hydroxylamine, \(\mathrm{NH}_{2} \mathrm{OH}\) . (a) What is the conjugate acid of hydroxylamine? (b) When it acts as a base, which atom in hydroxylamine accepts a proton? (c) There are two atoms in hydroxylamine that have nonbonding electron pairs that could act as proton acceptors. Use Lewis structures and formal charges (Section 8.5) to rationalize why one of these two atoms is a much better proton acceptor than the other.

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