Chapter 16: Problem 15
(a) Give the conjugate base of the following Bronsted-Lowry acids: (i) \(\mathrm{HIO}_{3},(\mathbf{i} \mathbf{i}) \mathrm{NH}_{4}^{+} .(\mathbf{b})\) Give the conjugate acid of the following Bronsted-Lowry bases: (i) \(\mathrm{O}^{2-},(\mathbf{i} \mathbf{i}) \mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)
Short Answer
Expert verified
The conjugate bases and acids of the given Bronsted-Lowry acids and bases are:
(a) Conjugate bases:
(i) HIO₃ ➞ IO₃⁻
(ii) NH₄⁺ ➞ NH₃
(b) Conjugate acids:
(i) O²⁻ ➞ OH⁻
(ii) H₂PO₄⁻ ➞ H₃PO₄
Step by step solution
01
Identify the acid as HIO₃
The given Bronsted-Lowry acid is HIO₃.
02
Remove a proton from the acid
To find the conjugate base, we need to remove a proton (H⁺) from the given acid, which means we are left with IO₃⁻.
03
Write down the conjugate base
The conjugate base of HIO₃ is IO₃⁻.
(ii) NH₄⁺
04
Identify the acid as NH₄⁺
The given Bronsted-Lowry acid is NH₄⁺.
05
Remove a proton from the acid
To find the conjugate base, we need to remove a proton (H⁺) from the given acid, which means we are left with NH₃.
06
Write down the conjugate base
The conjugate base of NH₄⁺ is NH₃.
(b) Give the conjugate acid of the following Bronsted-Lowry bases:
(i) O²⁻
07
Identify the base as O²⁻
The given Bronsted-Lowry base is O²⁻.
08
Add a proton to the base
To find the conjugate acid, we need to add a proton (H⁺) to the given base, which means we end up with OH⁻.
09
Write down the conjugate acid
The conjugate acid of O²⁻ is OH⁻.
(ii) H₂PO₄⁻
10
Identify the base as H₂PO₄⁻
The given Bronsted-Lowry base is H₂PO₄⁻.
11
Add a proton to the base
To find the conjugate acid, we need to add a proton (H⁺) to the given base, which means we end up with H₃PO₄.
12
Write down the conjugate acid
The conjugate acid of H₂PO₄⁻ is H₃PO₄.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conjugate Base
In the world of Bronsted-Lowry acids and bases, understanding the concept of a conjugate base is central. When an acid donates a proton, or hydrogen ion (
H^+
), it transforms into its conjugate base. This transformation is crucial to acid-base reactions. For example, when
HIO_3
, an acid, loses a proton, it becomes the conjugate base,
IO_3^-
. Similarly,
NH_4^+
, when losing a proton, turns into
NH_3
, its conjugate base.
To recognize a conjugate base:
To recognize a conjugate base:
- Start by identifying the acid in the reaction.
- Remove one proton from this acid.
- The resulting species is the conjugate base.
Conjugate Acid
Just as acids have conjugate bases, bases have conjugate acids. The concept of a conjugate acid comes into play when a base accepts a proton, resulting in a newly formed acid. Consider the base
O^{2-}
; when it gains a proton, it transforms into the conjugate acid
OH^-
. Another example is
H_2PO_4^-
, which, upon accepting a proton, becomes
H_3PO_4
.
To understand conjugate acids, follow these steps:
To understand conjugate acids, follow these steps:
- Identify the base involved in the reaction.
- Add one proton to the identified base.
- The new species formed is the conjugate acid.
Proton Transfer
At the heart of Bronsted-Lowry acid-base theory is the concept of proton transfer. This process involves the movement of a proton from an acid to a base. Such transfers are fundamental to many chemical reactions and drive the formation of conjugate acid-base pairs.
Consider the transformation of HIO_3 to IO_3^- and NH_4^+ to NH_3 , where protons are transferred from these acids, converting them to their respective conjugate bases. Similarly, the transition of O^{2-} to OH^- and H_2PO_4^- to H_3PO_4 involves an addition of protons, forming conjugate acids.
Important points to remember about proton transfer:
Consider the transformation of HIO_3 to IO_3^- and NH_4^+ to NH_3 , where protons are transferred from these acids, converting them to their respective conjugate bases. Similarly, the transition of O^{2-} to OH^- and H_2PO_4^- to H_3PO_4 involves an addition of protons, forming conjugate acids.
Important points to remember about proton transfer:
- Proton transfer creates two new entities: a conjugate base and a conjugate acid.
- It demonstrates the reversible reactions where an acid becomes a base and vice versa.