Chapter 15: Problem 42
(a) If \(Q_{c}>K_{c}\) how must the reaction proceed to reach equilibrium? (b) At the start of a certain reaction, only reactants are present; no products have been formed. What is the value of \(Q_{c}\) at this point in the reaction?
Short Answer
Expert verified
(a) If \(Q_c > K_c\), the reaction must shift in the reverse direction to reach equilibrium. (b) At the start of the reaction when only reactants are present and no products have been formed, the value of \(Q_c = 0\).
Step by step solution
01
(a) Understanding the relationship between Qc and Kc
The Reaction Quotient (\(Q_c\)) is a measure of the progress of a reaction, while the Equilibrium Constant (\(K_c\)) tells us the ratio of products to reactants when the reaction is at equilibrium. When \(Q_c = K_c\), the reaction is at equilibrium. If \(Q_c > K_c\), there are more products than reactants compared to the equilibrium state. Conversely, if \(Q_c < K_c\), there are more reactants than products compared to the equilibrium state.
02
(a) Determining the direction of the reaction
In this exercise, we are given that \(Q_c > K_c\). This means that there are more products than reactants compared to the equilibrium state. To reach equilibrium, the reaction must proceed in the direction that will decrease the amount of products and increase the amount of reactants. In other words, the reaction must shift in the reverse direction.
03
(b) Identifying the starting conditions
At the beginning of the reaction, only reactants are present, and no products have been formed. Since \(Q_c\) is calculated as the ratio of concentrations of products to reactants, we can write the general expression for \(Q_c\) as: \[Q_c = \frac{[Product_1]^{x_1}[Product_2]^{x_2}\cdots}{[Reactant_1]^{y_1}[Reactant_2]^{y_2}\cdots}\]
where \(x_i\) and \(y_i\) are the stoichiometric coefficients of the respective products and reactants.
04
(b) Calculate Qc at the beginning of the reaction
Since no products have been formed, the concentration of all products is zero at the beginning of the reaction. Therefore, the numerator of the \(Q_c\) expression will be a product of zeros. Since any number multiplied by zero is zero, the entire numerator becomes zero: \[Q_c = \frac{0}{[Reactant_1]^{y_1}[Reactant_2]^{y_2}\cdots}\] The value of \(Q_c\) at this point in the reaction is therefore \(Q_c = 0\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equilibrium Constant (Kc)
The equilibrium constant, denoted as \( K_c \), plays a crucial role in understanding chemical reactions. It is a number that expresses the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium, each raised to the power of their respective stoichiometric coefficients in the balanced equation. Mathematically, it is represented as:
\[ K_c = \frac{[Product_1]^{coeff_{p1}}[Product_2]^{coeff_{p2}}\ldots}{[Reactant_1]^{coeff_{r1}}[Reactant_2]^{coeff_{r2}}\ldots} \]
where the square brackets denote concentrations, and \( coeff_\{pi\} \) and \( coeff_\{ri\} \) are the coefficients of the products and reactants, respectively.
\[ K_c = \frac{[Product_1]^{coeff_{p1}}[Product_2]^{coeff_{p2}}\ldots}{[Reactant_1]^{coeff_{r1}}[Reactant_2]^{coeff_{r2}}\ldots} \]
where the square brackets denote concentrations, and \( coeff_\{pi\} \) and \( coeff_\{ri\} \) are the coefficients of the products and reactants, respectively.
Importance of \( K_c \)
Knowing the value of \( K_c \) gives insight into the position of equilibrium. A high \( K_c \) value indicates a tendency for the reaction to yield more products, whereas a low \( K_c \) suggests a reaction favoring the reactants. It is pivotal to remember that equilibrium does not mean the concentrations of reactants and products are equal, but rather that their rates of formation and consumption are balanced, resulting in constant concentrations. Temperature affects \( K_c \) significantly; as the conditions change, so does the value of the equilibrium constant, reflecting a shift in the balance point of the reaction.Chemical Equilibrium
Chemical equilibrium is the state of a reaction in which the rates of the forward and reverse reactions are equal, leading to no net change in the concentration of reactants and products over time. This does not mean the reaction has stopped; rather, the dynamic process is ongoing, but the opposing reactions balance each other out.
Knowing when a system has reached chemical equilibrium is essential for predicting the outcome of reactions and optimizing conditions for the desired product. To quantify this state, chemists use the equilibrium constant (as discussed above), which remains unchanged at a given temperature as long as the system remains undisturbed.
Dynamic Nature of Equilibrium
Even at equilibrium, the reactant molecules are continuously converting into product molecules and vice versa. The dynamic nature of equilibrium implies that while the macroscopic properties remain unchanged, microscopic changes are always happening within the system.Knowing when a system has reached chemical equilibrium is essential for predicting the outcome of reactions and optimizing conditions for the desired product. To quantify this state, chemists use the equilibrium constant (as discussed above), which remains unchanged at a given temperature as long as the system remains undisturbed.
Reaction Direction
Determining the reaction direction is key to predicting how a reaction will proceed to reach equilibrium. The reaction quotient, \( Q_c \), helps in predicting this direction before the system has reached equilibrium.
Using \( Q_c \) to Predict Reaction Direction
When a reaction has not yet reached equilibrium, comparing the reaction quotient (\( Q_c \)) to the equilibrium constant (\( K_c \)) informs us whether the reaction will proceed forward or reverse to reach equilibrium:- If \( Q_c < K_c \), the reaction will shift forward, favoring the formation of products.
- If \( Q_c > K_c \), the reaction will shift in the reverse direction, favoring the formation of reactants.