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Many metallic catalysts, particularly the precious-metal ones, are often deposited as very thin films on a substance of high surface area per unit mass, such as alumina \(\left(\mathrm{Al}_{2} \mathrm{O}_{3}\right)\) or silica \(\left(\mathrm{Si} \mathrm{O}_{2}\right)\) (a) Why is this an effective way of utilizing the catalyst material compared to having powdered metals? ( b) How does the surface area affect the rate of reaction?

Short Answer

Expert verified
In conclusion: a) Depositing metallic catalysts as thin films on high surface area substances like alumina or silica is more effective than using powdered metals, as it provides a higher surface area, improved catalyst utilization, and enhanced stability. b) The surface area affects the rate of reaction by allowing more reactant molecules to interact with the catalyst, increasing the chances of productive collisions and a faster reaction rate.

Step by step solution

01

Understanding Catalysis

Catalysis is a process in which a substance called a catalyst speeds up a chemical reaction without being consumed in the reaction. Catalysts work by lowering the activation energy required for a reaction to occur, allowing the reaction to happen faster and more efficiently.
02

Knowing the role of Surface Area

Surface area plays a critical role in the rate of reaction, especially in heterogeneous catalysis, where the catalyst is in a different phase than the reactants. The larger the surface area, the more reactant molecules can come in contact with the catalyst, allowing for more simultaneous reaction sites and, hence, a faster overall reaction rate.
03

Discussing Thin Films vs. Powdered Metals

Depositing metallic catalysts as thin films on high surface area substances such as alumina or silica is more effective than using powdered metals for several reasons: 1. Higher surface area: By depositing the catalyst as a thin film, the catalyst's overall surface area is increased, which allows more reactant molecules to come in contact with the catalyst, leading to a faster reaction rate. 2. Improved catalyst utilization: A thin film of catalyst allows reactants to access the catalyst more easily compared to powdered metals, ensuring the catalyst material is being used more efficiently. 3. Enhanced stability: Thin films are less likely to become contaminated or degraded, ensuring a more consistent performance and better longevity of the catalyst.
04

Explaining the effect of surface area on reaction rate

As discussed earlier, the surface area of the catalyst directly affects the reaction rate in heterogeneous catalysis. A larger surface area means that there are more available sites on the catalyst where reactant molecules can interact. This effectively increases the chances of fruitful collisions between reactant molecules and catalyst, thus enhancing the reaction rate. In essence, the larger the surface area of the catalyst, the more efficient and faster the reaction will be. In conclusion: a) Depositing metallic catalysts as thin films on high surface area substances is more effective than using powdered metals because it provides a higher surface area for reactants to interact and ensures more efficient catalyst utilization with better stability. b) The surface area directly affects the rate of reaction by providing more available sites for reactant molecules to interact with the catalyst, increasing the chances of fruitful collisions and a faster reaction rate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heterogeneous Catalysis
Heterogeneous catalysis is a process wherein the catalyst exists in a different state (solid, liquid, or gas) from the reactants. The catalyst typically is a solid with reactants as gases or liquids, creating a scenario where the magic of the reaction occurs on the surface of the solid catalyst.

Imagine having countless tiny helpers, each occupying a minuscule portion of space but equipped to help transform reactants into products efficiently. That's akin to what a heterogeneous catalyst does—it's not used up or changed during the reaction, which also makes it a sustainable choice.

Why Heterogeneous Catalysts?

They're popular because of their ease of separation from the reactants and products; since they’re in different states, you often can just filter them out! Plus, their reusability makes them economically attractive in industrial processes.
Surface Area and Reaction Rate
Surface area is essentially the 'playground' where chemical reactions take place. The bigger the playground, the more room there is for reactant molecules to run around and interact with the catalyst, much like children in a play area. The larger the surface area, the more molecules that can 'play' at the same time, speeding up the reaction.

From a scientific standpoint, having a large surface area increases the number of active sites available for the reactions to take place. These active sites are special spots on the catalyst surface where reactants adhere temporarily, transforming into new products through a series of steps. It's akin to having more checkout counters open at a grocery store—the more counters available, the faster customers (or reactants) can complete their transactions (or reactions).
Catalyst Utilization
Effective catalyst utilization means getting the most out of your catalyst for as long as possible. In the world of chemistry, this translates to how well a catalyst performs its role over time without deteriorating or becoming less efficient.

Think of it as getting the best value out of a high-quality purchase. When catalysts are used optimally, the expenses involved in these chemical processes can be dramatically reduced. This concept is pivotal in industries reliant on catalysis, as it can be the difference between a profitable operation and one that hemorrhages resources.

Best Practices for Utilization

Methods to enhance catalyst utilization include proper catalyst selection, maintaining the ideal reaction conditions, and ensuring the catalyst is not wasted or overused.
Thin Film Catalysts
Thin film catalysts are the chemical equivalent of a large mural painted on a wall versus a standalone sculpture. By spreading the catalyst in a thin layer over a large area, much like paint, the catalyst provides a vast canvas for reactions to occur.

This 'spread out' approach allows for more reactant molecules to come in direct contact with the catalyst at the same time. It's a method that's both resource-smart and space-efficient, perfectly embodying the saying 'less is more'—less material for more chemical reaction 'real estate'.

The Innovation of Thin Films

These ultrathin coatings can be applied to various substrates using advanced techniques like physical vapor deposition, enhancing not only the reaction kinetics but also potentially introducing new properties to the catalyst, such as resistance to poisoning and thermal stability.

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Most popular questions from this chapter

Which of the following linear plots do you expect for a reaction \(A \longrightarrow\) products if the kinetics are (a) zero order, (b) first order, or (c) second order? [Section 14.4\(]\)

The activation energy of an uncatalyzed reaction is 95 \(\mathrm{kJ} / \mathrm{mol} .\) The addition of a catalyst lowers the activation energy to 55 \(\mathrm{kJ} / \mathrm{mol}\) . Assuming that the collision factor remains the same, by what factor will the catalyst increase the rate of the reaction at (a) \(25^{\circ} \mathrm{C},\) (b) \(125^{\circ} \mathrm{C} ?\)

For each of the following gas-phase reactions, indicate how the rate of disappearance of each reactant is related to the rate of appearance of each product: \(\begin{array}{l}{\text { (a) } \mathrm{H}_{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)} \\ {\text { (b) } 2 \mathrm{N}_{2} \mathrm{O}(g) \longrightarrow 2 \mathrm{N}_{2}(g)+\mathrm{O}_{2}(g)} \\ {\text { (c) } \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)} \\ {\text { (d) } \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{NH}_{3}(g)}\end{array}\)

Hydrogen sulfide \(\left(\mathrm{H}_{2} \mathrm{S}\right)\) is a common and troublesome pollutant in industrial wastewaters. One way to remove \(\mathrm{H}_{2} \mathrm{S}\) is to treat the water with chlorine, in which case the following reaction occurs: $$ \mathrm{H}_{2} \mathrm{S}(a q)+\mathrm{Cl}_{2}(a q) \longrightarrow \mathrm{S}(s)+2 \mathrm{H}^{+}(a q)+2 \mathrm{Cl}^{-}(a q)$$ The rate of this reaction is first order in each reactant. The rate constant for the disappearance of \(\mathrm{H}_{2} \mathrm{S}\) at \(28^{\circ} \mathrm{C}\) is \(3.5 \times 10^{-2} \mathrm{M}^{-1} \mathrm{s}^{-1}\) . If at a given time the concentration of \(\mathrm{H}_{2} \mathrm{S}\) is \(2.0 \times 10^{-4} \mathrm{M}\) and that of \(\mathrm{Cl}_{2}\) is \(0.025 \mathrm{M},\) what is the rate of formation of \(\mathrm{Cl}^{-} ?\)

(a) What are the units usually used to express the rates of reactions occurring in solution? (b) As the temperature increases, does the reaction rate increase or decrease? (c) As a reaction proceeds, does the instantaneous reaction rate increase or decrease?

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