Chapter 13: Problem 45
Calculate the molality of each of the following solutions: (a) 8.66 g of benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) dissolved in 23.6 \(\mathrm{g}\) of carbon tetrachloride \(\left(\mathrm{CCl}_{4}\right),(\mathbf{b}) 4.80 \mathrm{g}\) of NaCl dissolved in 0.350 \(\mathrm{L}\) of water.
Short Answer
Expert verified
The molality of the first solution (benzene in carbon tetrachloride) is 4.70 mol/kg, and the molality of the second solution (NaCl in water) is 0.235 mol/kg.
Step by step solution
01
Calculate the moles of benzene
To find the moles of benzene, we need to divide the mass of benzene by its molar mass. The molar mass of benzene (C6H6) is: (6 × 12.01 + 6 × 1.01) g/mol = 78.12 g/mol.
moles of benzene = \(\frac{8.66}{78.12}\)
moles of benzene = 0.1109 moles
02
Convert the mass of carbon tetrachloride to kg
Since molality is expressed in terms of moles of solute per kg of solvent, we need to convert the given mass of carbon tetrachloride (23.6 g) to kg.
mass of carbon tetrachloride = 23.6 g = 0.0236 kg
03
Calculate the molality of benzene in carbon tetrachloride
Now, we can calculate the molality of benzene in carbon tetrachloride using the formula:
molality (m) = \(\frac{moles \, of \, benzene}{mass \, of \, carbon \, tetrachloride \, (kg)}\)
molality (m) = \(\frac{0.1109}{0.0236}\)
molality (m) = 4.70 mol/kg
The molality of benzene in carbon tetrachloride is 4.70 mol/kg.
**Solution (b):**
04
Calculate the moles of NaCl
To find the moles of NaCl, we need to divide the mass of NaCl by its molar mass. The molar mass of NaCl is (22.99 + 35.45) g/mol = 58.44 g/mol.
moles of NaCl = \(\frac{4.80}{58.44}\)
moles of NaCl = 0.0822 moles
05
Convert the volume of water to mass (in kg)
We are given the volume of water (0.350 L) and need to convert it to mass (in kg) because molality is expressed in terms of mass. Since the density of water is 1 g/mL (or 1 kg/L), we can directly convert the volume to mass.
mass of water = 0.350 L × 1 kg/L = 0.350 kg
06
Calculate the molality of NaCl in water
Now, we can calculate the molality of NaCl in water using the formula:
molality (m) = \(\frac{moles \, of \, NaCl}{mass \, of \, water \, (kg)}\)
molality (m) = \(\frac{0.0822}{0.350}\)
molality (m) = 0.235 mol/kg
The molality of NaCl in water is 0.235 mol/kg.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass
The concept of molar mass is fundamental in chemistry, as it connects the mass of a substance to the amount of its particles, expressed as moles. Molar mass is the mass of one mole of a given substance, typically measured in grams per mole (g/mol).
For example, benzene \(C_{6}H_{6}\) has a molar mass calculated by summing the atomic masses of all the atoms in its molecular formula:
For example, benzene \(C_{6}H_{6}\) has a molar mass calculated by summing the atomic masses of all the atoms in its molecular formula:
- Carbon (C) has an atomic mass of approximately 12.01 g/mol.
- Hydrogen (H) has an atomic mass of approximately 1.01 g/mol.
Moles of Solute
The concept of moles relates the amount of chemical substance to its mass in grams. Calculating the moles involves dividing the mass of the substance by its molar mass, which results in the number of moles.
For instance, if you have 8.66 g of benzene, and you know its molar mass is 78.12 g/mol, the calculation would be:\(\text{moles of benzene} = \frac{8.66}{78.12} = 0.1109\) moles.This resource helps you to find out how moles give a quantitative description of a substance, allowing for practical applications in stoichiometry and chemical equations.
For instance, if you have 8.66 g of benzene, and you know its molar mass is 78.12 g/mol, the calculation would be:\(\text{moles of benzene} = \frac{8.66}{78.12} = 0.1109\) moles.This resource helps you to find out how moles give a quantitative description of a substance, allowing for practical applications in stoichiometry and chemical equations.
Mass Conversion
Converting mass units is a practical skill needed in chemistry, especially when dealing with solution concentrations like molality, which requires the mass of the solvent in kilograms.
For instance, when converting 23.6 g of carbon tetrachloride into kilograms, you divide by 1000 (since there are 1000 grams in a kilogram):\(23.6\, \text{g} = 0.0236\, \text{kg}\).This conversion is crucial for consistent and accurate calculations of solution concentrations.
For instance, when converting 23.6 g of carbon tetrachloride into kilograms, you divide by 1000 (since there are 1000 grams in a kilogram):\(23.6\, \text{g} = 0.0236\, \text{kg}\).This conversion is crucial for consistent and accurate calculations of solution concentrations.
Density of Water
Density is a property that describes how much mass of a material is contained in a given volume, often used to convert between mass and volume. For water, this value is typically 1 g/mL or 1 kg/L.
This constant density allows for easy conversions from liters to kilograms. For example, if you have 0.350 L of water, converting to mass would be:\(0.350\, \text{L} \times 1\, \text{kg/L} = 0.350\, \text{kg}\).Using the known density aids in calculating solution properties when mass or volume is involved, an important aspect in many chemistry experiments and calculations.
This constant density allows for easy conversions from liters to kilograms. For example, if you have 0.350 L of water, converting to mass would be:\(0.350\, \text{L} \times 1\, \text{kg/L} = 0.350\, \text{kg}\).Using the known density aids in calculating solution properties when mass or volume is involved, an important aspect in many chemistry experiments and calculations.
Solution Chemistry
Solution chemistry involves the study of solutes dissolved in solvents, creating solutions. Understanding the properties like molality indicates how concentrated the solute is within the solvent.
The formula for molality is the moles of solute per kilogram of solvent. This unit remains unchanged by temperature, making it highly reliable for diverse laboratory conditions.For example, the molality of a solution with 0.1109 moles of benzene in 0.0236 kg of carbon tetrachloride is calculated as:\(\text{molality (m)} = \frac{0.1109}{0.0236} = 4.70\, \text{mol/kg}\).This type of calculation helps chemists to describe how the solute interacts with the solvent on a molecular level.
The formula for molality is the moles of solute per kilogram of solvent. This unit remains unchanged by temperature, making it highly reliable for diverse laboratory conditions.For example, the molality of a solution with 0.1109 moles of benzene in 0.0236 kg of carbon tetrachloride is calculated as:\(\text{molality (m)} = \frac{0.1109}{0.0236} = 4.70\, \text{mol/kg}\).This type of calculation helps chemists to describe how the solute interacts with the solvent on a molecular level.