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In the Dumas-bulb technique for determining the molar mass of an unknown liquid, you vaporize the sample of a liquid that boils below \(100^{\circ} \mathrm{C}\) in a boiling-water bath and determine the mass of vapor required to fill the bulb. From the following data, calculate the molar mass of the unknown liquid: mass of unknown vapor, 1.012 g; volume of bulb, \(354 \mathrm{cm}^{3} ;\) pressure, 742 torr; temperature, \(99^{\circ} \mathrm{C}\) .

Short Answer

Expert verified
The molar mass of the unknown liquid is approximately 25.18 g/mol, calculated using the given data and the Ideal Gas Law equation.

Step by step solution

01

Convert units of given data

Before we proceed to use the Ideal Gas Law equation, we should make sure that all the data is in the correct units. The ideal gas constant (R) is given in units of L atm/mol K. So, we need to convert the volume to liters, temperature to Kelvin, and pressure to atm. 1. Volume conversion: Volume = 354 cm³ = 0.354 L (since there are 1,000 cm³ in a liter) 2. Temperature conversion: Temperature = 99°C = 99 + 273.15 = 372.15 K 3. Pressure conversion: Pressure = 742 torr = (742/760) atm ≈ 0.976 atm (since there are 760 torr in 1 atm) Now we have the required units for the Ideal Gas Law equation: Volume (V) = 0.354 L Temperature (T) = 372.15 K Pressure (P) = 0.976 atm
02

Calculate the number of moles using the Ideal Gas Law equation

Now that we have all the data in the appropriate units, we can use the Ideal Gas Law equation to calculate the number of moles (n). Rearranging the Ideal Gas Law equation for n: \(n = \frac{PV}{RT}\) Using the given data: n = (0.976 atm) * (0.354 L) / (0.0821 L atm/mol K) * (372.15 K) n ≈ 0.0402 moles
03

Calculate the molar mass of the unknown liquid

Now that we have the number of moles of the unknown vapor, we can calculate the molar mass of the unknown liquid using the formula: Molar mass = mass of unknown vapor/number of moles Molar mass = (1.012 g) / (0.0402 moles) Molar mass ≈ 25.18 g/mol The molar mass of the unknown liquid is approximately 25.18 g/mol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
Calculating the molar mass of a substance is a crucial step in many chemistry experiments, including the Dumas-bulb technique. The molar mass is essentially the mass of one mole of a particular substance, usually expressed in grams per mole (g/mol). In this exercise, we determine the molar mass of an unknown liquid vaporized in a bulb.
To find the molar mass, we use the formula:
  • Molar mass = \( \frac{\text{mass of vapor}}{\text{number of moles}} \)
First, we need to calculate the number of moles of the gaseous sample using the ideal gas law equation (PV = nRT). Once we determine how many moles of the gas fill the bulb, we divide the given mass of the vapor by the number of moles. This provides us with the molar mass of the unknown liquid.
This step is key, as it helps identify the liquid by comparing the calculated molar mass with known values from reference materials or databases.
Unit Conversion
Unit conversion is a vital aspect of working with scientific data, as consistent units are necessary for accurate calculations. In this particular exercise, we must ensure that all measurements are in the correct units to employ the ideal gas law correctly. Let's go through each necessary conversion:
  • Volume: The original volume of the bulb was given in cubic centimeters (cm³), which we converted to liters (L). Since there are 1,000 cm³ in a liter, the conversion is straightforward: \( 354 \text{ cm}^3 = 0.354 \text{ L} \).
  • Temperature: Originally provided in degrees Celsius (°C), temperature needs converting to Kelvin (K). This is done using the formula \( T(\text{K}) = T(°\text{C}) + 273.15 \). Thus, \( 99°\text{C} = 372.15 \text{ K} \).
  • Pressure: Given in torr, pressure needs to be in atmospheres (atm) for use in the ideal gas law. Since 1 atm = 760 torr, the conversion is \( 742 \text{ torr} \approx 0.976 \text{ atm} \).
Properly converting these units ensures that when we apply the ideal gas law, the calculations will yield correct and reliable results.
Dumas-bulb Technique
The Dumas-bulb technique is an elegant method used to determine the molar mass of an unknown liquid. Named after French chemist Jean-Baptiste Dumas, it involves vaporizing a liquid in a specialized glass bulb, allowing the vapor to occupy a known volume at a given temperature and pressure.
This technique relies on the principles of the ideal gas law, which relates pressure (P), volume (V), and temperature (T) to the amount of gas in moles (n) using the equation \(PV = nRT\). To find the molar mass of the unknown liquid, the experimenter follows these steps:
  • The liquid is vaporized, causing it to fill the bulb completely, ensuring no extra air is present inside.
  • The mass of the vapor is carefully measured after condensation.
  • Using the determined mass and calculated moles of gas, the molar mass is computed.
The Dumas-bulb technique is widely recognized for its simplicity and effectiveness, making it a popular choice in laboratories where sophisticated equipment might not be available.

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Most popular questions from this chapter

Which of the following statements is false? \begin{equation}\begin{array}{l}{\text { (a) Gases are far less dense than liquids. }} \\ {\text { (b) Gases are far more compressible than liquids. }} \\\ {\text { (c) Because liquid water and liquid carbon tetrachloride do }} \\\ {\text { not mix, neither do their vapors. }} \\ {\text { (d) The volume occupied by a gas is determined by the volume }} \\ {\text { of its container. }}\end{array}\end{equation}

Consider a mixture of two gases, \(A\) and \(B,\) confined in a closed vessel. A quantity of a third gas, \(C,\) is added to the same vessel at the same temperature. How does the addition of gas C affect the following: (a) the partial pressure of gas A, (b) the total pressure in the vessel, (c) the mole fraction of gas B?

The temperature of a \(5.00-\mathrm{L}\) container of \(\mathrm{N}_{2}\) gas is increased from \(20^{\circ} \mathrm{C}\) to \(250^{\circ} \mathrm{C}\) . If the volume is held constant, predict qualitatively how this change affects the following: (a) the average kinetic energy of the molecules; (b) the root-mean- square speed of the molecules; (c) the strength of the impact of an average molecule with the container walls; (d) the total number of collisions of molecules with walls per second.

A glass vessel fitted with a stopcock valve has a mass of 337.428 g when evacuated. When filled with Ar, it has a mass of 339.854 g. When evacuated and refilled with a mixture of Ne and Ar, under the same conditions of temperature and pressure, it has a mass of 339.076 g. What is the mole percent of Ne in the gas mixture?

Perform the following conversions: \((\mathbf{a})\) 0.912 atm to torr, \((\mathbf{b})\) 0.685 bar to kilopascals, \((\mathbf{c})\) 655 \(\mathrm{mm}\) Hg to atmospheres, \((\mathbf{d})\) \(1.323 \times 10^{5}\) Pa to atmospheres, \((\mathbf{e})\) 2.50 atm to psi.

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