Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Does the effect of intermolecular attraction on the properties of a gas become more significant or less significant if (a) the gas is compressed to a smaller volume at constant temperature; (b) the temperature of the gas is increased at constant volume?

Short Answer

Expert verified
In summary, the effect of intermolecular attraction on the properties of a gas becomes (a) more significant when the gas is compressed to a smaller volume at constant temperature, as the molecules are forced closer together and attractive forces become stronger; and (b) less significant when the temperature of the gas is increased at constant volume, as the increased kinetic energy of the molecules weakens the overall influence of intermolecular forces.

Step by step solution

01

Scenario (a) - Gas compression at constant temperature

When a gas is compressed to a smaller volume, the molecules in the gas are forced closer together. As the distance between the gas molecules becomes smaller, the intermolecular attractive forces become stronger. This is because the attractive force typically follows an inverse-power law, meaning it becomes stronger as the distance between molecules becomes smaller. Thus, the effect of intermolecular attraction becomes more significant when a gas is compressed at constant temperature.
02

Scenario (b) - Temperature increase at constant volume

When the temperature of a gas is increased, the gas molecules gain more kinetic energy. This kinetic energy allows the molecules to move faster and more freely in the container. As a result, they are more likely to overcome the intermolecular attractive forces, and the overall influence of these forces becomes weaker. Hence, in this scenario, when the temperature of the gas is increased at a constant volume, the effect of intermolecular attraction becomes less significant.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Compression
Understanding how gas compression affects the physical properties of gases is crucial in the study of chemistry and physics. When we compress a gas, we are essentially squeezing the gas molecules into a smaller space without changing the temperature.

Through this process, we observe a critical change in one key physical property: the density of the gas. As you compress the gas, you force more molecules into a given volume, increasing the gas's density. But density is not the only thing affected during compression; the intermolecular forces also come into play.

The closer the molecules are to each other, the stronger their attraction. This phenomenon aligns with the principles of the kinetic molecular theory, which, among other postulates, assumes that the force of attraction between gas molecules is negligible under normal conditions. However, upon compression, these forces become increasingly influential, sometimes leading to a deviation from the ideal gas behavior expected under standard conditions.

What we derive from this understanding is that gas compression at a constant temperature can elevate the significance of intermolecular attractions. This has practical implications, such as when converting a gas to a liquid (liquefaction) or understanding the behavior of gases in various industrial processes.
Kinetic Molecular Theory
The kinetic molecular theory of gases offers a framework to explain the behavior of gases and their physical properties, particularly focusing on the motion and energy of molecules. It makes several key assumptions: gases are made up of molecules in constant random motion; the volume of these molecules is negligible compared to the total volume of gas; these molecules exert no forces on each other except during brief collisions; and the average kinetic energy of the molecules is proportional to the gas temperature in kelvins.

When considering gas compression and changes in temperature, the kinetic molecular theory helps us understand the impact on molecular behavior. For example, at constant temperature during compression, as volume decreases, the frequency of collisions between gas molecules increases. Despite the molecules' speed remaining unchanged (because temperature is constant), the increased collision frequency contributes to a rise in pressure, another fundamental physical property of gases.

Conversely, if you increase the temperature while maintaining volume, the gas molecules gain kinetic energy and move faster. This increased speed diminishes the duration and effectiveness of intermolecular attractions, as molecules are less likely to be affected by neighboring molecules. Hence, elevated temperature at a constant volume results in an overall decrease in the effect of intermolecular attraction.
Physical Properties of Gases
Looking closely at gases, their physical properties are often discussed in terms of pressure, volume, temperature, and the number of molecules (moles). These properties are interconnected, a relationship that is elegantly described by the ideal gas law. But real gases deviate from ideal behavior, largely due to intermolecular attractions, especially under high pressure (compression) or low temperature conditions.

Physical properties of gases, such as their ability to flow, diffuse, and occupy the entire space available to them, are inherently linked to the kinetic molecular theory. For example, gas diffusion, which is the spreading of gas molecules until they are evenly distributed, can be slower when intermolecular attractions become significant under conditions of compression.

The physical properties tell us how gases will behave in different scenarios. While an ideal gas would not be affected by changes in intermolecular attraction, real gases respond to these changes. So, by understanding how compression and temperature affect intermolecular attraction, we can predict and explain the behaviors of real gases in various natural and industrial contexts. The effects are seen in phenomena like gas liquefaction or the operation of heat engines, which rely on manipulating the physical properties of gases to achieve the desired outcomes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Are you more likely to see the density of a gas reported in \(\mathrm{g} / \mathrm{mL}, \mathrm{g} / \mathrm{L},\) or \(\mathrm{kg} / \mathrm{cm}^{3} ?(\mathbf{b})\) Which units are appropriate for expressing atmospheric pressures, \(\mathrm{N}, \mathrm{Pa},\) atm, kg/m \(^{2} ?\) (c) Which is most likely to be a gas at room temperature and ordinary atmospheric pressure, \(\mathrm{F}_{2}, \mathrm{Br}_{2}, \mathrm{K}_{2} \mathrm{O} .\)

Natural gas is very abundant in many Middle Eastern oil fields. However, the costs of shipping the gas to markets in other parts of the world are high because it is necessary to liquefy the gas, which are high because it is necessary to point at atmospheric pressure of \(-164^{\circ} \mathrm{C} .\) One possible strategy is to oxidize the methane to methanol, CH \(_{3} \mathrm{OH}\) , which has a boiling point of \(65^{\circ} \mathrm{C}\) and can therefore be shipped more readily. Suppose that \(10.7 \times 10^{9} \mathrm{ft}^{3}\) of methane at atmospheric pressure and \(25^{\circ} \mathrm{C}\) is oxidized to methanol. (a) What volume of methanol is formed if the density of \(\mathrm{CH}_{3} \mathrm{OH}\) is 0.791 \(\mathrm{g} / \mathrm{mL} ?\) (b) Write balanced chemical equations for the oxidations of methane and methanol to \(\mathrm{CO}_{2}(g)\) and \(\mathrm{H}_{2} \mathrm{O}(l) .\) Calculate the total enthalpy change for complete combustion of the \(10.7 \times 10^{9} \mathrm{ft}^{3}\) of methane just described and for complete combustion of the equivalent amount of methanol, as calculated in part (a). (c) Methane, when liquefied, has a density of 0.466 \(\mathrm{g} / \mathrm{mL}\) ; the density of methanol at \(25^{\circ} \mathrm{C}\) is 0.791 \(\mathrm{g} / \mathrm{mL} .\) Compare the enthalpy change upon combustion of a unit volume of liquid methane and liquid methanol. From the standpoint of energy production, which substance has the higher enthalpy of combustion per unit volume?

An ideal gas at a pressure of 1.50 atm is contained in a bulb of unknown volume. A stopcock is used to connect this bulb with a previously evacuated bulb that has a volume of 0.800 \(\mathrm{L}\) as shown here. When the stopcock is opened, the gas expands into the empty bulb. If the temperature is held constant during this process and the final pressure is 695 torr, what is the volume of the bulb that was originally filled with gas?

A glass vessel fitted with a stopcock valve has a mass of 337.428 g when evacuated. When filled with Ar, it has a mass of 339.854 g. When evacuated and refilled with a mixture of Ne and Ar, under the same conditions of temperature and pressure, it has a mass of 339.076 g. What is the mole percent of Ne in the gas mixture?

You have an evacuated container of fixed volume and known mass and introduce a known mass of a gas sample. Measuring the pressure at constant temperature over time, you are surprised to see it slowly dropping. You measure the mass of the gas-filled container and find that the mass is what it should be-gas plus container-and the mass does not change over time, so you do not have a leak. Suggest an explanation for your observations.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free