Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The lactic acid molecule, \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}\), gives sour milk its unpleasant, sour taste. (a) Draw the Lewis structure for the molecule, assuming that carbon always forms four bonds in its stable compounds. (b) How many \(\pi\) and how many \(\boldsymbol{\sigma}\) bonds are in the molecule? (c) Which CO bond is shortest in the molecule? (d) What is the hybridization of atomic orbitals around the carbon atom associated with that short bond? (e) What are the approximate bond angles around each carbon atom in the molecule?

Short Answer

Expert verified
The Lewis structure for lactic acid is: O=C-C-OH │ OH The molecule has 11 σ bonds and 2 π bonds. The shortest CO bond is the C=O double bond. The carbon atom associated with this bond has sp^2 hybridization. The approximate bond angles around this sp^2 hybridized carbon atom are 120°, and around the sp^3 hybridized carbon atom are 109.5°.

Step by step solution

01

a) Drawing the Lewis structure

The Lewis structure is a diagram that shows the distribution of electrons in a molecule. First, find the number of valence electrons: - Carbon (C): 4 valence electrons - Hydrogen (H): 1 valence electron - Oxygen (O): 6 valence electrons There are two Carbon atoms, six Hydrogen atoms, and three Oxygen atoms in the lactic acid molecule. Total valence electrons = 2(4) + 6(1) + 3(6) = 8 + 6 + 18 = 32 Now, draw the Lewis structure by connecting the atoms with shared pairs of electrons (covalent bonds) and distributing the remaining electrons around each atom to fulfill the octet rule (2 electrons for Hydrogen and 8 electrons for Carbon and Oxygen). The Lewis structure for lactic acid is: O=C-C-OH │ OH
02

b) Determining the number of π and σ bonds

In a molecule, there are two types of covalent bonds: σ (sigma) bonds and π (pi) bonds. σ bonds are formed by the overlap of atomic orbitals along the axis between two atoms, whereas π bonds are formed from parallel P orbitals. We can determine the number of π and σ bonds from the Lewis structure. - One C=C double bond (containing 1 σ bond and 1 π bond) - Two C-C single bonds (containing 2 σ bonds) - Two C-O single bonds (containing 2 σ bonds) - One C=O double bond (containing 1 σ bond and 1 π bond) - Three C-H single bonds (containing 3 σ bonds) - Two O-H single bonds (containing 2 σ bonds) In total, there are 1+2+2+1+3+2 = 11 σ bonds and 1+1 = 2 π bonds in the lactic acid molecule.
03

c) Identifying the shortest CO bond

Double bonds are shorter than single bonds due to greater electron density between the bonded atoms. Therefore, the shortest CO bond in the lactic acid molecule is the C=O double bond.
04

d) Determining the hybridization of atomic orbitals

To determine the hybridization of the carbon atom associated with the shortest CO bond (C=O), count the number of electron domains around the carbon atom: 1 double bond, 1 single bond, and no lone pairs. The carbon atom has 3 electron domains, meaning it undergoes sp^2 hybridization.
05

e) Approximating bond angles around each carbon atom

The approximate bond angles around each carbon atom depend on the hybridization: - sp^2 hybridized carbon (associated with the C=O bond): The geometry around an sp^2 hybridized carbon is trigonal planar, with bond angles of approximately 120°. - sp^3 hybridized carbon (associated with the C-C bond): The geometry around an sp^3 hybridized carbon is tetrahedral, with bond angles of approximately 109.5°. In conclusion, the approximate bond angles around the sp^2 hybridized carbon atom are 120°, and around the sp^3 hybridized carbon atom are 109.5° in the lactic acid molecule.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hybridization
Hybridization is a concept used to explain the bonding within molecules through the mixing of atomic orbitals to create new hybrid orbitals. These hybrid orbitals help predict the geometry of molecules and how atoms in a molecule bond. In the case of lactic acid, which contains carbon atoms forming different bonds, understanding the hybridization helps explain the molecule's shape and bond angles.

Each carbon atom in the lactic acid molecule can undergo different types of hybridization depending on its bonding environment:
  • sp2 Hybridization: This occurs in carbon atoms that have one double bond, like the carbon in the C=O bond. It involves mixing one s orbital with two p orbitals to form three equivalent sp2 hybrid orbitals, which are arranged in a trigonal planar shape with bond angles of approximately 120°.
  • sp3 Hybridization: This is seen in carbon atoms bonded with four single bonds, such as the carbon atoms forming C-H and C-C bonds in lactic acid. An s orbital mixes with three p orbitals to form four sp3 hybrid orbitals which arrange themselves in a tetrahedral shape, resulting in bond angles of roughly 109.5°.
Sigma and Pi Bonds
In the world of chemistry, sigma and pi bonds are the building blocks of molecular structure. They describe how atoms share electrons to form molecules. In the lactic acid molecule, which you might recognize by its sour contribution to milk, these bonds define its chemical framework.

- **Sigma ( \( \sigma \) ) Bonds** are the primary form of covalent bonding, formed by the direct overlap of atomic orbitals along the axis between two bonded nuclei. In lactic acid, these bonds make up the single bonds found between carbon and hydrogen (C-H), carbon and carbon (C-C), and carbon and oxygen (C-O). Since these bonds overlap directly between the nuclei, sigma bonds are generally stronger than pi bonds. In total, lactic acid contains 11 sigma bonds.
  • 3 C-H bonds
  • 2 C-C bonds
  • 2 O-H bonds
- **Pi ( \( \pi \) ) Bonds**, on the other hand, arise from the sideways overlap of p orbitals. These are present when atoms are connected by double bonds or triple bonds. In lactic acid, the pi bonds are found in the C=O double bond, adding additional electron density parallel to the sigma bond. Lactic acid has 2 pi bonds.

Understanding the distribution and nature of these bonds helps chemists predict molecule stability, reactivity, and physical properties.
Valence Electrons
Valence electrons are the electrons available in the outermost shell of an atom and are crucial for understanding how atoms bond and form molecules. They determine an atom's chemical properties and its ability to bond with other atoms.

In forming lactic acid, knowing the count of valence electrons from each participating atom allows you to build the molecule's Lewis structure. For example:
  • Carbon, with an atomic number of 6, has 4 valence electrons in its outer shell.
  • Hydrogen, which has an atomic number of 1, contributes 1 valence electron.
  • Oxygen, with its 8 electrons, provides 6 valence electrons.
To correctly draw a molecule's Lewis structure, sum all valence electrons from each atom in the molecule. In lactic acid (\(\text{CH}_3\text{CH}(\text{OH})\text{COOH}\)) , we find a total of 32 valence electrons.
  • 2 carbons: 2 × 4 = 8 electrons
  • 6 hydrogens: 6 × 1 = 6 electrons
  • 3 oxygens: 3 × 6 = 18 electrons
The distribution of these electrons informs us on how the atoms will bond together, forming a stable molecule with all atoms achieving a complete outer shell, according to the octet rule for main group elements (Hydrogen being the exception with a duet).
Bond Angles
Bond angles offer insight into the spatial orientation of bonded atoms within a molecule, revealing the overall shape and structural characteristics of the molecule. They are fundamentally determined by the arrangement of hybrid orbitals and the repulsion between electron pairs.

In lactic acid, two primary regions dictate the bond angles due to different hybridizations of carbon atoms:
  • Trigonally Planar around sp2 Hybridized Carbon: For the carbon atom involved in the C=O double bond, the bond angle is about 120°. This setup results from the plane formed by the three sp2 hybrid orbitals, which aim to minimize repulsion between the electron pairs.
  • Tetrahedral around sp3 Hybridized Carbon: For carbon atoms connected to the single bonds (like C-C and C-H bonds in lactic acid), the bond angles are approximately 109.5° due to the four sp3 hybridized orbitals, which form a tetrahedral shape maximizing the distance between each bond pair.
Understanding the bond angles helps explain both the two-dimensional (on paper) and three-dimensional (in space) molecular geometries, illuminating how we perceive molecular motion and reaction pathways.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Dichloroethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2} \mathrm{Cl}_{2}\right)\) has three forms (isomers), each of which is a different substance. (a) Draw Lewis structures of the three isomers, all of which have a carbon-carbon double bond. (b) Which of these isomers has a zero dipole moment? (c) How many isomeric forms can chloroethylene, \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}\), have? Would they be expected to have dipole moments?

(a) The \(\mathrm{PH}_{3}\) molecule is polar. Does this offer experimental proof that the molecule cannot be planar? Explain. (b) It turns out that ozone, \(\mathrm{O}_{3}\), has a small dipole moment. How is this possible, given that all the atoms are the same?

(a) Which geometry and central atom hybridization would you expect in the series \(\mathrm{BH}_{4}^{-}, \mathrm{CH}_{4}, \mathrm{NH}_{4}^{+}\)? (b) What would you expect for the magnitude and direction of the bond dipoles in this series? (c) Write the formulas for the analogous species of the elements of period 3 ; would you expect them to have the same hybridization at the central atom?

Suppose that silicon could form molecules that are precisely the analogs of ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right)\), ethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{4}\right)\), and acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\). How would you describe the bonding about \(\mathrm{Si}\) in terms of hydrid orbitals? Silicon does not readily form some of the analogous compounds containing \(\pi\) bonds. Why might this be the case?

There are two compounds of the formula \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\) : The compound on the right, cisplatin, is used in cancer therapy. The compound on the left, transplatin, is ineffective for cancer therapy. Both compounds have a square-planar geometry. (a) Which compound has a nonzero dipole moment? (b) The reason cisplatin is a good anticancer drug is that it binds tightly to DNA. Cancer cells are rapidly dividing, producing a lot of DNA. Consequently, cisplatin kills cancer cells at a faster rate than normal cells. However, since normal cells also are making DNA, cisplatin also attacks healthy cells, which leads to unpleasant side effects. The way both molecules bind to DNA involves the \(\mathrm{Cl}^{-}\)ions leaving the Pt ion, to be replaced by two nitrogens in DNA. Draw a picture in which a long vertical line represents a piece of DNA. Draw the \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\) fragments of cisplatin and transplatin with the proper shape. Also draw them attaching to your DNA line. Can you explain from your drawing why the shape of the cisplatin causes it to bind to DNA more effectively than transplatin?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free