Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

From their Lewis structures, determine the number of \(\sigma\) and \(\pi\) bonds in each of the following molecules or ions: (a) \(\mathrm{CO}_{2}\); (b) cyanogen, \((\mathrm{CN})_{2} ;\) (c) formaldehyde, \(\mathrm{H}_{2} \mathrm{CO}\); (d) formic acid, \(\mathrm{HCOOH}\), which has one \(\mathrm{H}\) and two \(\mathrm{O}\) atoms attached to \(\mathrm{C}\).

Short Answer

Expert verified
The number of \(\sigma\) and \(\pi\) bonds in the given molecules or ions are as follows: (a) \(\mathrm{CO}_{2}\): 2 \(\sigma\) bonds and 2 \(\pi\) bonds (b) Cyanogen, \((\mathrm{CN})_{2}\): 3 \(\sigma\) bonds and 4 \(\pi\) bonds (c) Formaldehyde, \(\mathrm{H}_{2} \mathrm{CO}\): 3 \(\sigma\) bonds and 2 \(\pi\) bonds (d) Formic acid, \(\mathrm{HCOOH}\): 4 \(\sigma\) bonds and 2 \(\pi\) bonds

Step by step solution

01

Draw the Lewis structures of the molecules or ions.

: (a) \(\mathrm{CO}_{2}\): The central atom is C and has two O atoms bonded to it. The Lewis structure will represent a double bond between the central C and each O atom. (b) Cyanogen, \((\mathrm{CN})_{2}\): The cyanogen molecule consists of a carbon atom singly bonded to a nitrogen, which is then triple bonded to another nitrogen, that is singly bonded to another carbon atom. (c) Formaldehyde, \(\mathrm{H}_{2} \mathrm{CO}\): The central atom is C and has an O atom and two H atoms bonded to it. The Lewis structure will represent a double bond between the central C and O atom, and a single bond between the central C and each H atom. (d) Formic acid, \(\mathrm{HCOOH}\): The central atom is C, which has an H, O, and an OH group attached to it. The Lewis structure will represent a double bond between the central C and O atom, a single bond between the central C and the hydroxyl O, and a single bond between C and H.
02

Count the σ and π bonds in each molecule/ion.

: (a) \(\mathrm{CO}_{2}\): In a double bond, there is one \(\sigma\) bond and one \(\pi\) bond. Therefore, \(\mathrm{CO}_{2}\) has 2 (\(\sigma\) bonds) + 2 (\(\pi\) bonds) = 4 bonds. (b) Cyanogen, \((\mathrm{CN})_{2}\): In a single bond, there is one \(\sigma\) bond, and in a triple bond, there is one \(\sigma\) bond and two \(\pi\) bonds. The cyanogen molecule has 3 (\(\sigma\) bonds) + 4 (\(\pi\) bonds) = 7 total bonds. (c) Formaldehyde, \(\mathrm{H}_{2} \mathrm{CO}\): The Lewis structure of formaldehyde has 3 (\(\sigma\) bonds) + 2 (\(\pi\) bonds) = 5 total bonds. (d) Formic acid, \(\mathrm{HCOOH}\): The Lewis structure of formic acid has 4 (\(\sigma\) bonds) + 2 (\(\pi\) bonds) = 6 total bonds. In summary: (a) \(\mathrm{CO}_{2}\): 2 \(\sigma\) bonds and 2 \(\pi\) bonds (b) Cyanogen, \((\mathrm{CN})_{2}\): 3 \(\sigma\) bonds and 4 \(\pi\) bonds (c) Formaldehyde, \(\mathrm{H}_{2} \mathrm{CO}\): 3 \(\sigma\) bonds and 2 \(\pi\) bonds (d) Formic acid, \(\mathrm{HCOOH}\): 4 \(\sigma\) bonds and 2 \(\pi\) bonds

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sigma Bonds
Sigma bonds, often represented as \( \sigma \) bonds, are a fundamental component to understanding chemical bonding. These bonds form the backbone of molecular structures. A sigma bond is the strongest type of covalent bond and occurs when two atomic orbitals overlap head-on. This overlap can occur between:
  • Two s-orbitals
  • One s-orbital and one p-orbital
  • Two p-orbitals, provided they align end-to-end
Sigma bonds are characterized by this head-on overlap, which allows for free rotation around the bond axis. This is a key distinction from other types of bonds. Every single bond in a molecule is, at its core, a sigma bond. For instance, in molecules like formic acid \( \text{HCOOH} \) or formaldehyde \( \text{H}_2\text{CO} \), each C-H and C-O single bond is a sigma bond. Each initial double or triple bond contains only one sigma bond, the rest are pi bonds.
Pi Bonds
Pi bonds \( \pi \) are another critical type of covalent bond that adds depth to molecular bonding. Unlike sigma bonds, pi bonds result from the side-by-side overlap of p-orbitals. Because this type of overlap occurs above and below the bond axis, pi bonds restrict the rotation around the bond, which can influence the molecular shape and properties.To understand pi bonds, it's essential to see them in the context of double and triple bonds:
  • Double bonds consist of one sigma bond and one pi bond.
  • Triple bonds include one sigma bond and two pi bonds.
These bonds add additional layers of electron sharing and influence the molecule's reactivity and stability. For example, in carbon dioxide (\( \text{CO}_2 \)), the double bonds between the carbon and oxygen include both a sigma and a pi bond.
Molecular Geometry
Molecular geometry is the three-dimensional arrangement of atoms within a molecule. It plays a crucial role in determining the physical and chemical properties of a substance. The geometry is largely determined by the number of electron pairs around the central atom, both bonding and non-bonding.Common geometries include:
  • Linear
  • Trigonal planar
  • Tetrahedral
  • Bent
  • Trigonal bipyramidal
  • Octahedral
Using the VSEPR (Valence Shell Electron Pair Repulsion) model, you can predict the geometry by considering the electron repulsions. For example, carbon dioxide \( \text{CO}_2 \) is linear due to two double bonds causing minimal electron pair repulsion. In contrast, formaldehyde \( \text{H}_2\text{CO} \) adopts a trigonal planar shape due to the presence of one double bond and two single bonds.
Covalent Bonding
Covalent bonding is essential in the formation of molecules by the sharing of electron pairs between atoms. This type of bonding arises when atoms, usually non-metals, have similar electronegativities, making it energetically favorable for them to share electrons equally.The shared electron pair constitutes the covalent bond, which can be either polar or non-polar depending on the atoms involved:
  • Polar covalent bonds occur between atoms with different electronegativities, leading to an unequal sharing of electrons.
  • Non-polar covalent bonds occur between atoms with similar electronegativities, leading to equal sharing of electrons.
Understanding covalent bonding is crucial for predicting molecular properties such as melting and boiling points, solubility, and reactivity. For example, in formic acid \( \text{HCOOH} \), the covalent bonds between carbon, hydrogen, and oxygen determine the molecule's acidity and solubility.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider a molecule with formula \(\mathrm{AX}_{3}\). Supposing the \(\mathrm{A}-\mathrm{X}\) bond is polar, how would you expect the dipole moment of the \(\mathrm{AX}_{3}\) molecule to change as the \(\mathrm{X}-\mathrm{A}-\mathrm{X}\) bond angle increases from \(100^{\circ}\) to \(120^{\circ}\) ?

The structure of borazine, \(\mathrm{B}_{3} \mathrm{~N}_{3} \mathrm{H}_{6}\), is a six-membered ring of alternating \(\mathrm{B}\) and \(\mathrm{N}\) atoms. There is one \(\mathrm{H}\) atom bonded to each \(\mathrm{B}\) and to each \(\mathrm{N}\) atom. The molecule is planar. (a) Write a Lewis structure for borazine in which the formal charges on every atom is zero. (b) Write a Lewis structure for borazine in which the octet rule is satisfied for every atom. (c) What are the formal charges on the atoms in the Lewis structure from part (b)? Given the electronegativities of \(B\) and \(\mathrm{N}\), do the formal charges seem favorable or unfavorable? (d) Do either of the Lewis structures in parts (a) and (b) have multiple resonance structures? (e) What are the hybridizations at the \(\mathrm{B}\) and \(\mathrm{N}\) atoms in the Lewis structures from parts (a) and (b)? Would you expect the molecule to be planar for both Lewis structures? (f) The six B-N bonds in the borazine molecule are all identical in length at \(1.44 \AA\). Typical values for the bond lengths of \(\mathrm{B}-\mathrm{N}\) single and double bonds are \(1.51 \AA \mathrm{A}\) and \(1.31 \mathrm{~A}\), respectively. Does the value of the \(\mathrm{B}-\mathrm{N}\) bond length seem to favor one Lewis structure over the other? (g) How many electrons are in the \(\pi\) system of borazine?

(a) If you combine two atomic orbitals on two different atoms to make a new orbital, is this a hybrid orbital or a molecular orbital? (b) If you combine two atomic orbitals on one atom to make a new orbital, is this a hybrid orbital or a molecular orbital? (c) Does the Pauli exclusion principle (Section 6.7) apply to MOs? Explain.

\mathrm{An} \mathrm{} \mathrm{AB}_{2}\( molecule is described as linear, and the \)\mathrm{A}-\mathrm{B}\( bond length is known. (a) Does this information completely describe the geometry of the molecule? (b) Can you tell how many nonbonding pairs of electrons are around the \)A$ atom from this information?

(a) Starting with the orbital diagram of a boron atom, describe the steps needed to construct hybrid orbitals appropriate to describe the bonding in \(\mathrm{BF}_{3}\). (b) What is the name given to the hybrid orbitals constructed in (a)? (c) Sketch the large lobes of the hybrid orbitals constructed in part (a). (d) Are any valence atomic orbitals of B left unhybridized? If so, how are they oriented relative to the hybrid orbitals?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free