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(a) What is the physical basis for the VSEPR model? (b) When applying the VSEPR model, we count a double or triple bond as a single electron domain. Why is this justified?

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(a) The physical basis of the VSEPR (Valence Shell Electron Pair Repulsion) Model is the electrostatic repulsion between negatively charged electron pairs in the valence shell of the central atom. By minimizing these repulsions, the electron pairs, and atoms arrange themselves to form a stable molecular geometry. (b) Double or triple bonds are counted as single electron domains in the VSEPR model because their electron pairs from pi bonds are more delocalized and have less repulsion compared to sigma bonds or lone pairs. This simplification allows for more accurate prediction of molecular geometries by focusing on the most significant repulsions.

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(a) Physical Basis of VSEPR Model

Valence Shell Electron Pair Repulsion (VSEPR) Model is based on the idea that electron groups (lone pairs, single, double, and triple bonds) surrounding a central atom in a molecule repel one another. This repulsion causes these electron groups to arrange themselves as far apart as possible to minimize the repulsion energy. The physical basis of VSEPR is electrostatic repulsion between negatively charged electron pairs in the valence shell of the central atom. By minimizing these repulsions, the arrangement of electron pairs and atoms around the central atom can result in a stable molecular geometry.
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(b) Justification for Counting Double or Triple Bonds as Single Electron Domains

The main reason for treating double or triple bonds as single electron domains in the VSEPR model is the concept of electron domain localization. In a double bond, there are two electron pairs shared between two atoms – one of them is a sigma bond and the other is a pi bond. Similarly, in a triple bond, there are three electron pairs shared - one sigma bond and two pi bonds. Although double and triple bonds consist of multiple bonding pairs, these electron pairs belonging to pi bonds are more delocalized and spread-out over the bonding region, compared to sigma bonds. As a result, their repulsion with other electron groups is relatively less compared to sigma bonds or lone pairs. Considering a double or triple bond as a single electron domain simplifies the VSEPR model and allows for more accurate prediction of molecular geometries by focusing on the most significant repulsions: those between sigma bonds and lone pairs. This approach has been found to be quite effective in predicting the molecular structures in most cases, making the counting of double or triple bonds as single electron domains a justified simplification in the VSEPR model.

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Most popular questions from this chapter

(a) The nitric oxide molecule, NO, readily loses one electron to form the NO+ion. Which of the following is the best explanation of why this happens: (i) Oxygen is more electronegative than nitrogen, (ii) The highest energy electron in NO lies in a π2p molecular orbital, or (iii) The π2pMO in NO is completely filled. (b) Predict the order of the NO bond strengths in NONO+, and NO, and deseribe the magnetic properties of each. (c) With what neutral homonuclear diatomic molecules are the NO+and NOions isoelectronic (same number of electrons)?

Propylene, C3H6, is a gas that is used to form the important polymer called polypropylene. Its Lewis structure is (a) What is the total number of valence electrons in the propylene molecule? (b) How many valence electrons are used to make σ bonds in the molecule? (c) How many valence electrons are used to make π bonds in the molecule? (d) How many valence electrons remain in nonbonding pairs in the molecule? (e) What is the hybridization at each carbon atom in the molecule?

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The phosphorus trihalides (PX3) show the following variation in the bond angle XPX:PF3,,96.3;PCl3,100.3; PBr3,101.0;PI3,102.0. The trend is generally attributed to the change in the electronegativity of the halogen. (a) Assuming that all electron domains are the same size, what value of the XPX angle is predicted by the VSEPR model? (b) What is the general trend in the XPX angle as the halide electronegativity increases? (c) Using the VSEPR model, explain the observed trend in XPX angle as the electronegativity of X changes. (d) Based on your answer to part (c), predict the structure of PBrCl4.

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