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Draw sketches illustrating the overlap between the following orbitals on two atoms: (a) the \(2 s\) orbital on each atom, (b) the \(2 p_{z}\) orbital on each atom (assume both atoms are on the \(z\)-axis), (c) the \(2 s\) orbital on one atom and the \(2 p_{z}\) orbital on the other atom.

Short Answer

Expert verified
For case (a), we illustrate the overlap of \(2s\) orbitals on both atoms by drawing two symmetrical spheres and showing the uniform overlap between them as the atoms approach each other. In case (b), we draw two \(2 p_{z}\) orbitals on both atoms aligned with the \(z\)-axis and illustrate the head-on overlap along the axis. Lastly, for case (c), we draw a \(2 s\) orbital on one atom and a \(2 p_{z}\) orbital on the other atom aligned with the \(z\)-axis, and show the overlap between one lobe of the \(2 p_{z}\) orbital and the \(2 s\) orbital as the atoms come closer.

Step by step solution

01

Case (a): Overlap of \(2 s\) orbitals on each atom

For this case, we will draw two \(2s\) orbitals on each atom and show how they overlap when the atoms approach each other. Since the \(2 s\) orbitals are symmetrical, they will overlap uniformly when the atoms come closer. 1. Draw two spheres representing the \(2 s\) orbitals on both atoms. 2. When the atoms come close enough for their orbitals to overlap, the overlapping region will appear as a larger shared region between the two orbitals. 3. Label the \(2s\) orbitals on both atoms.
02

Case (b): Overlap of \(2 p_{z}\) orbitals on each atom

For this case, we will draw two \(2 p_{z}\) orbitals on both atoms and show them overlapping when the atoms approach each other. Since the \(2 p_{z}\) orbitals are symmetrical along the z-axis, the head-on overlapping along the axis will happen. 1. Draw a cartesian coordinate system with the \(z\)-axis. 2. Draw two \(2 p_{z}\) orbitals on each atom aligned with the \(z\)-axis. 3. When the atoms come close enough for their orbitals to overlap, the overlapping region will appear as the shared region between the lobes on their \(2 p_{z}\) orbitals which are facing each other and oriented along the \(z\)-axis. 4. Label the \(2 p_{z}\) orbitals on both atoms.
03

Case (c): Overlap of \(2 s\) orbital on one atom and \(2 p_{z}\) orbital on another atom

For this case, we will draw the \(2 s\) orbital on one atom and \(2 p_{z}\) orbital on the other atom, both aligned with the \(z\)-axis, and show them overlapping when the atoms approach each other. 1. Draw a cartesian coordinate system with the \(z\)-axis. 2. Draw a \(2 s\) orbital on one atom and a \(2 p_{z}\) orbital on the other atom aligned with the \(z\)-axis. 3. When the atoms come close enough for their orbitals to overlap, the overlapping region will appear as the shared area between one lobe of the \(2 p_{z}\) orbital and the \(2 s\) orbital. 4. Label the \(2 s\) orbital on one atom and the \(2 p_{z}\) orbital on the other atom.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the 2s Orbital
The concept of atomic orbitals is fundamental to chemistry, and the 2s orbital is a key player in this arena. Imagine a spacious balloon with a smooth surface, gently inflated with the probability of finding an electron. This is what the 2s orbital roughly resembles. It is one of the quantum states of the electron where it can exist with a higher energy level than the 1s orbital, indicative of its principal quantum number, 2.

Unlike the p or d orbitals, the 2s orbital is spherically symmetrical and lacks directional properties. This means it can overlap with other orbitals in any direction. When two 2s orbitals from different atoms approach each other, they merge to form a single, larger region of electron probability, promoting the potential for chemical bonds to form.
  • The 2s orbital is larger than the 1s orbital due to its higher energy level.
  • It is a single, spherical shape without any nodal planes, unlike p or d orbitals.
  • When overlapping, 2s orbitals create a uniform electron density between the two nuclei.
Understanding the interaction of 2s orbitals is pivotal when delving into the nuances of chemical bonding, as it often serves as the initial handshake between atoms forming a molecule.
Deciphering the 2pz Orbital
The 2pz orbital holds its own unique charm in the atomic world. Visualize a dumbbell, with elongated lobes extending in opposite directions along an axis—the z-axis, in this case. This is a simplified view of the 2pz orbital. The 'p' stands for 'principal', indicating a specific orientation in three-dimensional space, while the 'z' signifies its alignment along the z-axis.

This dumbbell shape leads to directed bonding when two 2pz orbitals overlap end-to-end, a type often involved in forming \(\textbackslash\textbackslashpi\) bonds. This directional bonding contrasts the 2s orbital's indiscrimination, leading to different molecular shapes and properties. Here, electron density is concentrated in the space directly between the two nuclei along the z-axis when overlapping.
  • The 2pz orbital is one of three p orbitals, each oriented along a different Cartesian axis.
  • It is crucial in the formation of \(\pi\) bonds, which are essential for double and triple bonds in chemicals.
  • Its overlap forms a bond that is more focused and directional.
Understanding the behavior of 2pz orbitals is essential for grasping concepts like hybridization, molecular geometry, and the nature of double or triple bonds.
The Fundamentals of Molecular Orbital Theory
Molecular Orbital (MO) Theory is like the grand architect of chemical bonding. It propounds that atomic orbitals combine to form molecular orbitals when atoms bond together. These molecular orbitals are the residences of electrons in a molecule and are spread over multiple atoms, unlike the atomic orbitals specific to a single atom.

This theory allows chemists to predict the electronic structure of molecules, estimate bond order, magnetic properties, and the stability of the molecules. A key tenet of MO theory is that for a bond to form, atomic orbitals must overlap effectively. The strength of this overlap is a determining factor in the bond's strength.
  • MO theory provides an explanation for the formation and properties of molecules.
  • It introduces the concept of bonding and antibonding orbitals, which helps explain why not all interactions lead to stable bonds.
  • The theory not only accounts for the shape of the molecules but also delves into their electronic behavior during chemical reactions.
The sketches from the textbook illustrate how the MO theory translates in practice, showing the possible overlaps between atomic orbitals—whether it be the spherical 2s orbitals or the directional 2pz orbitals.
Chemical Bonding: The Force that Shapes Molecules
Chemical bonding is the force that crafts the myriad structures and substances in our universe. At its essence, it's the glue that holds atoms together in molecules. The bonds form when atoms share or transfer electrons to achieve greater stability, often likened to having a complete outer shell similar to the noble gases.

There are several types of chemical bonds, including ionic, covalent, and metallic bonds, each with its distinct characteristics and electron sharing or transferring scenarios. Covalent bonds, where atoms share electrons, directly involve the overlap of atomic orbitals, which is why understanding orbitals is so significant.
  • Ionic bonds result from the transfer of electrons from one atom to another, resulting in a net electrical charge.
  • Covalent bonds involve the sharing of electrons, and their strength depends on the extent of orbital overlap.
  • Metallic bonds involve a 'sea' of electrons that are free to move around, giving rise to properties like conductivity.
Whether it's a simple diatomic molecule or a complex polymer, every bond has its story rooted in the fundamental principles of chemical bonding, orbital overlap, and molecular orbital theory.

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Most popular questions from this chapter

The \(\mathrm{O}-\mathrm{H}\) bond lengths in the water molecule \(\left(\mathrm{H}_{2} \mathrm{O}\right)\) are \(0.96 \AA\), and the \(\mathrm{H}-\mathrm{O}-\mathrm{H}\) angle is \(104.5^{\circ}\). The dipole moment of the water molecule is \(1.85\) D. (a) In what directions do the bond dipoles of the \(\mathrm{O}-\mathrm{H}\) bonds point? In what direction does the dipole moment vector of the water molecule point? (b) Calculate the magnitude of the bond dipole of the \(\mathrm{O}-\mathrm{H}\) bonds. (Note: You will need to use vector addition to do this.) (c) Compare your answer from part (b) to the dipole moments of the hydrogen halides (Table 8.3). Is your answer in accord with the relative electronegativity of oxygen?

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