The energy-level diagram in Figure 9.36 shows that the sideways overlap of a
pair of porbitals produces two molecular orbitals, one bonding and one
antibonding. In ethylene there
is a pair of electrons in the bonding \(\pi\) orbital between the two carbons.
Absorption of a photon of the appropriate wavelength can result in promotion
of one of the bonding electrons from the \(\pi_{2 p}\) to the $\pi_{2
p}^{\star}$ molecular orbital. (a) Assuming this electronic transition
corresponds to the HOMO-LUMO transition, what is the HOMO in ethylene? (b)
Assuming this electronic transition corresponds to the HOMO-LUMO transition,
what is the LUMO in ethylene? (c) Is the C-Cbond in ethylene stronger or
weaker in the excited state than in the ground state? Why? (d) Is the \(C-C\)
bond in ethylene easier to twist in the ground state or in the excited state?