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(a) Does \(\mathrm{SCl}_{2}\) have a dipole moment? If so, in which direction does the net dipole point? (b) Does \(\mathrm{BeCl}_{2}\) have a dipole moment? If so, in which direction does the net dipole point?

Short Answer

Expert verified
(a) Yes, SCl2 has a dipole moment that points from the S atom to the midpoint between the two Cl atoms due to its bent molecular geometry and the significant difference in electronegativity between S and Cl atoms. (b) No, BeCl2 does not have a dipole moment because the linear molecular geometry causes the polarities of its individual bonds to cancel each other out, despite the electronegativity differences between Be and Cl atoms.

Step by step solution

01

Determine the molecular geometry of SCl2

First, let's determine the molecular geometry of SCl2. Sulfur has 6 valence electrons, and each chlorine atom contributes 7 valence electrons. Thus, the total number of valence electrons is 6 + (2 × 7) = 20. These 20 electrons form 2 single bonds between sulfur and the two chlorine atoms, and a pair of lone pair electrons on the sulfur. In this arrangement, we have a bent molecular geometry for SCl2.
02

Determine electronegativity differences for SCl2

Now, let's check the electronegativity difference between S and Cl. The electronegativity of S is 2.58, and that of Cl is 3.16. Thus, the difference in electronegativity between sulfur and chlorine is 3.16 - 2.58 = 0.58. This difference is significant and implies that SCl2 has a polar bond.
03

Determine the dipole moment direction of SCl2

Since we have a bent molecular geometry, the asymmetrical distribution of electron density leads to a net dipole moment. The net dipole points towards the more electronegative atom, which is chlorine. So, the direction of the net dipole in SCl2 is from S to the midpoint between the two Cl atoms. Now let's analyze BeCl2:
04

Determine the molecular geometry of BeCl2

First, let's determine the molecular geometry of BeCl2. Beryllium has 2 valence electrons, and each chlorine contributes 7 valence electrons. This makes a total of 2 + (2 × 7) = 16 valence electrons. Beryllium uses its 2 valence electrons to form single bonds with both chloride atoms. The molecular geometry for BeCl2 is linear.
05

Determine electronegativity differences for BeCl2

Now, let's check the electronegativity difference between Be and Cl. The electronegativity of Be is 1.57, and the value for Cl stays at 3.16. The difference in electronegativity between beryllium and chlorine is 3.16 - 1.57 = 1.59. This indicates that the Be-Cl bond is polar.
06

Determine the dipole moment direction of BeCl2

The molecular geometry of BeCl2 is linear, causing the individual bond dipoles to cancel each other out, resulting in no net dipole moment for BeCl2. In summary: (a) SCl2 has a dipole moment that points from the S atom to the midpoint between the two Cl atoms. (b) BeCl2 does not have a dipole moment, as the polarity of its individual bonds cancel each other out due to the linear molecular geometry.

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Most popular questions from this chapter

The structure of borazine, \(\mathrm{B}_{3} \mathrm{~N}_{3} \mathrm{H}_{6}\), is a six-membered ring of alternating \(\mathrm{B}\) and \(\mathrm{N}\) atoms. There is one \(\mathrm{H}\) atom bonded to each \(\mathrm{B}\) and to each \(\mathrm{N}\) atom. The molecule is planar. (a) Write a Lewis structure for borazine in which the formal charges on every atom is zero. (b) Write a Lewis structure for borazine in which the octet rule is satisfied for every atom. (c) What are the formal charges on the atoms in the Lewis structure from part (b)? Given the electronegativities of \(B\) and \(\mathrm{N}\), do the formal charges seem favorable or unfavorable? (d) Do either of the Lewis structures in parts (a) and (b) have multiple resonance structures? (e) What are the hybridizations at the \(\mathrm{B}\) and \(\mathrm{N}\) atoms in the Lewis structures from parts (a) and (b)? Would you expect the molecule to be planar for both Lewis structures? (f) The six B-N bonds in the borazine molecule are all identical in length at \(1.44 \AA\). Typical values for the bond lengths of \(\mathrm{B}-\mathrm{N}\) single and double bonds are \(1.51 \AA \mathrm{A}\) and \(1.31 \mathrm{~A}\), respectively. Does the value of the \(\mathrm{B}-\mathrm{N}\) bond length seem to favor one Lewis structure over the other? (g) How many electrons are in the \(\pi\) system of borazine?

(a) What is the physical basis for the VSEPR model? (b) When applying the VSEPR model, we count a double or triple bond as a single electron domain. Why is this justified?

Consider the bonding in an \(\mathrm{MgH}_{2}\) molecule. (a) Draw a Lewis structure for the molecule, and predict its molecular geometry. (b) What hybridization scheme is used in \(\mathrm{MgH}_{2}\) ? (c) Sketch one of the two-electron bonds between an \(\mathrm{Mg}\) hybrid orbital and an \(\mathrm{H} 1 \mathrm{~s}\) atomic orbital.

Consider a molecule with formula \(\mathrm{AX}_{3}\). Supposing the \(\mathrm{A}-\mathrm{X}\) bond is polar, how would you expect the dipole moment of the \(\mathrm{AX}_{3}\) molecule to change as the \(\mathrm{X}-\mathrm{A}-\mathrm{X}\) bond angle increases from \(100^{\circ}\) to \(120^{\circ}\) ?

The phosphorus trihalides \(\left(\mathrm{PX}_{3}\right)\) show the following variation in the bond angle \(\mathrm{X}-\mathrm{P}-\mathrm{X}: \mathrm{PF}_{3,}, 96.3^{\circ} ; \mathrm{PCl}_{3}, 100.3^{\circ}\); \(\mathrm{PBr}_{3}, 101.0^{\circ} ; \mathrm{PI}_{3}, 102.0^{\circ}\). The trend is generally attributed to the change in the electronegativity of the halogen. (a) Assuming that all electron domains are the same size, what value of the \(\mathrm{X}-\mathrm{P}-\mathrm{X}\) angle is predicted by the VSEPR model? (b) What is the general trend in the \(\mathrm{X}-\mathrm{P}-\mathrm{X}\) angle as the halide electronegativity increases? (c) Using the VSEPR model, explain the observed trend in \(\mathrm{X}-\mathrm{P}-\mathrm{X}\) angle as the electronegativity of \(\mathrm{X}\) changes. (d) Based on your answer to part (c), predict the structure of \(\mathrm{PBrCl}_{4}\).

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