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Suppose that silicon could form molecules that are precisely the analogs of ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right)\), ethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{4}\right)\), and acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\). How would you describe the bonding about \(\mathrm{Si}\) in terms of hydrid orbitals? Silicon does not readily form some of the analogous compounds containing \(\pi\) bonds. Why might this be the case?

Short Answer

Expert verified
The silicon analogues of ethane, ethylene, and acetylene are Si2H6, Si2H4, and Si2H2, respectively. Si2H6 has an sp3 hybridized silicon with a tetrahedral geometry. In Si2H4, silicon is theoretically sp2 hybridized with a trigonal planar geometry, and in Si2H2, silicon is sp hybridized with a linear geometry. However, silicon's larger size and availability of empty d orbitals make it difficult for π bonds to form robustly. Thus, silicon analogues of ethylene and acetylene are less stable and less likely to form compared to their carbon counterparts.

Step by step solution

01

Identifying the Silicon Analogues

Let's first identify the silicon analogues of ethane, ethylene, and acetylene: Ethane (C2H6) - Silicon analogue would be Si2H6 Ethylene (C2H4) - Silicon analogue would be Si2H4 Acetylene (C2H2) - Silicon analogue would be Si2H2 Now, we will analyze the bonding about silicon in each of these analogues, considering the hybrid orbitals.
02

Analyzing Si2H6 (Analog of Ethane)

In Si2H6, each silicon atom shares a single bond with another silicon atom and forms single bonds with three hydrogen atoms. The silicon in Si2H6 is sp3 hybridized, and its geometry is tetrahedral.
03

Analyzing Si2H4 (Analog of Ethylene)

In Si2H4, similar to ethylene, each silicon atom would theoretically be double bonded to another silicon atom and would form single bonds with two hydrogen atoms. The silicon atoms should have sp2 hybridization, and the geometry would be trigonal planar.
04

Analyzing Si2H2 (Analog of Acetylene)

In Si2H2, each silicon atom would be triple bonded to another silicon atom and forms a single bond with one hydrogen atom. For this analog, the silicon atom should have sp hybridization, and the geometry would be linear.
05

Explaining the Rarity of π bonds in Silicon Analogues

Silicon atoms are larger than carbon atoms and have empty d orbitals, which can also participate in bonding. Due to the larger size, the overlap between the p orbitals of silicon atoms is smaller and weaker, making it difficult for π bonds to form. This is why silicon analogues of ethylene and acetylene are less stable than their carbon counterparts and don't readily form. However, silicon can form compounds with single bonds and use its empty d orbitals for bonding with other atoms or expanding its coordination number beyond 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hybrid Orbitals
In the fascinating world of chemistry, hybrid orbitals play a crucial role in determining the shape and bonding characteristics of molecules. Hybrid orbitals are formed when atomic orbitals within an atom mix to produce new orbitals. This hybridization process occurs because electrons are looking to adopt the most stable arrangement possible. For instance, when silicon forms molecules like Si2H6, it undergoes sp3 hybridization. This means that one s orbital and three p orbitals combine to form four equivalent sp3 hybrid orbitals, leading to a tetrahedral geometric structure much like a pyramid with a triangle as its base.

These new orbitals are identical and have a 109.5-degree angle between them, ensuring that the electrons they house are as far apart as possible, minimizing repulsion. In sp2 and sp hybridizations, which are proposed for silicon analogues of ethylene and acetylene respectively, the conditions change. An sp2 hybridization would combine one s and two p orbitals yielding a flat, trigonal planar shape, while sp hybridization would merge one s and one p orbital forming a straight line or linear shape.
σ and π Bonds
The world of chemical bonds is broadly categorized into two types: sigma (σ) and pi (π) bonds. Sigma bonds are the first bonds formed between two atoms and are marked by a head-on overlap of orbitals. They can be formed using any kind of hybrid orbitals or even pure s or p orbitals. For example, the silicon atoms in Si2H6 are linked by a σ bond, which is the result of the head-on overlapping of sp3 hybrid orbitals.

On the other hand, pi bonds, which are supplementary bonds formed after the σ bond, involve the side-to-side overlap of p orbitals. These are less common in silicon compounds because of the larger size and less effective overlap of silicon's p orbitals compared to carbon's. The significance of this lies in the bond strength and the molecule's ability to engage in reactions. While σ bonds are stronger and form the framework of molecules, π bonds are weaker and often participate in reactions enabling the formation of diverse organic compounds.
Chemical Bonding in Silicon Compounds
Silicon, which lies just below carbon in the periodic table, shows many similarities with carbon, including its ability to form four bonds. The chemical bonding in silicon compounds, however, has its own unique twist. Since silicon is larger, the electrons are farther from the nucleus and have higher energy compared to those in carbon. This means that silicon is less electronegative and has a difficult time forming strong pi (π) bonds because p orbitals overlap less effectively due to the increased distance between nuclei.

Moreover, silicon's vacant d orbitals come into play, allowing it to expand its octet and bond with more than four atoms, contrasting the typical behavior of carbon. This behavior is capitalized upon in silicon-based materials, such as silicones, where silicon atoms bond with oxygen in chains or networks, exploiting single σ bonds to create materials with remarkable properties such as heat resistance and flexibility.
Silicon-Carbon Analogy
The comparison between silicon and carbon compounds, known as the silicon-carbon analogy, is a compelling topic in chemistry because it reveals the periodic trends and element behaviors. Both silicon and carbon belong to group 14, which allows them to form four covalent bonds. However, while carbon is proficient at forming stable double and triple bonds due to effective p-orbital overlap, silicon struggles to do so due to its larger atomic size and less effective orbital overlap.

Students often learn about the versatility of carbon in organic chemistry and its multitude of stable structures, such as chains, rings, and multiple bond types. Silicon, despite its chemical kinship to carbon, tends to form fewer multiply-bonded structures, imitating only some aspects of carbon's bonding aspects. Understanding the differences and similarities between these two elements is essential for comprehending the vast world of inorganic chemistry and materials science where silicon's chemical behavior is exploited, leading to innovative materials different from those based on carbon.

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Most popular questions from this chapter

Indicate the hybridization of the central atom in (a) \(\mathrm{BCl}_{3}\), (b) \(\mathrm{AlCl}_{4}^{-}\), (c) \(\mathrm{CS}_{2}\), (d) \(\mathrm{GeH}_{4}\) -

(a) How does one determine the number of electron domains in a molecule or ion? (b) What is the difference between a bonding electron domain and a nonbonding electron domain?

Antibonding molecular orbitals can be used to make bonds to other atoms in a molecule. For example, metal atoms can use appropriate \(d\) orbitals to overlap with the \(\pi_{2 p}^{*}\) orbitals of the carbon monoxide molecule. This is called \(d-\pi\) backbonding. (a) Draw a coordinate axis system in which the \(y\)-axis is vertical in the plane of the paper and the \(x\)-axis horizontal. Write " \(\mathrm{M}^{"}\) at the origin to denote a metal atom. (b) Now, on the \(x\) axis to the right of \(M\), draw the Lewis structure of a CO molecule, with the carbon nearest the \(M\). The CO bond axis should be on the \(x\)-axis. (c) Draw the \(\mathrm{CO} \pi_{2 p}^{*}\) orbital, with phases (see the "Closer Look" box on phases) in the plane of the paper. Two lobes should be pointing toward M. (d) Now draw the \(d_{x y}\) orbital of \(\mathrm{M}\), with phases. Can you see how they will overlap with the \(\pi_{2}^{*}\) orbital of \(\mathrm{CO}\) ? (e) What kind of bond is being made with the orbitals between \(M\) and \(\mathrm{C}_{,} \sigma\) or \(\pi\) ? (f) Predict what will happen to the strength of the CO bond in a metal\(\mathrm{CO}\) complex compared to \(\mathrm{CO}\) alone.

Which of the following statements about hybrid orbitals is or are true? (i) After an atom undergoes sp hybridization there is one unhybridized \(p\) orbital on the atom, (ii) Under \(s p^{2}\) hybridization, the large lobes point to the vertices of an equilateral triangle, and (iii) The angle between the large lobes of \(s p^{3}\) hybrids is \(109.5^{\circ}\).

Propylene, \(\mathrm{C}_{3} \mathrm{H}_{6}\), is a gas that is used to form the important polymer called polypropylene. Its Lewis structure is (a) What is the total number of valence electrons in the propylene molecule? (b) How many valence electrons are used to make \(\sigma\) bonds in the molecule? (c) How many valence electrons are used to make \(\pi\) bonds in the molecule? (d) How many valence electrons remain in nonbonding pairs in the molecule? (e) What is the hybridization at each carbon atom in the molecule?

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