One scale for electronegativity is based on the concept that the
electronegativity of any atom is proportional to the ionization energy of the
atom minus its electron affinity: electronegativity \(=k(I-E A)\), where \(k\) is
a proportionality constant. (a) How does this definition explain why the
electronegativity of \(\mathrm{F}\) is greater than that of \(\mathrm{Cl}\) even
though \(\mathrm{Cl}\) has the greater electron affinity? (b) Why are both
ionization energy and electron affinity relevant to the notion of
electronegativity? (c) By using data in Chapter 7 , determine the value of \(k\)
that would lead to an electronegativity of \(4.0\) for \(F\) under this
definition. (d) Use your result from part (c) to determine the
electronegativities of \(\mathrm{Cl}\) and \(\mathrm{O}\) using this scale. (e)
Another scale for electronegativity defines electronegativity as the average
of an atom's first ionization energy and its electron affinity. Using this
scale, calculate the electronegativities for the halogens, and scale them so
fluorine has an electronegativity of 4.0. On this scale, what is Br's
electronegativity?