Question

Write balanced equations for the following reactions: (a) barium oxide with water, (b) iron(II) oxide with perchloric acid, (c) sulfur trioxide with water, (d) carbon dioxide with aqueous sodium hydroxide.

Short answer

Here are the balanced equations for each reaction: (a) Barium oxide with water: \( BaO + H_2O \rightarrow Ba(OH)_2 \) (b) Iron(II) oxide with perchloric acid: \( 2FeO + 2HClO_4 \rightarrow 2Fe(ClO_4)_2 + 2H_2O \) (c) Sulfur trioxide with water: \( SO_3 + H_2O \rightarrow H_2SO_4 \) (d) Carbon dioxide with aqueous sodium hydroxide: \( CO_2 + 2NaOH \rightarrow Na_2CO_3 + H_2O \)

Step-by-step solution

Reaction 1: Barium oxide with water

1. Identify reactants and products: Reactants: Barium oxide (BaO) and water (H₂O) Product: Barium hydroxide (Ba(OH)₂) 2. Write the unbalanced equation: BaO + H₂O → Ba(OH)₂ 3. Balance the equation: BaO + H₂O → Ba(OH)₂ (The equation is already balanced with 1:1:1 stoichiometry)

Reaction 2: Iron(II) oxide with perchloric acid

1. Identify reactants and products: Reactants: Iron(II) oxide (FeO) and perchloric acid (HClO₄) Products: Iron(II) perchlorate (Fe(ClO₄)₂) and water (H₂O) 2. Write the unbalanced equation: FeO + HClO₄ → Fe(ClO₄)₂ + H₂O 3. Balance the equation: 2FeO + 2HClO₄ → 2Fe(ClO₄)₂ + 2H₂O

Reaction 3: Sulfur trioxide with water

1. Identify reactants and products: Reactants: Sulfur trioxide (SO₃) and water (H₂O) Product: Sulfuric acid (H₂SO₄) 2. Write the unbalanced equation: SO₃ + H₂O → H₂SO₄ 3. Balance the equation: SO₃ + H₂O → H₂SO₄ (The equation is already balanced with 1:1:1 stoichiometry)

Reaction 4: Carbon dioxide with aqueous sodium hydroxide

1. Identify reactants and products: Reactants: Carbon dioxide (CO₂) and aqueous sodium hydroxide (NaOH) Products: Sodium carbonate (Na₂CO₃) and water (H₂O) 2. Write the unbalanced equation: CO₂ + NaOH → Na₂CO₃ + H₂O 3. Balance the equation: CO₂ + 2NaOH → Na₂CO₃ + H₂O