Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Some metal oxides, such as Sc2O3, do not react with pure water, but they do react when the solution becomes either acidic or basic. Do you expect Sc2O3 to react when the solution becomes acidic or when it becomes basic? Write a balanced chemical equation to support your answer.

Short Answer

Expert verified
Sc2O3 is an amphoteric metal oxide, meaning it can react with both acidic and basic solutions. The balanced chemical equations are: Reaction with an acid (H+ ions): Sc2O3+6H+2Sc3++3H2O Reaction with a base (OH- ions): Sc2O3+6OH2Sc(OH)63

Step by step solution

01

Analyze the given compound Sc2O3

Sc2O3 is a metal oxide, which means it is composed of a metal (Sc) and oxygen (O). Metal oxides tend to be either basic or amphoteric, meaning they can react with either acids or bases.
02

Predict if Sc2O3 is basic or amphoteric

Sc2O3 is composed of scandium, which is a metal from Group 3 of the periodic table. Group 3 metal oxides typically display amphoteric behavior, meaning they can react with both acidic and basic solutions. We can therefore predict that Sc2O3 will react with acidic and basic solutions.
03

Write balanced chemical equations for reactions with acids and bases

As Sc2O3 is amphoteric, it will react with both acidic and basic solutions. Let's write balanced chemical equations for both reactions. Reaction with an acid (H+ ions): Sc2O3+6H+2Sc3++3H2O Reaction with a base (OH- ions): Sc2O3+6OH2Sc(OH)63 We have now written balanced chemical equations for the reaction of Sc2O3 with acidic and basic solutions. Sc2O3 will react with both acidic and basic solutions since it is an amphoteric metal oxide.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Discussing this chapter, a classmate says, "An element that commonly forms a cation is a metal." Do you agree or disagree? Explain your answer.

(a) One of the alkali metals reacts with oxygen to form a solid white substance. When this substance is dissolved in water, the solution gives a positive test for hydrogen peroxide, H2O2. When the solution is tested in a burner flame, a lilac-purple flame is produced. What is the likely identity of the metal? (b) Write a balanced chemical equation for the reaction of the white substance with water.

When magnesium metal is burned in air (Figure 3.6), two products are produced. One is magnesium oxide, MgO. The other is the product of the reaction of Mg with molecular nitrogen, magnesium nitride. When water is added to magnesium nitride, it reacts to form magnesium oxide and ammonia gas. (a) Based on the charge of the nitride ion (Table 2.5), predict the formula of magnesium nitride. (b) Write a balanced equation for the reaction of magnesium nitride with water. What is the driving force for this reaction? (c) In an experiment, a piece of magnesium ribbon is burned in air in a crucible. The mass of the mixture of MgO and magnesium nitride after burning is 0.470 g. Water is added to the crucible, further reaction occurs, and the crucible is heated to dryness until the final product is 0.486 g of MgO. What was the mass percentage of magnesium nitride in the mixture obtained after the initial burning? (d) Magnesium nitride can also be formed by reaction of the metal with ammonia at high temperature. Write a balanced equation for this reaction. If a 6.3-g Mg ribbon reacts with 2.57 gNH3(g) and the reaction goes to completion, which component is the limiting reactant? What mass of H2(g) is formed in the reaction? (e) The standard enthalpy of formation of solid magnesium nitride is 461.08 kJ/mol. Calculate the standard enthalpy change for the reaction between magnesium metal and ammonia gas.

Potassium superoxide, KO2, is often used in oxygen masks (such as those used by firefighters) because KO2 reacts with CO2 to release molecular oxygen. Experiments indicate that 2 mol of KO2(s) react with each mole of CO2(g). (a) The products of the reaction are K2CO3(s) and O2(g). Write a balanced equation for the reaction between KO2(s) and CO2(g). (b) Indicate the oxidation number for each atom involved in the reaction in part (a). What elements are being oxidized and reduced? (c) What mass of KO2(s) is needed to consume 18.0 gCO2( g) ? What mass of O2(g) is produced during this reaction?

Zinc in its 2+ oxidation state is an essential metal ion for life. Zn2+ is found bound to many proteins that are involved in biological processes, but unfortunately Zn2+ is hard to detect by common chemical methods. Therefore, scientists who are interested in studying Zn2+-containing proteins frequently substitute Cd2+ for Zn2+, since Cd2+ is easier to detect. (a) On the basis of the properties of the elements and ions discussed in this chapter and their positions in the periodic table, describe the pros and cons of using Cd2+ as a Zn2+ substitute. (b) Proteins that speed up (catalyze) chemical reactions are called enzymes. Many enzymes are required for proper metabolic reactions in the body. One problem with using Cd2+ to replace Zn2+ in enzymes is that Cd2+ substitution can decrease or even eliminate enzymatic activity. Can you suggest a different metal ion that might replace Zn2+ in enzymes instead of Cd2+ ? Justify your answer.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free