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Predict whether each of the following oxides is ionic or molecular: \(\mathrm{SnO}_{2}, \mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{CO}_{2}, \mathrm{Li}_{2} \mathrm{O}, \mathrm{Fe}_{2} \mathrm{O}_{3}, \mathrm{H}_{2} \mathrm{O}\).

Short Answer

Expert verified
Based on the analysis of electronegativity differences, we predict the following oxides to be ionic or molecular: \( SnO_{2} \) - Molecular \( Al_{2}O_{3} \) - Ionic \( CO_{2} \) - Molecular \( Li_{2}O \) - Ionic \( Fe_{2}O_{3} \) - Ionic \( H_{2}O \) - Molecular

Step by step solution

01

Determine the electronegativity values of each element

First, we need to find the electronegativity values of each element. We can use a periodic table or look up these values online.
02

Calculate the electronegativity difference between the elements in each compound

Next, we'll calculate the electronegativity difference for each compound by subtracting the smaller electronegativity value from the larger one. For example, for SnO2: Electronegativity of Sn: 1.96 Electronegativity of O: 3.44 Difference: 3.44 - 1.96 = 1.48 We'll repeat this process for each compound.
03

Determine if each compound is ionic or molecular based on electronegativity difference

Using our calculations, we'll determine if each compound is ionic or molecular based on the electronegativity difference. If the difference is 1.7 or greater, the compound is ionic. If the difference is less than 1.7, the compound is molecular. Here's what we've found based on these guidelines: \( SnO_{2} \) Electronegativity difference: 1.48 Verdict: Molecular \( Al_{2}O_{3} \) Electronegativity difference: 2.01 Verdict: Ionic \( CO_{2} \) Electronegativity difference: 0.89 Verdict: Molecular \( Li_{2}O \) Electronegativity difference: 2.30 Verdict: Ionic \( Fe_{2}O_{3} \) Electronegativity difference: 1.75 Verdict: Ionic \( H_2O \) Electronegativity difference: 1.24 Verdict: Molecular
04

Summary

Based on our analysis of electronegativity differences, we predict the following oxides to be ionic or molecular: \( SnO_{2} \) - Molecular \( Al_{2}O_{3} \) - Ionic \( CO_{2} \) - Molecular \( Li_{2}O \) - Ionic \( Fe_{2}O_{3} \) - Ionic \( H_{2}O \) - Molecular

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic and Molecular Compounds
Understanding the distinction between ionic and molecular compounds is pivotal for grasping foundational chemistry concepts. An ionic compound forms when there is a complete transfer of electrons from one atom to another, leading to the formation of oppositely charged ions. Typically, these compounds consist of a metal and a non-metal, such as sodium chloride ((SnO_{2}) is molecular, not ionic.

For instance, when considering aluminum oxide (CO_{2}) demonstrates a lower electronegativity difference (0.89), indicating that the attraction between the carbon and oxygen atoms does not result in electron transfer but in sharing, which categorizes (Li_{2}O) ensuring a strong electrostatic attraction and establishing it as an ionic compound.

In essence, to classify a compound as ionic or molecular, one must look not only at the electronegativity difference but also at the types of atoms involved and their bonding tendencies.
The Periodic Table
The periodic table is an organized arrangement of all known elements, providing a wealth of information at a glance. Elements are ordered by increasing atomic number and arranged into rows called periods and columns known as groups or families, which share common characteristics. One vital piece of information the periodic table provides is electronegativity, which is crucial for predicting the type of bond that forms between atoms.

To solve our textbook exercise, the periodic table acts as a map to find each element's electronegativity. Elements such as fluorine, found on the upper right of the table, exhibit high electronegativity, while those like lithium, located lower left, show lower values. This variation is what underpins our understanding of why some compounds, like (SnO_{2}) or Al_{2}O_{3}) and lithium oxide ((H_{2}O), fall on the molecular side, as the differences in electronegativity in these pairings are not drastic enough to cause full electron transfer.
Chemical Bonding
Chemical bonding is the process that enables atoms to join together to form compounds. Bonds result from attractions between atoms trying to reach a more stable energy state. Generally, bonds can be classified into three main types: ionic, covalent (molecular), and metallic.

Ionic bonds, as seen in lithium oxide ((H_{2}O), electrons are shared between atoms, leading to the formation of a molecule. The guidelines in our exercise use the electronegativity difference to determine the bond type because it implies how strongly an atom can attract and hold onto electrons. A larger difference often signals ionic bonding, as is the case for Al_{2}O_{3}), stoichiometry, and molecular geometry also play roles.

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Most popular questions from this chapter

Consider the following equation: $$ \mathrm{Ca}^{+}(g)+\mathrm{e}^{-} \longrightarrow \mathrm{Ca}(g) $$ Which of the following statements are true? (i) The energy change for this process is the electron affinity of the \(\mathrm{Ca}^{+}\)ion. (ii) The energy change for this process is the negative of the first ionization energy of the Ca atom. (iii) The energy change for this process is the negative of the electron affinity of the \(\mathrm{Ca}\) atom.

Detailed calculations show that the value of \(Z_{\text {eff }}\) for the outermost electrons in \(\mathrm{Na}\) and \(\mathrm{K}\) atoms is \(2.51+\) and \(3.49+\), respectively. (a) What value do you estimate for \(Z_{\text {eff }}\) experienced by the outermost electron in both \(\mathrm{Na}\) and \(\mathrm{K}\) by assuming core electrons contribute \(1.00\) and valence electrons contribute \(0.00\) to the screening constant? (b) What values do you estimate for \(Z_{\text {eff }}\) using Slater's rules? (c) Which approach gives a more accurate estimate of \(Z_{\text {eff ? }}\) ? (d) Does either method of approximation account for the gradual increase in \(Z_{\text {eff }}\) that occurs upon moving down a group? (e) Predict \(Z_{\text {eff }}\) for the outermost electrons in the \(\mathrm{Rb}\) atom based on the calculations for \(\mathrm{Na}\) and \(\mathrm{K}\).

Silver and rubidium both form \(+1\) ions, but silver is far less reactive. Suggest an explanation, taking into account the ground-state electron configurations of these elements and their atomic radii.

Hydrogen is an unusual element because it behaves in some ways like the alkali metal elements and in other ways like nonmetals. Its properties can be explained in part by its electron configuration and by the values for its ionization energy and electron affinity. (a) Explain why the electron affinity of hydrogen is much closer to the values for the alkali elements than for the halogens. (b) Is the following statement true? "Hydrogen has the smallest bonding atomic radius of any element that forms chemical compounds. If not, correct it. If it is, explain in terms of electron configurations. (c) Explain why the ionization energy of hydrogen is closer to the values for the halogens than for the alkali metals. (d) The hydride ion is \(\mathrm{H}\). Write out the process corresponding to the first ionization energy of the hydride ion. (e) How does the process in part (d) compare to the process for the electron affinity of a neutral hydrogen atom?

(a) What is meant by the term effective nuclear charge? (b) How does the effective nuclear charge experienced by the valence electrons of an atom vary going from left to right across a period of the periodic table?

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