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What is the relationship between the ionization energy of an anion with a \(1-\) charge such as \(\mathrm{F}^{-}\)and the electron affinity of the neutral atom, F?

Short Answer

Expert verified
The relationship between the ionization energy of an anion with a -1 charge (F-) and the electron affinity of the neutral atom (F) is that they represent the reverse processes of one another. The ionization energy of F- is the energy required to remove an electron from F-, while the electron affinity of F is the energy released when an electron is added to F to form F-.

Step by step solution

01

Definition of Ionization Energy

Ionization energy is the minimum amount of energy required to remove an electron from a neutral atom or ion (in this case, the anion F-). In the case of F-, the reaction can be represented as: \[ \mathrm{F}^{-} \rightarrow \mathrm{F} + e^{-} \]
02

Definition of Electron Affinity

Electron affinity is the energy released when an electron is added to a neutral atom (in this case, F) to form an anion (F-). The reaction can be represented as: \[ \mathrm{F} + e^{-} \rightarrow \mathrm{F}^{-} \]
03

Relationship between Ionization Energy and Electron Affinity

Comparing the two reactions, we can see that the ionization energy of F- is the reverse reaction of the electron affinity of F. In other words, ionization energy represents the energy required to remove an electron from F-, while electron affinity represents the energy released when an electron is added to F.
04

Conclusion

The relationship between the ionization energy of an anion with a -1 charge (F-) and the electron affinity of the neutral atom (F) is that they represent the reverse processes of one another. The ionization energy of F- is the energy required to remove an electron from F-, while the electron affinity of F is the energy released when an electron is added to F to form F-.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Affinity
Electron affinity is a fundamental concept in chemistry. It refers to the energy change that occurs when an electron is added to a neutral atom in its gaseous state. This process transforms the atom into a negatively charged ion, known as an anion. For fluorine (F), this process can be succinctly described by the equation: \[ \mathrm{F} + e^{-} \rightarrow \mathrm{F}^{-} \]When an electron is added, energy is usually released, indicating how strongly an atom wants to gain an electron. The greater the electron affinity, the more energy is released and the more likely it is for the atom to accept the electron.
  • Electron affinity is measured in kilojoules per mole (kJ/mol).
  • The process involves a neutral gaseous atom and an added electron.

This measure is significant because it highlights the tendency of an atom to become an anion.
Anion Chemistry
An anion is a negatively charged ion. It occurs when a neutral atom gains one or more electrons. In the case of fluorine, which becomes fluoride (\(\mathrm{F}^{-}\)) after gaining an electron, the electron affinity plays a pivotal role. The gained electron adds extra negative charge, hence forming an anion.
  • Anions are crucial in forming chemical compounds.
  • They engage in ionic bonding with positively charged ions (cations).
Anion chemistry is essential for understanding reactions and compound formation processes. The interaction between anions and cations leads to the formation of ionic compounds that are integral to both natural processes and technological applications. This knowledge helps in predicting behaviors like solubility and electrical conductivity in various environments.
Energy Transformations
Energy transformations are at the heart of ionization and electron affinity. They illustrate how energy changes during chemical processes.
In the case of electron affinity for fluorine, energy is released when an electron is added. Conversely, during ionization energy processes, energy is required to remove an electron from an ion. These energy transformations can be conceptualized as opposite reactions:
  • Electron affinity is exothermic (releases energy).
  • Ionization energy is endothermic (requires energy input).
Understanding these transformations helps predict and explain the stability and reactivity of different elements and ions.
In practical terms, these energy changes influence how substances like ions interact in diverse chemical environments and why certain reactions are more favorable than others. Recognizing these transformations can aid in mastering the energy behavior in complex reactions.

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Most popular questions from this chapter

We will see in Chapter 12 that semiconductors are materials that conduct electricity better than nonmetals but not as well as metals. The only two elements in the periodic table that are technologically useful semiconductors are silicon and germanium. Integrated circuits in computer chips today are based on silicon. Compound semiconductors are also used in the electronics industry. Examples are gallium arsenide, GaAs; gallium phosphide, GaP; cadmium sulfide, CdS; and cadmium selenide, CdSe. (a) What is the relationship between the compound semiconductors' compositions and the positions of their elements on the periodic table relative to \(\mathrm{Si}\) and \(\mathrm{Ge}\) ? (b) Workers in the semiconductor industry refer to "II-VI" and "III-V" materials, using Roman numerals. Can you identify which compound semiconductors are II-VI and which are III-V? (c) Suggest other compositions of compound semiconductors based on the positions of their elements in the periodic table.

Explain the following variations in atomic or ionic radii: (a) \(\mathrm{I}^{-}>\mathrm{I}>\mathrm{I}^{+}\) (b) \(\mathrm{Ca}^{2+}>\mathrm{Mg}^{2+}>\mathrm{Be}^{2+}\) (c) \(\mathrm{Fe}>\mathrm{Fe}^{2+}>\mathrm{Fe}^{3+}\)

Use electron configurations to explain the following observations: (a) The first ionization energy of phosphorus is greater than that of sulfur. (b) The electron affinity of nitrogen is lower (less negative) than those of both carbon and oxygen. (c) The second ionization energy of oxygen is greater than the first ionization energy of fluorine. (d) The third ionization energy of manganese is greater than those of both chromium and iron.

Consider the first ionization energy of neon and the electron affinity of fluorine. (a) Write equations, including electron configurations, for each process. (b) These two quantities have opposite signs. Which will be positive, and which will be negative? (c) Would you expect the magnitudes of these two quantities to be equal? If not, which one would you expect to be larger?

Compare the elements bromine and chlorine with respect to the following properties: (a) electron configuration, (b) most common ionic charge, (c) first ionization energy, (d) reactivity toward water, (e) electron affinity, (f) atomic radius. Account for the differences between the two elements.

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