Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Using only the periodic table, arrange each set of atoms in order of increasing radius: (a) \(\mathrm{Ba}, \mathrm{Ca}, \mathrm{Na}\); (b) In, \(\mathrm{Sn}, \mathrm{As}\); (c) \(\mathrm{Al}, \mathrm{Be}, \mathrm{Si}\).

Short Answer

Expert verified
Using the periodic table trends, the order of increasing atomic radius for each set of atoms is: (a) Na, Ca, Ba; (b) As, In, Sn; (c) Be, Al, Si.

Step by step solution

01

(a) Ba, Ca, Na - Increasing Atomic Radius

First, locate the positions of Ba, Ca, and Na in the periodic table. - Ba (Barium) is in group 2 and period 6 - Ca (Calcium) is in group 2 and period 4 - Na (Sodium) is in group 1 and period 3 Since all elements are in period 3 or further down, we prioritize the group trend (atomic radius increases going down a group). Hence the order of increasing atomic radius is: Na, Ca, Ba.
02

(b) In, Sn, As - Increasing Atomic Radius

Locate the positions of In, Sn, and As in the periodic table. - In (Indium) is in group 13 and period 5 - Sn (Tin) is in group 14 and period 5 - As (Arsenic) is in group 15 and period 4 In and Sn are in the same period, so we prioritize the period trend (atomic radius decreases as we go left to right across a period). As is one period above In and Sn; hence, it will be the smallest among three. The order of increasing atomic radius is: As, In, Sn.
03

(c) Al, Be, Si - Increasing Atomic Radius

Locate the positions of Al, Be, and Si in the periodic table. - Al (Aluminum) is in group 13 and period 3 - Be (Beryllium) is in group 2 and period 2 - Si (Silicon) is in group 14 and period 3 No two elements are in the same period, so we need to consider both group and period trends. The order of increasing atomic radius due to both effects is: Be, Al, Si.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Periodic Table
The periodic table is an organized chart of chemical elements, arranged in order of increasing atomic number, which corresponds to the number of protons in an atom's nucleus. This arrangement shows recurring "periodic" trends in the properties of the elements. It consists of rows, known as periods, and columns, called groups or families.

Each element in a period has one more proton and is slightly more massive than the element before it. Elements in the same group share chemical properties, primarily because they have the same number of valence electrons that participate in chemical reactions. The periodic table helps chemists understand and predict the behavior of elements in chemical reactions. Its organization is crucial for studying trends and patterns in atomic structure and properties.
Group and Period Trends
In the periodic table, understanding trends within groups and periods helps predict element properties like atomic radius, ionization energy, and electronegativity.

  • **Group Trends:** As you move down a group (a column) in the periodic table, the atomic radius of an element increases. This happens because each subsequent element has an additional shell of electrons, which makes the atom larger despite an overall increase in nuclear charge.

  • **Period Trends:** Moving across a period (a row) from left to right, the atomic radius tends to decrease. This is because electrons are added to the same shell while protons are being added to the nucleus, increasing the nuclear charge which pulls the electron cloud closer to the nucleus, making the atom smaller.
These trends are essential for predicting the size of an atom compared to others when arranging them in order of increasing atomic radius.
Atomic Size
Atomic size, often referred to as atomic radius, is a measure of the size of an atom's electron cloud, which surrounds the nucleus. Since the precise edge of an atom is difficult to define, atomic size is typically approximated by measuring the distance between the nuclei of two bonded atoms and dividing by two.

The atomic radius can be affected by:
  • **Number of Electron Shells:** More electron shells mean a larger atomic radius, as seen when moving down a group.

  • **Nuclear Charge:** A higher number of protons (atomic number) results in a stronger pull on electrons, which decreases the atomic radius as you move across a period.
Understanding atomic size is fundamental in explaining the reactive nature of an element. It helps in determining how elements interact with one another and their positioning in the periodic table aids in predicting atomic size.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Which ion is smaller, \(\mathrm{Co}^{3+}\) or \(\mathrm{Co}^{4+}\) ? (b) In a lithium-ion battery that is discharging to power a device, for every \(\mathrm{Li}^{+}\)that inserts into the lithium cobalt oxide electrode, \(\mathrm{a} \mathrm{Co}^{4+}\) ion must be reduced to \(\mathrm{Co}^{3+}\) ion to balance charge. Using the \(C R C\) Handbook of Chemistry and Physics or other standard reference, find the ionic radii of \(\mathrm{Li}^{+}, \mathrm{Co}^{3+}\), and \(\mathrm{Co}^{4+}\). Order these ions from smallest to largest. (c) Will the lithium cobalt electrode expand or contract as lithium ions are inserted? (d) Lithium is not nearly as abundant as sodium. If sodium ion batteries were developed that function as lithium ion ones, do you think "sodium cobalt oxide" would still work as the electrode material? Explain. (e) If you don't think cobalt would work as the redox-active partner ion in the sodium version of the electrode, suggest an alternative metal ion and explain your reasoning.

Consider the first ionization energy of neon and the electron affinity of fluorine. (a) Write equations, including electron configurations, for each process. (b) These two quantities have opposite signs. Which will be positive, and which will be negative? (c) Would you expect the magnitudes of these two quantities to be equal? If not, which one would you expect to be larger?

Use electron configurations to explain the following observations: (a) The first ionization energy of phosphorus is greater than that of sulfur. (b) The electron affinity of nitrogen is lower (less negative) than those of both carbon and oxygen. (c) The second ionization energy of oxygen is greater than the first ionization energy of fluorine. (d) The third ionization energy of manganese is greater than those of both chromium and iron.

Silver and rubidium both form \(+1\) ions, but silver is far less reactive. Suggest an explanation, taking into account the ground-state electron configurations of these elements and their atomic radii.

Arrange each of the following sets of atoms and ions, in order of increasing size: (a) \(\mathrm{Se}^{2-}, \mathrm{Te}^{2-}, \mathrm{Se} ;\) (b) \(\mathrm{Co}^{3+}, \mathrm{Fe}^{2+}, \mathrm{Fe}^{3+}\); (c) \(\mathrm{Ca}^{2 \mathrm{Ti}^{4+}}, \mathrm{Sc}^{3+}\); (d) \(\mathrm{Be}^{2+}, \mathrm{Na}^{+}, \mathrm{Ne}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free