Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) Why are fats well suited for energy storage in the human body? (b) A particular chip snack food is composed of \(12 \%\) protein, \(14 \%\) fat, and the rest carbohydrate. What percentage of the calorie content of this food is fat? (c) How many grams of protein provide the same fuel value as \(25 \mathrm{~g}\) of fat?

Short Answer

Expert verified
(a) Fats are well suited for energy storage in the human body because they provide more than twice the amount of energy per gram compared to proteins and carbohydrates (9 Calories/gram for fats vs. 4 Calories/gram for proteins and carbohydrates). This allows the body to store more energy in a smaller amount of space. (b) 26.81% of the calorie content in the chip snack food is from fat. (c) 56.25 grams of protein provide the same fuel value as 25 grams of fat.

Step by step solution

01

(a) Explanation for energy storage suitability for fats in the human body

Fats are well suited for energy storage in the human body because they provide more than twice the amount of energy per gram compared to proteins and carbohydrates. With 9 Calories per gram of fat, the human body can store more energy in a smaller amount of space, which is essential for maintaining body functions, warmth, and activity levels when food is scarce.
02

(b) The percentage of calorie content from fat

We know that the chip snack food is composed of 12% protein, 14% fat, and the rest carbohydrate, which implies the carbohydrate content is 100% - 12% - 14% = 74%. The calorie content for each component per gram is as follows: - Protein: 4 Calories per gram - Carbohydrate: 4 Calories per gram - Fat: 9 Calories per gram To find the percentage of overall calorie content from fat, we follow these steps: 1. Calculate Calories from each gram of protein, carbohydrate, and fat. 2. Calculate the total Calories. 3. Calculate the percentage of Calories from fat. To maintain uniformity, let's assume the chip snack food weighs 100 grams. Therefore, the amounts are: - Protein: 12 grams - Carbohydrate: 74 grams - Fat: 14 grams
03

Calculate Calories from each component

Protein: \(12\text{ g} \times 4\text{ Calories/g} = 48\text{ Calories}\) Carbohydrate: \(74\text{ g} \times 4\text{ Calories/g} = 296\text{ Calories}\) Fat: \(14\text{ g} \times 9\text{ Calories/g} = 126\text{ Calories}\)
04

Calculate total Calories

Total Calories: \(48\text{ Calories (protein)} + 296\text{ Calories (carbohydrate)} + 126\text{ Calories (fat)} = 470\text{ Calories}\)
05

Calculate percentage of Calories from fat

Percentage of Calories from fat: \(\frac{126\text{ Calories (fat)}}{470\text{ Calories (total)}} \times 100\% = 26.81\% \) Thus, 26.81% of the calorie content in this chip snack food is from fat.
06

(c) Grams of protein providing the same fuel value as 25g of fat

We are given that 25 grams of fat provide a certain amount of energy, and we need to find how many grams of protein would provide the same amount of energy. First, we'll find the energy provided by 25 grams of fat.
07

Calculate energy from 25 grams of fat

Energy from 25 grams of fat: \(25\text{ g} \times 9\text{ Calories/g} = 225\text{ Calories}\) Now we'll find the amount of protein (in grams) needed to provide this amount of energy.
08

Calculate grams of protein for the same energy

Let's denote the grams of protein as \(x\): \(x\text{ g (protein)} \times 4\text{ Calories/g}\ = 225\text{ Calories}\) Now, we'll solve for \(x\): \(x = \frac{225\text{ Calories}}{4\text{ Calories/g}} = 56.25\text{ g}\) Therefore, 56.25 grams of protein provide the same fuel value as 25 grams of fat.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) is currently blended with gasoline as an automobile fuel. (a) Write a balanced equation for the combustion of liquid ethanol in air. (b) Calculate the standard enthalpy change for the reaction, assuming \(\mathrm{H}_{2} \mathrm{O}(g)\) as a product. (c) Calculate the heat produced per liter of ethanol by combustion of ethanol under constant pressure. Ethanol has a density of \(0.789 \mathrm{~g} / \mathrm{mL}\). (d) Calculate the mass of \(\mathrm{CO}_{2}\) produced per \(\mathrm{kJ}\) of heat emitted.

Identify the force present and explain whether work is being performed in the following cases: (a) You lift a pencil off the top of a desk. (b) A spring is compressed to half its normal length.

(a) When a 4.25-g sample of solid ammonium nitrate dissolves in \(60.0 \mathrm{~g}\) of water in a coffee-cup calorimeter (Figure \(5.17)\), the temperature drops from \(22.0\) to \(16.9^{\circ} \mathrm{C}\). Calculate \(\Delta H\left(\right.\) in \(\mathrm{kJ} / \mathrm{mol} \mathrm{} \mathrm{NH}_{4} \mathrm{NO}_{3}\) ) for the solution process: $$ \mathrm{NH}_{4} \mathrm{NO}_{3}(s) \longrightarrow \mathrm{NH}_{4}^{+}(a q)+\mathrm{NO}_{3}^{-}(a q) $$ Assume that the specific heat of the solution is the same as that of pure water. (b) Is this process endothermic or exothermic?

Calculate \(\Delta E\) and determine whether the process is endothermic or exothermic for the following cases: (a) \(q=0.763 \mathrm{~kJ}\) and \(w=-840 \mathrm{~J}\). (b) A system releases \(66.1 \mathrm{~kJ}\) of heat to its surroundings while the surroundings do \(44.0 \mathrm{~kJ}\) of work on the system.

5.104 We can use Hess's law to calculate enthalpy changes that cannot be measured. One such reaction is the conversion of methane to ethylene: $$ 2 \mathrm{CH}_{4}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g) $$ Calculate the \(\Delta H^{\circ}\) for this reaction using the following thermochemical data: $$ \begin{array}{ll} \mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l) & \Delta H^{\circ}=-890.3 \mathrm{~kJ} \\ \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{6}(g) & \Delta H^{\circ}=-136.3 \mathrm{~kJ} \\ 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(l) & \Delta H^{\circ}=-571.6 \mathrm{~kJ} \\ 2 \mathrm{C}_{2} \mathrm{H}_{6}(g)+7 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l) & \Delta H^{\circ}=-3120.8 \mathrm{~kJ} \end{array} $$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free