At one time, a common means of forming small quantities of oxygen gas in the
laboratory was to heat \(\mathrm{KClO}_{3}\) :
$$
2 \mathrm{KClO}_{3}(s) \longrightarrow 2 \mathrm{KCl}(s)+3 \mathrm{O}_{2}(g)
\quad \Delta H=-89.4 \mathrm{~kJ}
$$
For this reaction, calculate \(\Delta H\) for the formation of (a) \(1.36\)
\(\mathrm{mol}\) of \(\mathrm{O}_{2}\) and (b) \(10.4 \mathrm{~g}\) of
\(\mathrm{KCl}\). (c) The decomposition of \(\mathrm{KClO}_{3}\) proceeds
spontaneously when it is heated. Do you think that the reverse reaction, the
formation of \(\mathrm{KClO}_{3}\) from \(\mathrm{KCl}\) and \(\mathrm{O}_{2}\), is
likely to be feasible under ordinary conditions? Explain your answer.