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Acetone, \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\), is a nonelectrolyte; hypochlorous acid, \(\mathrm{HClO}\), is a weak electrolyte; and ammonium chloride, \(\mathrm{NH}_{4} \mathrm{Cl}\), is a strong electrolyte. (a) What are the solutes present in aqueous solutions of each compound? (b) If \(0.1 \mathrm{~mol}\) of each compound is dissolved in solution, which one contains \(0.2 \mathrm{~mol}\) of solute particles, which contains \(0.1 \mathrm{~mol}\) of solute particles, and which contains somewhere between \(0.1\) and \(0.2 \mathrm{~mol}\) of solute particles?

Short Answer

Expert verified
(a) The solutes present in aqueous solutions are: 1. Acetone: \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\) 2. Hypochlorous Acid: \(\mathrm{H^+}\) and \(\mathrm{ClO^-}\) 3. Ammonium Chloride: \(\mathrm{NH}_{4}^+\) and \(\mathrm{Cl}^-\). (b) Based on the number of solute particles, the solutions are: 1. Acetone has 0.1 mol of solute particles. 2. Hypochlorous acid has between 0.1 and 0.2 mol of solute particles. 3. Ammonium chloride has 0.2 mol of solute particles.

Step by step solution

01

Identify Solutes in Aqueous Solutions

To identify the solutes in aqueous solution, we should know how these compounds dissociate when dissolved in water: 1. Acetone, being a nonelectrolyte, does not dissociate. It remains intact: \[\mathrm{CH}_{3} \mathrm{COCH}_{3}\]. 2. Hypochlorous acid, being a weak electrolyte, dissociates partially into ions: \[\mathrm{HClO} \rightleftharpoons \mathrm{H^+} + \mathrm{ClO^-}\]. 3. Ammonium chloride, being a strong electrolyte, dissociates completely into ions: \[\mathrm{NH}_{4} \mathrm{Cl} \rightarrow \mathrm{NH}_{4}^+ + \mathrm{Cl}^-\].
02

Determine the Amount of Solute Particles

Now let's determine the amount of solute particles present when 0.1 mol of each compound is dissolved in a solution: 1. Acetone, 0.1 mol remains intact, so the number of solute particles is 0.1 mol. 2. Hypochlorous acid, 0.1 mol dissociates partially: We assume a certain extent 'x' dissociates, then we have x mol of \(\mathrm{H^+}\) and x mol of \(\mathrm{ClO^-}\). Hence, the number of solute particles is \((0.1 - x) + x + x = 0.1 + x\), where \(0 < x < 0.1\). 3. Ammonium chloride, 0.1 mol dissociates completely, so we have 0.1 mol of \(\mathrm{NH}_{4}^+\) and 0.1 mol of \(\mathrm{Cl}^-\), which gives a total of 0.2 mol solute particles.
03

Identify the Solutions in Terms of Solute Particles

Now we can determine which solution has 0.2 mol, 0.1 mol, and somewhere between 0.1 to 0.2 mol of solute particles: 1. Acetone solution contains 0.1 mol of solute particles. 2. Hypochlorous acid solution contains between 0.1 and 0.2 mol of solute particles. 3. Ammonium chloride solution contains 0.2 mol of solute particles. So, the solution to the exercise is: (a) The solutes present in aqueous solutions are: 1. Acetone: \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\) 2. Hypochlorous Acid: \(\mathrm{H^+}\) and \(\mathrm{ClO^-}\) 3. Ammonium Chloride: \(\mathrm{NH}_{4}^+\) and \(\mathrm{Cl}^-\). (b) Based on the number of solute particles, the solutions are: 1. Acetone has 0.1 mol of solute particles. 2. Hypochlorous acid has between 0.1 and 0.2 mol of solute particles. 3. Ammonium chloride has 0.2 mol of solute particles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nonelectrolytes
Nonelectrolytes are substances that, when dissolved in water, do not produce ions. These materials do not conduct electricity in their aqueous form because they do not separate into charged particles. A classic example of a nonelectrolyte is acetone (CH_{3}COCH_{3}), which is used in the textbook exercise. Acetone molecules remain whole in solution, resulting in 0.1 mol of solute particles since it does not dissociate at all.

Understanding this concept is crucial when predicting the behavior of a substance in solution. For students, a helpful way to remember nonelectrolytes is to think about many organic compounds, such as sugars and alcohols, which typically fall into this category.
Weak Electrolytes
Weak electrolytes are substances that partially dissociate into ions when dissolved in water, which means they only partially conduct electricity. Hypochlorous acid (HClO) demonstrates this behavior. In the exercise, the key is to realize that weak electrolytes establish a dynamic equilibrium between the undissociated molecules and the ions they form.

The proportion of dissociated molecules to undissociated ones varies, which is represented by 'x' in the solution; 'x' being the fraction that dissociates. Thus, the total amount of solute particles is greater than 0.1 mol but less than 0.2 mol. To help students visualize this concept, using an analogy like a partially unzippered zipper, where some teeth separate and others remain joined, could be instructive.
Strong Electrolytes
Strong electrolytes are substances that fully dissociate into ions in solution, thus conducting electricity well. Ammonium chloride (NH_{4}Cl), as used in our problem, is a strong electrolyte. When 0.1 mol of ammonium chloride is dissolved in water, it fully separates into 0.1 mol of ammonium ions (NH_{4}^{+}) and 0.1 mol of chloride ions (Cl^{-}), totaling 0.2 mol of ions.

To assimilate this knowledge, students might imagine a strong electrolyte as a bag of popcorn in a microwave; once heated (dissolved in water), all kernels (molecules) pop (dissociate) into popcorn (ions). This full dissociation characteristic of strong electrolytes is critical for understanding their behavior in various chemical reactions and applications.

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Most popular questions from this chapter

Formic acid, HCOOH, is a weak electrolyte. What solutes are present in an aqueous solution of this compound? Write the chemical equation for the ionization of HCOOH.

Classify each of the following substances as a nonelectrolyte, weak electrolyte, or strong electrolyte in water: (a) \(\mathrm{H}_{2} \mathrm{SO}_{3}\), (b) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) (ethanol), (c) \(\mathrm{NH}_{3}\), (d) \(\mathrm{KClO}_{3}\), (e) \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\).

State whether each of the statements below is true or false. Justify your answer in each case. (a) Electrolyte solutions conduct electricity because electrons are moving through the solution. (b) If you add a nonelectrolyte to an aqueous solution that already contains an electrolyte, the electrical conductivity will not change.

Determine the oxidation number of sulfur in each of the following substances: (a) barium sulfate, \(\mathrm{BaSO}_{4}\), (b) sulfurous acid, \(\mathrm{H}_{2} \mathrm{SO}_{3}\), (c) strontium sulfide, \(\mathrm{SrS}\), (d) hydrogen sulfide, \(\mathrm{H}_{2} \mathrm{~S}\). (e) Locate sulfur in the periodic table in Exercise 4.47; what region is it in? (f) Which region(s) of the period table contains elements that can adopt both positive and negative oxidation numbers?

Federal regulations set an upper limit of 50 parts per million (ppm) of \(\mathrm{NH}_{3}\) in the air in a work environment [that is, 50 molecules of \(\mathrm{NH}_{3}(g)\) for every million molecules in the air]. Air from a manufacturing operation was drawn through a solution containing \(1.00 \times 10^{2} \mathrm{~mL}\) of \(0.0105 \mathrm{M} \mathrm{HCl}\). The \(\mathrm{NH}_{3}\) reacts with \(\mathrm{HCl}\) according to: $$ \mathrm{NH}_{3}(a q)+\mathrm{HCl}(a q) \longrightarrow \mathrm{NH}_{4} \mathrm{Cl}(a q) $$ After drawing air through the acid solution for \(10.0 \mathrm{~min}\) at a rate of \(10.0 \mathrm{~L} / \mathrm{min}\), the acid was titrated. The remaining acid needed \(13.1 \mathrm{~mL}\) of \(0.0588 \mathrm{M} \mathrm{NaOH}\) to reach the equivalence point. (a) How many grams of \(\mathrm{NH}_{3}\) were drawn into the acid solution? (b) How many ppm of \(\mathrm{NH}_{3}\) were in the air? (Air has a density of \(1.20 \mathrm{~g} / \mathrm{L}\) and an average molar mass of \(29.0 \mathrm{~g} / \mathrm{mol}\) under the conditions of the experiment.) (c) Is this manufacturer in compliance with regulations?

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