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Write balanced chemical equations to correspond to each of the following descriptions: (a) When sulfur trioxide gas reacts with water, a solution of sulfuric acid forms. b) Boron sulfide, \(\mathrm{B}_{2} \mathrm{~S}_{3}(s)\), reacts violently with water to form dissolved boric acid, \(\mathrm{H}_{3} \mathrm{BO}_{3}\), and hydrogen sulfide gas. (c) Phosphine, \(\mathrm{PH}_{3}(g)\), combusts in oxygen gas to form water vapor and solid tetraphosphorus decaoxide. (d) When solid mercury(II) nitrate is heated, it decomposes to form solid mercury(II) oxide, gaseous nitrogen dioxide, and oxygen. (e) Copper metal reacts with hot concentrated sulfuric acid solution to form aqueous copper(II) sulfate, sulfur dioxide gas, and water.

Short Answer

Expert verified
The balanced chemical equations are as follows: (a) SO₃(g) + H₂O(l) → H₂SO₄(aq) (b) B₂S₃(s) + 6H₂O(l) → 2H₃BO₃(aq) + 3H₂S(g) (c) 4PH₃(g) + 5O₂(g) → 6H₂O(g) + P₄O₁₀(s) (d) 2Hg(NO₃)₂(s) → 2HgO(s) + 4NO₂(g) + O₂(g) (e) Cu(s) + H₂SO₄(aq) → CuSO₄(aq) + SO₂(g) + H₂O(l)

Step by step solution

01

Identify reactants and products, and write their chemical formulas

Reactants: Sulfur trioxide (SO₃), water (H₂O) Product: Sulfuric acid (H₂SO₄)
02

Write the unbalanced chemical equation

SO₃(g) + H₂O(l) → H₂SO₄(aq)
03

Balance the equation

SO₃(g) + H₂O(l) → H₂SO₄(aq) (Already balanced) (b) Boron sulfide, B₂S₃(s), reacts violently with water to form dissolved boric acid, H₃BO₃, and hydrogen sulfide gas.
04

Identify reactants and products, and write their chemical formulas

Reactants: Boron sulfide (B₂S₃), water (H₂O) Products: Boric acid (H₃BO₃), hydrogen sulfide (H₂S)
05

Write the unbalanced chemical equation

B₂S₃(s) + H₂O(l) → H₃BO₃(aq) + H₂S(g)
06

Balance the equation

B₂S₃(s) + 6H₂O(l) → 2H₃BO₃(aq) + 3H₂S(g) (c) Phosphine, PH₃(g), combusts in oxygen gas to form water vapor and solid tetraphosphorus decaoxide.
07

Identify reactants and products, and write their chemical formulas

Reactants: Phosphine (PH₃), oxygen (O₂) Products: Water vapor (H₂O), tetraphosphorus decaoxide (P₄O₁₀)
08

Write the unbalanced chemical equation

PH₃(g) + O₂(g) → H₂O(g) + P₄O₁₀(s)
09

Balance the equation

4PH₃(g) + 5O₂(g) → 6H₂O(g) + P₄O₁₀(s) (d) When solid mercury(II) nitrate is heated, it decomposes to form solid mercury(II) oxide, gaseous nitrogen dioxide, and oxygen.
10

Identify reactants and products, and write their chemical formulas

Reactant: Mercury(II) nitrate (Hg(NO₃)₂) Products: Mercury(II) oxide (HgO), nitrogen dioxide (NO₂), oxygen (O₂)
11

Write the unbalanced chemical equation

Hg(NO₃)₂(s) → HgO(s) + NO₂(g) + O₂(g)
12

Balance the equation

2Hg(NO₃)₂(s) → 2HgO(s) + 4NO₂(g) + O₂(g) (e) Copper metal reacts with hot concentrated sulfuric acid solution to form aqueous copper(II) sulfate, sulfur dioxide gas, and water.
13

Identify reactants and products, and write their chemical formulas

Reactants: Copper (Cu), sulfuric acid (H₂SO₄) Products: Copper(II) sulfate (CuSO₄), sulfur dioxide (SO₂), water (H₂O)
14

Write the unbalanced chemical equation

Cu(s) + H₂SO₄(aq) → CuSO₄(aq) + SO₂(g) + H₂O(l)
15

Balance the equation

Cu(s) + H₂SO₄(aq) → CuSO₄(aq) + SO₂(g) + H₂O(l) (Already balanced)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
Chemical reactions are processes where substances, called reactants, change into new substances, known as products. This transformation occurs due to the rearrangement of atoms, creating a new set of chemical bonds in the products.
In the world of chemistry, these reactions are represented using chemical equations, which show the essential details of the reactants converting into products. Observing these transformations allows us to understand how substances interact and how new compounds form.
For instance, when sulfur trioxide reacts with water to form sulfuric acid, a chemical reaction occurs. Reactants on the left side of the chemical equation, like sulfur trioxide (\( ext{SO}_3(g) \)) and water (\( ext{H}_2 ext{O}(l) \)), come together to produce a new compound, such as sulfuric acid (\( ext{H}_2 ext{SO}_4(aq) \)) which is found on the right side.
Balancing Equations
Balancing chemical equations is crucial because it reflects the conservation of mass principle. This principle ensures that atoms are neither created nor destroyed in a chemical reaction. Consequently, the number of atoms of each element must be the same on both sides of the equation.
Balancing begins with writing the correct unbalanced equation using chemical formulas, outlining what happens during the reaction.
Here's an example: Boron sulfide (\( ext{B}_2 ext{S}_3(s) \)) reacts with water (\( ext{H}_2 ext{O}(l) \)) to form boric acid (\( ext{H}_3 ext{BO}_3(aq) \)) and hydrogen sulfide (\( ext{H}_2 ext{S}(g) \)). To balance the equation, coefficients are used:
  1. Determine the initial amounts of each element on both sides.
  2. Adjust the coefficients to equalize the number of each type of atom in the reactants and products.
  3. Check your work to ensure the equation is balanced.
Thus, the balanced equation becomes (\[ ext{B}_2 ext{S}_3(s) + 6 ext{H}_2 ext{O}(l) \rightarrow 2 ext{H}_3 ext{BO}_3(aq) + 3 ext{H}_2 ext{S}(g) \]).
Reactants and Products
In any chemical equation, reactants and products are fundamental components. Reactants are the starting substances that undergo a chemical change.
Products are the new substances formed as a result of the reaction. The transformation from reactants to products is what defines a chemical reaction.
Understanding the nature and composition of these chemicals is essential. The chemical equations are like recipes that tell us what's needed and what's produced. For example, in this exercise:
  • Reactants, such as phosphine (\( ext{PH}_3(g) \)) and oxygen (\( ext{O}_2(g) \)), start the reaction.
  • Products, like water vapor (\( ext{H}_2 ext{O}(g) \)) and tetraphosphorus decaoxide (\( ext{P}_4 ext{O}_{10}(s) \)), are the outcome of the chemical process.
Accurate identification of reactants and products is crucial for crafting correct and balanced chemical equations.

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Most popular questions from this chapter

The fizz produced when an Alka-Seltzer tablet is dissolved in water is due to the reaction between sodium bicarbonate \(\left(\mathrm{NaHCO}_{3}\right)\) and citric acid \(\left(\mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}\right)\) : $$ \begin{aligned} 3 \mathrm{NaHCO}_{3}(a q)+& \mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}(a q) \longrightarrow \\ & 3 \mathrm{CO}_{2}(g)+3 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Na}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}(a q) \end{aligned} $$ In a certain experiment \(1.00 \mathrm{~g}\) of sodium bicarbonate and \(1.00 \mathrm{~g}\) of citric acid are allowed to react. (a) Which is the limiting reactant? (b) How many grams of carbon dioxide form? (c) How many grams of the excess reactant remain after the limiting reactant is completely consumed?

Balance the following equations: (a) \(\mathrm{Al}_{4} \mathrm{C}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{Al}(\mathrm{OH})_{3}(s)+\mathrm{CH}_{4}(g)\) (b) \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}(l)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)\) (c) \(\mathrm{Fe}(\mathrm{OH})_{3}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{Fe}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) (d) \(\mathrm{Mg}_{3} \mathrm{~N}_{2}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{MgSO}_{4}(a q)+\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}(a q)\)

Balance the following equations: (a) \(\mathrm{Ca}_{3} \mathrm{P}_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{Ca}(\mathrm{OH})_{2}(a q)+\mathrm{PH}_{3}(g)\) (b) \(\mathrm{Al}(\mathrm{OH})_{3}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) (c) \(\mathrm{AgNO}_{3}(a q)+\mathrm{Na}_{2} \mathrm{CO}_{3}(a q) \longrightarrow \mathrm{Ag}_{2} \mathrm{CO}_{3}(s)+\mathrm{NaNO}_{3}(a q)\) (d) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{N}_{2}(g)\)

The molecular formula of aspartame, the artificial sweetener marketed as NutraSweet \({ }^{\infty}\), is \(\mathrm{C}_{14} \mathrm{H}_{18} \mathrm{~N}_{2} \mathrm{O}_{5}\). (a) What is the molar mass of aspartame? (b) How many moles of aspartame are present in \(1.00 \mathrm{mg}\) of aspartame? (c) How many molecules of aspartame are present in \(1.00 \mathrm{mg}\) of aspartame? (d) How many hydrogen atoms are present in \(1.00 \mathrm{mg}\) of aspartame?

When hydrogen sulfide gas is bubbled into a solution of sodium hydroxide, the reaction forms sodium sulfide and water. How many grams of sodium sulfide are formed if \(1.25 \mathrm{~g}\) of hydrogen sulfide is bubbled into a solution containing \(2.00 \mathrm{~g}\) of sodium hydroxide, assuming that the sodium sulfide is made in \(92.0 \%\) yield?

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