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How many structural isomers are there for a five straight carbon chain with one double bond? member straight carbon chain with two double bon.

Short Answer

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There are 4 possible structural isomers for a five straight carbon chain with one double bond and 2 possible structural isomers for a five straight carbon chain with two double bonds.

Step by step solution

01

Identifying the molecular formula

For a five straight carbon chain with one double bond, the molecular formula is C5H10.
02

Considering double bond placement

The double bond can be placed between any two adjacent carbon atoms. In a five-carbon chain, there are four possibilities: between C1 and C2, between C2 and C3, between C3 and C4, or between C4 and C5. So, the possible structural isomers for a five straight carbon chain with one double bond are: 1. C1=C2-C3-C4-C5 2. C1-C2=C3-C4-C5 3. C1-C2-C3=C4-C5 4. C1-C2-C3-C4=C5 There are 4 possible structural isomers in this case. #Case 2: Two double bonds in the five-carbon chain#
03

Identifying the molecular formula

For a five straight carbon chain with two double bonds, the molecular formula is C5H8.
04

Considering double bond placement

To place two double bonds in the five carbon chain, we need at least one carbon atom between them. There are two possible arrangements for the double bonds: 1. Two double bonds with one carbon in between (C1=C2-C3=C4-C5) 2. Two double bonds placed at the ends of the chain (C1=C2-C3-C4=C5) So, the possible structural isomers for a five straight carbon chain with two double bonds are: 1. C1=C2-C3=C4-C5 2. C1=C2-C3-C4=C5 There are 2 possible structural isomers in this case.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Formula
The molecular formula provides a clear snapshot of the numbers of each type of atom in a molecule. Take the compound with a five-carbon chain and one double bond, which has the molecular formula C5H10. This tells us we have five carbon atoms and ten hydrogen atoms. The formula remains constant, regardless of the structure's shape or double bond placement; only the arrangement of the atoms changes.

In organic chemistry, the molecular formula is the starting point for understanding the structure and potential isomers of a compound. It's crucial for students to recognize and write the correct formula before exploring the different structural configurations.
Double Bond Placement
In the study of organic chemistry, the double bond placement is key to determining the structural variations of compounds. A double bond consists of four bonding electrons between two carbons, as opposed to the single bond's two electrons. This double bond affects the molecule's geometry and reactivity.

When considering a carbon chain, double bonds create more rigid structures and limit rotation, leading to various structural isomers based on their location. For instance, placing the double bond between different pairs of carbons in a five-carbon chain yields distinct isomers. These subtle shifts in placement can significantly modify the molecule's properties.
Organic Chemistry
Organic chemistry is the chemistry subdiscipline involved with carbon-containing compounds. This branch of chemistry covers a vast range of substances, including those that make up living organisms. Structural isomers are a fundamental concept in organic chemistry, as they represent compounds with the same molecular formula but different structural arrangements. This can lead to varied physical and chemical properties even though the compounds contain the exact same atoms.

Researchers in this field explore the nuances of carbon-based molecules, their synthesis, and how different bonds between atoms can lead to different molecular structures and, by extension, different chemical behaviors.
Isomer Counting
Isomer counting is a practice within organic chemistry for identifying all possible isomers for a given molecular formula. Isomers are compounds that share the same molecular formula but have different arrangements of atoms, leading to different structures.

To count isomers, you must consider all possible variations in the chain and the position of functional groups, like double bonds. With a five-carbon chain possessing one double bond, there are four possible structural isomers. If the same chain has two double bonds, the number changes to two. Understanding how to correctly count isomers, including taking note of the bonds and atoms involved, is crucial for students to master the complexity of organic compounds.

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Most popular questions from this chapter

Aldehydes and ketenes can be named in a systematic way by counting the number of carbon atoms (including the carbonyl carbon) that they contain. The name of the aldehyde or ketone is based on the hydrocarbon with the same number of carbon atoms. The ending - al for aldehyde or-one for ketone is added as appropriate. Draw the structural formulas for the following aldehydes or ketones: (a) propanal, (b) 2-pentanone, (c) 3 -methyl-2-butanone, (d) 2-methylbutanal.

A typical amino acid with one amino group and one carboxylic acid group, such as serine, can exist in water in several ionic forms. (a) Suggest the forms of the amino acid at low pH and at high pH. (b) Amino acids generally have two pKa values, one in the range of 2 to 3 and the other in the range of 9 to 10. Serine, for example, has pKK4 values of 2.19 and 9.21. Using species such as acetic acid and ammonia as models, suggest the origin of the two pKa values. (c) Glutamic acid is an amino acid that has three pKa ' ×2.10,4.07, and 9.47. Draw the structure of glutamic acid, and assign each pKa to the appropriate part of the molecule. (d) An unknown amino acid is titrated with strong base, producing the following titration curve. Which amino acids are likely candidates for the unknown?

(a) What is the empirical formula of starch? (b) What is the monomer that forms the basis of the starch polymer? (c) What bond connects the monomer units in starch: amide, acid, ether, ester, or alcohol?

The standard free energy of formation of solid glycine is 369 kJ/mol, whereas that of solid glycylglycine is 488kl/mol. What is ΔG4 for the condensation of glycine to form glycylglycine?

Pure acetic acid is a viscous liquid, with high melting and boiling points ( 16.7C and 118C ) compared to compounds of similar molecular weight. Suggest an explanation.

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