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Draw the condensed structural formulas for two molecules with the formula \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\).

Short Answer

Expert verified
Two possible molecules with the formula \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\) are: 1. Propenal (an aldehyde): \(CH_2=CH-CHO\) 2. 2-Propen-1-ol (an allyl alcohol): \(CH_2=C(CH_3)-OH\)

Step by step solution

01

Identify possible functional groups and molecular skeletons

Since the molecular formula is \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\), we should check for common functional groups like the carbonyl group (-C=O), alcohol group (-OH) or alkene (-C=C-). In addition, we should also consider different molecular skeletons, like a linear or branched carbon chain.
02

Generate isomers

Let's form two different molecules by adjusting the positions of the functional groups and molecular skeletons. Molecule 1: Since we have 3 carbons and 1 oxygen, we can make a linear molecule with an aldehyde functional group. In this case, we will have a double bond (C=O) and the other carbons forming singly bonded (C-C) chains. Molecule 2: For the branched molecule, there are two carbons in the main chain, while the other carbon is attached to the second carbon, creating an alcohol group (-OH) attached to the last carbon.
03

Draw the condensed structural formulas

Now that we have outlined the structures of two different molecules that have the formula \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\), let's draw their condensed structural formulas. Molecule 1: \(CH_2=CH-CHO\) (propenal, an aldehyde) Molecule 2: \(CH_2=C(CH_3)-OH\) (2-propen-1-ol, an allyl alcohol)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Condensed Structural Formula
In organic chemistry, the condensed structural formula is a streamlined way to represent the arrangement of atoms in a molecule. It shows which atoms are connected to which, but unlike the full structural formula, it does not explicitly display every single bond. It conveniently lists atoms close together to indicate bonding. For example, in the exercise, the condensed structural formula of propenal is given as \(CH_2=CH-CHO\). This indicates:
  • Carbons are forming a carbon chain.
  • Double bonds are written with '=' between atoms.
  • The placement of \(CHO\) signifies it is bonded to a carbon that is double-bonded within the chain.
This method allows for an easy and quick representation of organic molecules without drawing out each bond explicitly. But it's important to remember that it only suggests atom connectivity and we often need the full displayed structure for a complete understanding.
Isomerism
Isomerism is a fascinating concept in organic chemistry, where molecules with the same molecular formula have different arrangements of atoms or bonds. These different forms are called isomers. In the exercise, the formula \(C_3H_4O\) was illustrated to produce two such isomers:
  • Propenal with a linear aldehyde structure: \(CH_2=CH-CHO\)
  • 2-propen-1-ol with a branched alcohol structure: \(CH_2=C(CH_3)-OH\)
The difference between them lies in their connectivity and placement of functional groups while having the same atoms and numbers. Isomerism highlights chemical diversity in specific formulas, as these varied structures can lead to dramatically different chemical properties and functions.
Functional Groups
Functional groups are specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. They define many of the properties and reactions of organic compounds. For molecules with the formula \(C_3H_4O\), they exhibit different functional groups which drastically alter their chemical behavior:
  • Aldehyde group (-CHO) in propenal, which gives it typical aldehyde properties such as participation in nucleophilic addition reactions.
  • Alcohol group (-OH) in 2-propen-1-ol, which allows it to engage in reactions typical of alcohols, like dehydration or hydrogen bonding.
These functional groups not only determine molecular reactivity but also often define the categories into which organic compounds fall, making them a central theme in the study of organic chemistry.

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Most popular questions from this chapter

A typical amino acid with one amino group and one carboxylic acid group, such as serine, can exist in water in several ionic forms. (a) Suggest the forms of the amino acid at low pH and at high \(\mathrm{pH}\). (b) Amino acids generally have two \(\mathrm{p} K_{a}\) values, one in the range of 2 to 3 and the other in the range of 9 to 10. Serine, for example, has \(\mathrm{pK} K_{4}\) values of \(2.19\) and \(9.21\). Using species such as acetic acid and ammonia as models, suggest the origin of the two \(\mathrm{pK}_{\mathrm{a}}\) values. (c) Glutamic acid is an amino acid that has three \(\mathrm{pK}_{a}\) ' \(\times 2.10,4.07\), and 9.47. Draw the structure of glutamic acid, and assign each \(\mathrm{p} K_{a}\) to the appropriate part of the molecule. (d) An unknown amino acid is titrated with strong base, producing the following titration curve. Which amino acids are likely candidates for the unknown?

Indicate whether each statement is true or false: (a) Fat molecules contain amide bonds. (b) Phosphoplipids can be zwitterions. (c) Phespholipids form bilayers in water in order to have their long hydrophobic tails interact favorably with each other, leaving their polar heads to the aqueous environment.

Indicate whether each statement is true or false: (a) In the alpha helical structure of proteins, hydrogen bonding occurs between the side chains (R groups). (b) Dispersion forces, not hydrogen bonding, holds beta sheet structures together. Carbohydrates and Lipids (Sections \(24.8\) and 24.9)

The IUPAC name for a carboxylic acid is based on the name of the hydrocarbon with the same number of carbon atoms. The ending -oic is appended, as in ethanoic acid, which is the IUPAC name for acetic acid. Draw the structure of the following acids: (a) methanoic acid, (b) pentanoic acid, (c) 2-chloro-3-methyldecanoic acid.

Does 3-chloro-3-methylhexane have optical isomers? Why or why not? Introduction to Biochemistry; Proteins (Sections \(24.6\) and \(24.7)\)

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