Question

Enediynes are a class of compounds that include some antibiotic drugs. Draw the structure of an "enediyne" fragment that contains six carbons in a row.

Short answer

The enediyene fragment containing six carbons in a row can be represented by the following structure: H H | | H-C=C-C≡C-C≡C | | H H

Step-by-step solution

Identify the Alkene and Diyne Positions

To create a six-carbon enediyene fragment, we need to first consider the positions of the alkene and diyne bonds in the structure. Since there are only six carbons, we can start by identifying pi-bond positions to create the enediyene fragment. The alkene can be positioned between carbons 1 and 2, and the diyne can be positioned between carbons 3 and 4, and carbons 5 and 6.

Illustrate the Bonds

Now that the positions of the alkene and diyne have been identified, the next step is to draw the structure. Start by drawing 6 carbon atoms in a row, and then add the appropriate bonds between these carbons: a single bond between carbons 2 and 3 and a single bond between carbons 4 and 5. Add a double bond between carbons 1 and 2, create two triple bonds between carbons 3 and 4, and between carbons 5 and 6.

Add Hydrogen Atoms

After completing the carbon framework, it's essential to add the necessary hydrogen atoms bonded to each carbon, fulfilling the tetravalency of carbon atoms. Add hydrogen atoms to each of the carbon atoms so that each carbon atom has four bonds. There should be two hydrogen atoms on carbon 1, one hydrogen atom on carbon 2, only one hydrogen atom on both carbon 3 and 6, and no hydrogen atoms on carbon 4 and 5. The resulting structure for the enediyene fragment containing six carbons in a row is as follows: H H | | H-C=C-C≡C-C≡C | | H H