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(c) When the coordinated water to the \(\mathrm{Zn}(\mathrm{II})\) center in carbonic anhydrase is deprotonated, what ligands are bound to the Zn(II) center? Assume the three nitrogen ligands are unaffected. (d) The \(\mathrm{F} K_{a}\) of \(\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{d}\right]^{2+}\) is 10 . Suggest an explanation for the difference between this \(\mathrm{pK} \mathrm{K}_{\text {and }}\) that of carbonic anhydrase. (e) Would you expect carbonic anhydrase to have a decp color, like hemoglobin and other metalion containing proteins do? Explain. Two different compounds have the formulation \(\mathrm{CoBr}\left(\mathrm{SO}_{4}\right) \cdot 5 \mathrm{NH}_{3}\). Compound \(\mathrm{A}\) is dark violet, and compound B is red-violet. When compound \(A\) is treated with \(\mathrm{AgNO}_{3}(\mathrm{Gq})\), no reaction occurs, whereas compound \(\mathrm{B}\)

Short Answer

Expert verified
When the coordinated water to the Zn(II) center in carbonic anhydrase is deprotonated, the ligands bound to the Zn(II) center include the three nitrogen ligands and the hydroxide ion (OH-). The difference in pKa values between [Zn(H2O)d]2+ and carbonic anhydrase might be due to the different electron-withdrawing capabilities of the ligands surrounding the Zn(II) center. Carbonic anhydrase is not likely to have a deep color like hemoglobin and other metal-containing proteins, as the ligands bound to the Zn(II) center do not have extensive conjugation or chelation.

Step by step solution

01

(c) Identifying the ligands bound to Zn(II) center

In carbonic anhydrase, the Zn(II) center is initially coordinated to three nitrogen ligands and a water molecule. When the coordinated water is deprotonated, a hydroxide ion (OH-) is formed and remains bound to the Zn(II) center. Therefore, when the coordinated water to the Zn(II) center in carbonic anhydrase is deprotonated, the ligands bound to the Zn(II) center include the three nitrogen ligands and the hydroxide ion (OH-).
02

(d) Explaining differences in pKa values

The pKa value of [Zn(H2O)d]2+ is 10, and it is different from that of carbonic anhydrase. The difference in pKa values might be due to the different electron-withdrawing capabilities of the ligands surrounding the Zn(II) center. In carbonic anhydrase, the ligands are stronger electron-withdrawing species (such as OH-) compared to the ligands in [Zn(H2O)d]2+. This causes the Zn(II)-OH bond in carbonic anhydrase to be more polar, making it more acidic and thus having a lower pKa value than [Zn(H2O)d]2+.
03

(e) Predicting color of carbonic anhydrase

It is not likely that carbonic anhydrase will have a deep color like hemoglobin and other metal-containing proteins. The reason for this is that the color in metal-containing proteins is often due to the presence of ligands with extensive conjugation or chelation that allows for the absorption of visible light. In carbonic anhydrase, the ligands bound to the Zn(II) center (three nitrogen ligands and OH-) do not have such extensive conjugation or chelation, so the complex will not absorb visible light to the same extent, and therefore, will not exhibit a deep color.
04

Analysis of CoBr(SO4) ยท 5NH3 compounds

Compound A is dark violet with no reaction to AgNO3, while compound B is red-violet and reacts with AgNO3. This reactivity suggests that in Compound B, the Br- ion is a ligand, and Ag+ can replace it, forming AgBr as a precipitate. In contrast, Compound A must have the Br- ion involved in an ionic bond, so it remains unaffected by AgNO3. The different colors of these compounds indicate that their ligands or the arrangement of ligands around the Co center are different, which affects their electronic transitions and absorption of visible light.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ligand Coordination
In carbonic anhydrase, the coordination of ligands around the zinc (Zn(II)) center plays a crucial role. Initially, the Zn(II) center is bound to one water molecule and three nitrogen ligands. The water molecule undergoes deprotonation, leaving a hydroxide ion (OH-) in its place. This substitution is important because it alters the overall coordination environment, while the nitrogen ligands remain unaffected.

Ligand coordination impacts how a metal center like Zn(II) interacts with its environment. These interactions can affect the stability and reactivity of the enzyme. In carbonic anhydrase, effective coordination ensures the enzyme accurately fulfills its role in regulating pH and converting carbon dioxide to bicarbonate. Understanding these interactions helps in grasping fundamental enzyme mechanisms and potentially developing inhibitors or therapeutic agents.
pKa Value Differences
The pKa value, which indicates the acidity of a compound, varies for different complexes such as \([\text{Zn(H}_2 \text{O})_d]\text{]^{2+}\) and carbonic anhydrase. While the former has a pKa value of 10, carbonic anhydrase presents a much lower pKa.

This discrepancy can be attributed to the nature of the ligands surrounding the zinc center. In carbonic anhydrase, electron-withdrawing ligands like the hydroxide ion create a more polar environment. This increases acidity by stabilizing the negative charge after deprotonation, thus resulting in a lower pKa.

The concept of pKa is crucial for understanding biochemical environments. It illustrates how alterations in ligand character and coordination can significantly change the chemical behavior and function of metalloproteins. By studying these differences, scientists can better explain enzyme performance and potential therapeutic applications.
Color Prediction of Metalloproteins
Metalloproteins often exhibit colors due to specific ligand interactions; however, carbonic anhydrase is not among those displaying vivid colors like hemoglobin. This is due to the type of ligands presentโ€”three nitrogen ligands and a hydroxide ion bound to its Zn(II) center.

Color in metalloproteins usually arises when ligands have extensive conjugation or chelation, which impact how light is absorbed and reflected. These traits cause certain electronic transitions that absorb visible light, coloring the protein.

Since carbonic anhydrase lacks highly conjugated or chelated ligands, it absorbs visible light less efficiently. Consequently, it exhibits no deep color. This understanding helps explore how structural features influence not only the aesthetic but also functional properties of metalloproteins. These insights are useful in fields such as biochemistry and materials science, guiding design and identification of biofunctional materials.

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Most popular questions from this chapter

Draw the crystal-field energy-level diagrams and show the placement of electrons for the following complexes: (a) \(\left[\mathrm{VCl}_{6}\right]^{3-}\), (b) \(\left[\mathrm{FeF}_{6}\right]^{3-}\) (a high-spin complex), (c) \([\text { Ru(bipy) }]^{3+}\) (a low-spin complex), (d) \(\left[\mathrm{NiCl}_{4}\right]^{2-}\) (tetrahedral), (e) \(\left[\mathrm{PtBr}_{6}\right]^{2-},(f)\left[\mathrm{Ti}(\mathrm{en})_{3}\right]^{2+}\). S in the spectrochemical series?

The complex \(\left[\mathrm{Ru}(\mathrm{EDTA})\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{-}\)undergoes substitution reactions with several ligands, replacing the water molecule with the ligand. In all cases, the ruthenium stays in the \(+3\) oxidation state and the ligands use a nitrogen donor atom to bind to the metal. $$ \left[\operatorname{Ru}(\mathrm{EDTA})\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{-}+\mathrm{L} \longrightarrow[\operatorname{Ru}(\mathrm{EDTA}) \mathrm{L}]^{-}+\mathrm{H}_{2} \mathrm{O} $$ The rate constants for several ligands are as follows: (a) One possible mechanism for this substitution reaction is that the water molecule dissociates from the Ru(III) in the rate-determining step, and then the ligand L binds to Ru(III) in a rapid second step. A second possible mechanism is that L approaches the complex, begins to form a new bond to the Ru(III), and displaces the water molecule, all in a single concerted step. Which of these two mechanisms is more consistent with the data? Explain. (b) What do the results suggest about the relative donor ability of the nitrogens of the three ligands toward Ru(TII))? (c) Assuming that the complexes are all low spin, how many unpaired electrons are in each?

The red color of ruby is due to the presence of \(\mathrm{Cr}(\mathrm{III})\) ions at octahedral sites in the dose-packed exide lattice of \(\mathrm{Al}_{2} \mathrm{O}_{2}\). Draw the crystal-field splitting diagram for \(\mathrm{Cr}\) (III) in this environment. Suppose that the ruby crystal is subjected to high pressure. What do you predict for the variation in the wavelength of absorption of the ruby as a function of pressure? Explain.

Give the number of (valence) \(d\) electrons associated with the central metal ion in each of the following complexes: (a) \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\), (b) \(\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]\left(\mathrm{NO}_{3}\right)_{2}\) (c) \(\mathrm{Na}\left[\mathrm{Ag}(\mathrm{CN})_{2}\right]\), (d) \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{ClO}_{4}\), (c) \([\mathrm{Sr}(\mathrm{EDTA})]^{2-}\) -

(a) What is the meaning of the term coordination number as it applies to metal complexes? (b) Give an example of a ligand that is neutral and one that is negatively charged. (c) Would you expect ligands that are positively charged to be common? Explain. (d) What type of chemical bonding is characteristic of coordination compounds? Illustrate with the compound \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{2}\). (e) What are the most common coordination numbers for metal complexes?

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