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Draw the crystal-field energy-level diagrams and show the placement of electrons for the following complexes: (a) \(\left[\mathrm{VCl}_{6}\right]^{3-}\), (b) \(\left[\mathrm{FeF}_{6}\right]^{3-}\) (a high-spin complex), (c) \([\text { Ru(bipy) }]^{3+}\) (a low-spin complex), (d) \(\left[\mathrm{NiCl}_{4}\right]^{2-}\) (tetrahedral), (e) \(\left[\mathrm{PtBr}_{6}\right]^{2-},(f)\left[\mathrm{Ti}(\mathrm{en})_{3}\right]^{2+}\). S in the spectrochemical series?

Short Answer

Expert verified
In summary, the crystal-field energy-level diagrams and electron placements for the given complexes are: (a) \([\text{VCl}_{6}]^{3-}\): Octahedral, high-spin; 2 electrons in \(t_{2g}\) orbitals. (b) \([\text{FeF}_{6}]^{3-}\): Octahedral, high-spin; 3 electrons in \(t_{2g}\) and 2 in \(e_{g}\) orbitals. (c) \([\text{Ru(bipy)}]^{3+}\): Octahedral, low-spin; 5 electrons in \(t_{2g}\) orbitals. (d) \([\text{NiCl}_{4}]^{2-}\): Tetrahedral; 3 electrons in \(e\) and 5 in \(t_{2}\) orbitals. (e) \([\text{PtBr}_{6}]^{2-}\): Octahedral, low-spin; 6 electrons in \(t_{2g}\) orbitals. (f) \([\text{Ti(en)}_{3}]^{2+}\): Octahedral, low-spin; 2 electrons in \(t_{2g}\) orbitals.

Step by step solution

01

Determine the Electron Configuration

The vanadium ion in this complex has a +3 oxidation state, so it has the electron configuration of [Ar] 3d^{2}.
02

Determine the Geometry and Splitting Pattern

The complex is octahedral, and in octahedral complexes, the d-orbitals are split into two sets: \(e_{g}\) (dx2-y2, dz2) and \(t_{2g}\) (dxy, dyz, dxz). Since Cl- is a weak field ligand, the complex is high-spin.
03

Draw the Diagram and Place the Electrons

In high-spin complexes, electrons fill the orbitals according to Hund's rule. We would first fill the \(t_{2g}\) orbitals and then the \(e_{g}\) orbitals. So, in this case, the two electrons go into the \(t_{2g}\) orbitals, one in each orbital. (b) \(\left[\mathrm{FeF}_{6}\right]^{3-}\)
04

Determine the Electron Configuration

The iron ion in this complex has a +3 oxidation state and has an electron configuration of [Ar] 3d^{5}.
05

Determine the Geometry and Splitting Pattern

The complex is octahedral, so it has the same \(e_{g}\) and \(t_{2g}\) splitting pattern as in (a). The problem states that this is a high-spin complex.
06

Draw the Diagram and Place the Electrons

The electron filling follows Hund's rule, which results in three electrons in the \(t_{2g}\) orbitals and two in the \(e_{g}\) orbitals. (c) \([\text { Ru(bipy) }]^{3+}\)
07

Determine the Electron Configuration

The ruthenium ion in this complex has a +3 oxidation state, so it has an electron configuration of [Kr] 4d^{5}.
08

Determine the Geometry and Splitting Pattern

The complex is octahedral, so it has the same \(e_{g}\) and \(t_{2g}\) splitting pattern as in (a). The problem states that this is a low-spin complex.
09

Draw the Diagram and Place the Electrons

In low-spin complexes, electrons first occupy the lower-energy orbitals before any pairing takes place. Therefore, all five electrons are in the \(t_{2g}\) orbitals, with two orbitals having two electrons and one having just one electron. (d) \(\left[\mathrm{NiCl}_{4}\right]^{2-}\)
10

Determine the Electron Configuration

The nickel ion in this complex has a +2 oxidation state, so it has an electron configuration of [Ar] 3d^{8}.
11

Determine the Geometry and Splitting Pattern

The complex is tetrahedral, so the d-orbitals are split into two sets: \(e\) (dxy, dyz, dxz) and \(t_{2}\) (dx2-y2, dz2).
12

Draw the Diagram and Place the Electrons

The electron filling follows Hund's rule, resulting in three electrons in the \(e\) orbitals and five in the \(t_{2}\) orbitals. (e) \(\left[\mathrm{PtBr}_{6}\right]^{2-}\)
13

Determine the Electron Configuration

The platinum ion in this complex has a +4 oxidation state, so it has an electron configuration of [Xe] 4f^{14} 5d^{6}.
14

Determine the Geometry and Splitting Pattern

The complex is octahedral and Pt(IV) is a strong field, so this is a low-spin complex with an \(e_{g}\) and \(t_{2g}\) splitting pattern.
15

Draw the Diagram and Place the Electrons

In this low-spin complex, the electrons first occupy the lower-energy orbitals, the \(t_{2g}\) subset. Therefore, all six electrons are in the three \(t_{2g}\) orbitals. (f) \(\left[\mathrm{Ti}(\mathrm{en})_{3}\right]^{2+}\)
16

Determine the Electron Configuration

The titanium ion in this complex has a +2 oxidation state, so it has an electron configuration of [Ar] 3d^{2}.
17

Determine the Geometry and Splitting Pattern

The complex is octahedral, so it has the same \(e_{g}\) and \(t_{2g}\) splitting pattern as in (a). Since en is a moderately strong field ligand, this is a low-spin complex.
18

Draw the Diagram and Place the Electrons

In this low-spin complex, both electrons occupy the lower-energy \(t_{2g}\) orbitals.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Octahedral Complexes
Octahedral complexes consist of a central metal ion surrounded by six ligands arranged at the corners of an octahedron. This geometry creates a unique environment that affects the energy levels of the metal ion's d-orbitals, leading to a phenomenon known as crystal field splitting. In an octahedral field, the d-orbitals split into two groups: three t2g orbitals with lower energy and two eg orbitals with higher energy. This splitting pattern is crucial for determining the electronic structure and properties of the complex.

When electrons occupy these split d-orbitals, their arrangement follows specific rules based on the nature of the ligands, which can be either strong field (low-spin) or weak field (high-spin). Understanding the electron configuration in these complexes is vital as it influences their color, magnetic properties, and reactivity.
High-Spin and Low-Spin Complexes
The difference between high-spin and low-spin complexes is determined by the strength of the field produced by the ligands. High-spin complexes occur when the metal is surrounded by weak field ligands, which results in a smaller splitting of the d-orbitals. Electrons prefer to occupy the higher energy eg orbitals to maintain unpaired spins as per Hund's rule, leading to a maximum number of unpaired electrons.

On the other hand, low-spin complexes form with strong field ligands that produce a larger splitting of the d-orbitals. In this scenario, electrons fill the lower energy t2g orbitals first, and pairing occurs even if empty eg orbitals are available, resulting in a minimal number of unpaired electrons. These nuances in electron arrangement have profound effects on the chemical behavior of the complex.
Electron Configuration
Electron configuration refers to the distribution of electrons in the atomic or molecular orbitals of an element or compound. For transition metal complexes, the configuration is expressed in terms of the number of electrons in the d-orbitals. The knowledge of the oxidation state of the metal ion and its electronic configuration in its free ion state (before complexation) is essential to determine how the d-orbitals will be filled once the metal forms a complex.

In the context of crystal field theory, the electron configuration is influenced by the splitting of the d-orbitals into t2g and eg sets. Whether the complex is high-spin or low-spin alters the electron placement and directly impacts the magnetic and optical properties of the complex.
d-Orbital Splitting
d-Orbital splitting is at the heart of crystal-field theory. It explains the separation of the five degenerate d-orbitals into subsets with different energy levels upon the approach of ligands to a metal ion. In an octahedral crystal field, this splitting results in the lower-energy t2g orbitals and the higher-energy eg orbitals. The energy gap between these subsets, known as the crystal field splitting energy (Δoct), determines whether a complex adopts a high-spin or low-spin electron configuration.

Factors like the nature of the ligands and the metal ion's charge can affect the magnitude of Δoct. Ligands are often ranked according to their ability to split these orbitals on the spectrochemical series, with strong-field ligands inducing greater splitting and favoring low-spin arrangements, while weak-field ligands induce lesser splitting and favor high-spin arrangements.
Hund's Rule
Hund's rule, also known as the rule of maximum multiplicity, is a guiding principle for electron distribution in degenerate orbitals such as the t2g and eg sets in transition metal complexes. According to this rule, electrons occupy empty orbitals singly before they pair up. Electrons in singly occupied orbitals keep parallel spins as far as possible, which minimizes electron-electron repulsions and lowers the total energy of the atom or ion.

Applying Hund's rule in the context of crystal field theory helps predict the magnetic properties of complexes, as the number of unpaired electrons determines whether the complex will be diamagnetic (all electrons paired) or paramagnetic (one or more unpaired electrons). When combined with the knowledge of the ligand field strength, Hund's rule reveals whether a complex is high-spin or low-spin.

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Most popular questions from this chapter

For each of the following polydentate ligands, determine (i) the maximum number of coordination sites that the ligand can occupy on a single metal ion and (ii) the number and type of donor atoms in the ligand: (a) acetylacetonate ion (acac), (b) phenanthroline (phen), (c) diethylenetriamine, (d) carbonate ion, (e) triphosphate ion.

A Cu electrode is immersed in a solution that is \(1.00 \mathrm{M}\) in \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) and \(1.00 \mathrm{M}\) in \(\mathrm{NH}_{3}\). When the cathode is a standard hydrogen electrode, the emf of the cell is found to be \(+0.08 \mathrm{~V}\). What is the formation constant for \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) ?

The most important oxides of iron are magnetite, \(\mathrm{Fe}_{3} \mathrm{O}_{4}\), and hematite, \(\mathrm{Fe}_{2} \mathrm{O}_{3}\). (a) What are the oxidation states of iron in these compounds? (b) One of these iron oxides is ferrimagnetic, and the other is antiferromagnetic. Which iron oxide is likely to show which type of magnetism? Explain. Transition-Metal Complexes (Section 23.2)

Based on the molar conductance values listed here for the series of platinum(IV) complexes, write the formula for each complex so as to show which ligands are in the coordination sphere of the metal. By way of example, the molar conductances of \(0.050 \mathrm{M} \mathrm{NaCl}\) and \(\mathrm{BaCl}_{2}\) are \(107 \mathrm{ohm}^{-1}\) and \(197 \mathrm{ohm}^{-1}\), respectively. \begin{tabular}{lc} \hline Complex & Molar Conductance \(\left(o \text { ohm }^{-1}\right)^{*}\) of \(0.050\) M Solution \\ \hline \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{4}\) & 523 \\ \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{4}\) & 228 \\ \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{4}\) & 97 \\ \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{4}\) & 0 \\ \(\left.\mathrm{KPt}_{4}\right) \mathrm{NH}_{5}\) & 108 \\ \hline \end{tabular} "The ohm is a unit of resistance; conductance is the inverse of resistance.

Give the number of (valence) d clectrons associated with the central metal ion in each of the following complexess (a) \(\mathrm{K}_{3}\left[\mathrm{TiCl}_{6}\right]\), (b) \(\mathrm{Na}_{3}\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)_{6}\right]\), (c) \(\left[\mathrm{Ru}(e n)_{3}\right] \mathrm{Br}_{3}\), (d) \([\mathrm{Mo}(\mathrm{EDTA})] \mathrm{ClO}_{4}\), (e) \(\mathrm{K}_{3}\left[\mathrm{ReCl}_{6}\right]\)

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