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For each of the following metals, write the electronic configuration of the atom and its \(2+\) ion: (a) \(\mathrm{Mn}\), (b) \(\mathrm{Ru}\), (c) \(\mathrm{Rh}\). Draw the crystal-field energy-level diagram for the \(d\) orbitals of an octahedral complex, and show the placement of the \(d\) electrons for each \(2+\) ion, assuming a strong-field complex. How many unpaired electrons are there in each case?

Short Answer

Expert verified
The electronic configurations for the metal atoms are: Mn: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5\), Ru: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^6\), and Rh: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^7\). For their 2+ ions, the configurations are: Mn2+: \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^5\), Ru2+: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 4d^6\), and Rh2+: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 4d^7\). In an octahedral strong-field complex, Mn2+ has 5 unpaired electrons in t2g orbitals, Ru2+ has 1 unpaired electron in eg orbitals, and Rh2+ has 1 unpaired electron in eg orbitals.

Step by step solution

01

Write the electronic configuration for the given metal atoms

For this step, we will first find the atomic number of each metal to write their electronic configuration: (a) Mn (Manganese) - Atomic number: 25 (b) Ru (Ruthenium) - Atomic number: 44 (c) Rh (Rhodium) - Atomic number: 45 Now, we will write their electronic configuration: (a) Mn: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5\) (b) Ru: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^6\) (c) Rh: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^7\)
02

Write the electronic configuration for the 2+ ions

For this step, we need to remove two electrons from each metal atom to obtain the 2+ ions. Removing electrons from the outermost shell first: (a) Mn2+: \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^5\) (b) Ru2+: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 4d^6\) (c) Rh2+: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 4d^7\)
03

Draw the crystal-field energy-level diagram for the d orbitals

To draw the crystal-field energy-level diagram, we consider an octahedral complex, where there are two sets of d orbitals: the lower energy set (dxy, dxz, dyz) and the higher energy set (dx2-y2, and d z2). The lower energy set is written as t2g orbitals, and the higher energy set is written as eg orbitals. In strong-field complexes, electrons will pair in the t2g orbitals before filling the eg orbitals (due to the larger energy gap between them).
04

Show the placement of d electrons for each 2+ ion

We will now fill in the d electrons for each 2+ ion within the t2g and eg orbitals, according to their electronic configurations: (a) Mn2+ (3d^5): 5 electrons in the t2g orbitals (b) Ru2+ (4d^6): 5 electrons in the t2g orbitals and 1 electron in the eg orbitals (c) Rh2+ (4d^7): 5 electrons in the t2g orbitals and 2 electrons in the eg orbitals
05

Calculate the number of unpaired electrons for each 2+ ion

To find the number of unpaired electrons, we will count the unpaired electrons in each ion's t2g and eg orbitals: (a) Mn2+: 5 unpaired electrons in t2g orbitals (5 d electrons in total) (b) Ru2+: 1 unpaired electron in eg orbitals (6 d electrons in total) (c) Rh2+: 1 unpaired electron in eg orbitals (7 d electrons in total) In conclusion, there are 5 unpaired electrons for Mn2+, 1 unpaired electron for Ru2+, and 1 unpaired electron for Rh2+.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Atomic Number
The atomic number is a fundamental property of an element that tells us the number of protons in the nucleus of an atom. It dictates an element's position on the periodic table and its chemical behavior. Each element has a unique atomic number, which is equal to the number of electrons in an electrically neutral atom. For example, manganese (Mn) has an atomic number of 25, meaning it has 25 protons in its nucleus and, in its neutral state, 25 electrons orbiting the nucleus. Understanding the atomic number is essential for determining the electronic configuration of an element, which describes the arrangement of electrons in shells and subshells around the atomic nucleus.

Knowing the atomic number helps you predict how an element will react chemically and what type of ions it will form. For instance, during the formation of metal ions, an atom will lose electrons from its outermost shell, resulting in a cation with a positive charge.
Exploring Crystal Field Theory
Crystal field theory (CFT) is a model that helps us understand the interaction between the electric fields of a crystal or ligands (molecules or ions surrounding a central atom) and the d orbitals of a metal ion. This interaction causes the energy levels of the d orbitals to split into different energy states. In an octahedral complex, for example, the d orbitals split into two groups: the t2g set (dxy, dxz, and dyz) and the eg set (dx2-y2 and dz2), which have higher energy. CFT helps us predict the electronic arrangement in the d orbitals of a metal ion in a complex, the color of the complex, and its magnetic properties. Whether a complex is a strong-field or weak-field one affects whether electrons will pair up or remain unpaired, leading to different magnetic properties.

Understanding CFT is also crucial in explaining the stability of complexes, the nature of the metal-ligand bond, and the electronic transitions that give complexes their unique colors.
The Significance of d Orbitals
The d orbitals are a set of five orbitals, named dxy, dxz, dyz, dx2-y2, and dz2, that have specific shapes and orientations in space. These orbitals play a crucial role in transition metals and their compounds, particularly in the formation of coordination complexes. The shape and energy of d orbitals influence many properties, such as color and magnetism, in transition metal complexes. Electrons in these orbitals can be paired or unpaired, and their distribution in the case of complexes is often influenced by the crystal field splitting energy, which varies depending on the geometry of the complex and the nature of the ligands involved.

For students, understanding the d orbitals and their behavior is key to mastering topics like crystal field theory and electronic configurations in transition metal chemistry.
Analyzing Octahedral Complexes
Octahedral complexes consist of a central metal ion surrounded by six ligands at the corners of an octahedron. This geometry causes the splitting of the d orbitals into two sets with different energy levels, governed by the crystal field theory. The t2g orbitals, due to their lower energy, are filled with electrons before the eg orbitals. In a strong-field octahedral complex, a greater energy difference between the t2g and eg orbitals leads to electron pairing in the t2g orbitals, affecting the magnetic properties of the complex.

The configuration of an octahedral complex can significantly influence its physical and chemical properties, such as absorption of light and magnetism. For example, when transition metals form 2+ ions in an octahedral crystal field, the removal of electrons following the electronic configuration directly affects the resulting electronic configuration of the complex.
Determining Unpaired Electrons
The presence of unpaired electrons is a determining factor for the magnetic properties of a substance. Unpaired electrons contribute to paramagnetism, which makes a complex attracted to magnetic fields. The electronic configuration of an ion, as influenced by the crystal field splitting in octahedral complexes, reveals the number of unpaired electrons. In a strong-field complex, electrons will pair up in the lower energy t2g orbitals first, leaving any additional electrons to occupy the higher energy eg orbitals, potentially as unpaired electrons. By analyzing the electronic configuration, we can predict the number of unpaired electrons, and thus the magnetic behavior of the complex. This concept is crucial in fields like magnetochemistry, where the magnetic properties of substances are studied.

For students, understanding how to determine unpaired electrons is vital for predicting the magnetic properties of coordination compounds and for comprehending the principles of crystal field theory in action.

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Most popular questions from this chapter

Consider the following three complexes: (Complex 1) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{Cl}\) \(\left(\right.\) Complex 2) \(\left[\mathrm{Pd}\left(\mathrm{NH}_{5}\right)_{2}(\mathrm{ONO})_{2}\right]\) (Complex 3) \(\left[\mathrm{V}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+}\). Which of the three complexes can have (a) geometric isomers, (b) linkage isomers, (c) optical isomers, (d) coordinationsphere isomers?

The most important oxides of iron are magnetite, \(\mathrm{Fe}_{3} \mathrm{O}_{4}\), and hematite, \(\mathrm{Fe}_{2} \mathrm{O}_{3}\). (a) What are the oxidation states of iron in these compounds? (b) One of these iron oxides is ferrimagnetic, and the other is antiferromagnetic. Which iron oxide is likely to show which type of magnetism? Explain. Transition-Metal Complexes (Section 23.2)

One of the more famous species in coordination chemistry is the Creutz-Taube complex: It is named for the two scientists who discovered it and initially studied its properties. The central ligand is pyrazine, a planar six-membered ring with nitrogens at opposite sides. (a) How can you account for the fact that the complex, which has only neutral ligands, has an odd overall charge? (b) The metal is in a low-spin configuration in both cases. Assuming octahedral coordination, draw the d-orbital energy-level diagram for each metal. (c) In many experiments the two metal ions appear to be in exactly equivalent states. Can you think of a reason that this might appear to be so, recognizing that electrons move very rapidly compared to nuclei?

(a) Sketch a diagram that shows the definition of the crystal-field splitting energy \((\Delta)\) for an octahedral crystal field. (b) What is the relationship between the magnitude of \(\Delta\) and the energy of the \(d-d\) transition for a \(d^{2}\) complex? (c) Calculate \(\Delta\) in \(\mathrm{kJ} / \mathrm{mol}\) if a \(d^{1}\) complex has an absorption maximum at \(545 \mathrm{~nm}\).

Which periodic trend is responsible for the observation that the maximum oxidation state of the transition-metal elements peaks near groups \(7 \mathrm{~B}\) and \(8 \mathrm{~B}\) ? (a) The number of valence electrons reaches a maximum at group \(8 \mathrm{~B}\). (b) The effective nuclear charge inereases on moving left across each period. (c) The radii of the transition-metal elements reaches a minimum for group \(8 \mathrm{~B}\) and as the size of the atoms decreases it becomes casier to remove electrons.

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