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True or false? The following ligand can act as a bidentate ligand? c1ccc2nc3ccccc3nc2c1

Short Answer

Expert verified
True. The given ligand has two nitrogen atoms with lone pairs, allowing it to act as a bidentate ligand.

Step by step solution

01

1. Interpret the SMILES notation of the ligand

The given SMILES notation is: c1ccc2nc3ccccc3nc2c1. Let's break down the structure: - The lower-case 'c' represents a carbon atom in an aromatic ring. - The numbers (1, 2, 3) are used to indicate the connection between two atoms. - 'n' represents a nitrogen atom So the SMILES notation represents a molecular structure with three fused aromatic rings, with nitrogen atoms in the second and third rings.
02

2. Identify the molecular structure by drawing it

Now, we draw the molecular structure based on the SMILES notation: ![ligand_structure](https://i.imgur.com/y8wkIzi.png) We have drawn the molecular structure. Aromatic carbon atoms are highlighted in gray, while nitrogen atoms are in blue.
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3. Identify possible donor atoms in the ligand

In order to act as a bidentate ligand, there must be two or more lone pair donor atoms within the ligand structure. Nitrogen atoms are common lone pair donor atoms that can bind to metal ions. In our structure, there are two nitrogen atoms.
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4. Determine the ligand's ability to act as a bidentate ligand

Since there are two nitrogen atoms with lone pairs in the ligand structure, it is possible for the ligand to act as a bidentate ligand. Therefore, the answer is True, the given ligand can act as a bidentate ligand.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SMILES Notation
SMILES (Simplified Molecular Input Line Entry System) notation is a way to represent a chemical structure using a string of text. This system is very popular in computational chemistry, as it allows chemists to describe complex molecules concisely. Each atom is represented by its own letter, for example, 'C' for carbon, 'N' for nitrogen.
Lower-case letters, like 'c', specifically denote atoms in aromatic rings. SMILES also uses numbers to indicate the connectivity between atoms. These come into play when atoms are bonded across different parts of the molecule, such as in ring formations or bridged structures.
Reading SMILES notation requires understanding these conventions, which allows for the accurate depiction of molecular structures, like the ligand in question.
Aromatic Rings
Aromatic rings are a class of cyclic, planar structures with delocalized pi-electron systems that provide stability. This delocalization is often represented by a circle within the ring in traditional chemical structures. Aromatic compounds, like benzene, exhibit unique properties such as increased stability and specific bonding patterns.
In the SMILES notation, 'c' represents a carbon atom in such aromatic rings. Aromatic rings are often seen in complex organic molecules, forming the structural backbone that can influence the molecule's reactivity and interaction with other compounds.
The ligand described in the exercise contains three fused aromatic rings, which are indicated by multiple 'c' characters in the SMILES notation. These rings contribute to the planarity and potential reactivity of the ligand.
Nitrogen Atoms
Nitrogen atoms play a crucial role in coordination chemistry and the formation of bidentate ligands. As common donors in ligands, nitrogen atoms can donate lone pairs of electrons to form coordinate bonds with metal ions.
In the SMILES notation and the provided molecular structure, 'n' represents nitrogen atoms. In our ligand example, these nitrogen atoms appear in the second and third aromatic rings. They can use their lone electron pairs to bind with metal ions, making them ideal donor atoms in bidentate ligands.
Understanding the position and availability of nitrogen atoms is vital in predicting the behavior and functionality of ligands in coordination chemistry.
Coordination Chemistry
Coordination chemistry revolves around the complex formation between a central atom (often a transition metal) and surrounding ligands. Ligands are ions or molecules capable of donating pairs of electrons to the metal atom. This donation forms a coordinate covalent bond.
Bidentate ligands, like the one in the exercise, have two atoms that can donate electron pairs. These ligands form more stable complexes due to their ability to "bite" the metal atom at two points, effectively forming a chelate.
The nitrogen atoms in our ligand act as these two donor atoms, fulfilling the criteria for bidentate ligand formation. Coordination complexes play vital roles in biology and industry, serving functions from oxygen transport in hemoglobin to catalysis in chemical reactions. Understanding the interaction of ligands helps in designing and applying these complexes effectively.

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Most popular questions from this chapter

Crystals of hydrated chromium(III) chloride are green, have an empirical formula of \(\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}\), and are highly soluble, (a) Write the complex ion that exists in this compound. (b) If the complex is treated with excess \(\mathrm{AgNO}_{3}(a q)\), how many moles of \(\mathrm{AgCl}\) will precipitate per mole of \(\mathrm{CrCl}_{3} * 6 \mathrm{H}_{2} \mathrm{O}\) dissolved in solution? (c) Crystals of anhydreus chromium(III) chloride are violet and insoluble in aqueous solution. The coordination geometry of chromium in these crystals is octahedral as is almost always the case for \(\mathrm{Cr}^{3+}\). How can this be the case if the ratio of \(\mathrm{Cr}\) to \(\mathrm{Cl}\) is not 1:6?

The total concentration of \(\mathrm{Ca}^{2+}\) and \(\mathrm{Mg}^{2+}\) in a sample of hard water was determined by titrating a \(0.100\) - L sample of the water with a solution of EDTA \({ }^{4-}\). The EDTA \({ }^{4-}\) chelates the two cations: $$ \begin{aligned} \mathrm{Mg}^{2+}+[\mathrm{EDTA}]^{4-} & \longrightarrow[\mathrm{Mg}(\mathrm{EDTA})]^{2-} \\ \mathrm{Ca}^{2+}+\left[\mathrm{EDTA}^{4-}\right.& \longrightarrow[\mathrm{Ca}(\mathrm{EDTA})]^{2-} \end{aligned} $$ It requires \(31.5 \mathrm{~mL}\) of \(0.0104 \mathrm{M}[\mathrm{EDTA}]^{4-}\) solution to reach the end point in the titration. A second \(0.100-L\) sample was then treated with sulfate ion to precipitate \(\mathrm{Ca}^{2+}\) as calcium sulfate. The \(\mathrm{Mg}^{2+}\) was then titrated with \(18.7 \mathrm{~mL}\) of \(0.0104 \mathrm{M}\) [EDTA] ]- Calculate the concentrations of \(\mathrm{Mg}^{2+}\) and \(\mathrm{Ca}^{2+}\) in the hard water in mg/I.

Which periodic trend is responsible for the observation that the maximum oxidation state of the transition-metal elements peaks near groups \(7 \mathrm{~B}\) and \(8 \mathrm{~B}\) ? (a) The number of valence electrons reaches a maximum at group \(8 \mathrm{~B}\). (b) The effective nuclear charge inereases on moving left across each period. (c) The radii of the transition-metal elements reaches a minimum for group \(8 \mathrm{~B}\) and as the size of the atoms decreases it becomes casier to remove electrons.

Which type of substance is attracted by a magnetic field, a diamagnetic substance or a paramagnetic substance?

As shown in Figure 23.26, the \(d-d\) transition of \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) produces an absorption maximum at a wavelength of about \(500 \mathrm{~nm}\). (a) What is the magnitude of \(\Delta\) for \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) in \(\mathrm{kJ} / \mathrm{mol}\) ? (b) How would the magnitude of \(\Delta\) change if the \(\mathrm{H}_{2} \mathrm{O}\) ligands in \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) were replaced with \(\mathrm{NH}_{2}\) ligands?

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