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Write a balanced equation for each of the following reactions: (a) Burning magnesium metal in a carbon dioxide atmosphere reduces the \(\mathrm{CO}_{2}\) to carbon. (b) In photosynthesis, solar energy is used to produce glucose \(\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)\) and \(\mathrm{O}_{2}\) from carbon dioxide and water. (c) When carbonate salts dissolve in water, they produce basic solutions.

Short Answer

Expert verified
(a) Mg + CO₂ → 2MgO + C (b) 6CO₂ + 12H₂O → C₆H₁₂O₆ + 6O₂ (c) Na₂CO₃ + H₂O → 2NaOH + H₂CO₃

Step by step solution

01

Write the unbalanced equation

To write an unbalanced equation, we list the reactants and products involved in the reaction. For this reaction, we have magnesium metal (Mg) reacting with carbon dioxide (CO₂) to form magnesium oxide (MgO) and carbon (C). Unbalanced equation: Mg + CO₂ → MgO + C
02

Balance the equation

To balance the equation, we compare the number of atoms of each element on both sides and adjust the coefficients accordingly. Here, we have one oxygen on the product side and two oxygens on the reactant side, so we need to add a coefficient of 2 in front of MgO. Balanced equation: Mg + CO₂ → 2MgO + C #b) Photosynthesis reaction#
03

Write the unbalanced equation

In the photosynthesis reaction, carbon dioxide (CO₂) reacts with water (H₂O) to form glucose (C₆H₁₂O₆) and oxygen gas (O₂). Unbalanced equation: CO₂ + H₂O → C₆H₁₂O₆ + O₂
04

Balance the equation

To balance the equation, we adjust the coefficients of each part accordingly to have the same number of atoms of each element on both sides. Balanced equation: 6CO₂ + 12H₂O → C₆H₁₂O₆ + 6O₂ #c) Carbonate salts dissolving in water#
05

Write the unbalanced equation

When carbonate salts (such as sodium carbonate, Na₂CO₃) dissolve in water (H₂O), they produce a basic solution (such as sodium hydroxide, NaOH) and carbonic acid (H₂CO₃). Unbalanced equation: Na₂CO₃ + H₂O → NaOH + H₂CO₃
06

Balance the equation

To balance the equation, we adjust the coefficients of each part accordingly. Balanced equation: Na₂CO₃ + H₂O → 2NaOH + H₂CO₃

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Most popular questions from this chapter

Write a balanced equation for each of the following reactions: (a) preparation of white phosphorus from calcium phosphate, (b) hydrolysis of \(\mathrm{PBr}_{3}\), (c) reduction of \(\mathrm{PBr}_{3}\) to \(\mathrm{P}_{4}\) in the gas phase, using \(\mathrm{H}_{2}\).

Write the Lewis structure for each of the following species, and indicate the structure of each: (a) \(\mathrm{SeO}_{3}{ }^{2-} ;\) (b) \(\mathrm{S}_{2} \mathrm{Cl}_{2}\); (c) chlorosulfonic acid, \(\mathrm{HSO}_{3} \mathrm{Cl}\) (chlorine is bonded to sulfur).

The standard heats of formation of \(\mathrm{H}_{2} \mathrm{O}(g), \mathrm{H}_{2} \mathrm{~S}(g), \mathrm{H}_{2} \mathrm{Se}(g)\), and \(\mathrm{H}_{2} \mathrm{Te}(g)\) are \(-241.8,-20.17,+29.7\), and \(+99.6 \mathrm{~kJ} /\) mol, respectively. The enthalpies necessary to convert the elements in their standard states to one mole of gaseous atoms are \(248,277,227\), and \(197 \mathrm{~kJ} / \mathrm{mol}\) of atoms for \(\mathrm{O}, \mathrm{S}, \mathrm{Se}\), and Te, respectively. The enthalpy for dissociation of \(\mathrm{H}_{2}\) is \(436 \mathrm{~kJ} / \mathrm{mol}\). Calculate the average \(\mathrm{H}-\mathrm{O}, \mathrm{H}-\mathrm{S}, \mathrm{H}-\mathrm{Se}\), and \(\mathrm{H}\) - Te bond enthalpies, and comment on their trend.

Select the member of group \(4 \mathrm{~A}\) that best fits each description: (a) forms chains to the greatest extent, (b) forms the most basic oxide, (c) is a metalloid that can form \(2+\) ions.

Write the Lewis structure for each of the following species, describe its geometry, and indicate the oxidation state of the nitrogen: (a) \(\mathrm{HNO}_{2}\), (b) \(\mathrm{N}_{3}^{-}\), (c) \(\mathrm{N}_{2} \mathrm{H}_{5}^{+}\), (d) \(\mathrm{NO}_{3}^{-}\).

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