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A friend tells you that the "neon" in neon signs is a compound of neon and aluminum. Can your friend be correct? Explain.

Short Answer

Expert verified
Your friend's statement is incorrect. The "neon" in neon signs is not a compound of neon and aluminum because neon is a noble gas with a full valence electron shell, making it unreactive and unlikely to form compounds with other elements, such as aluminum.

Step by step solution

01

Understand Neon and Compounds

First, let's understand the nature of neon. Neon is a noble gas, which means it has a full electron shell and rarely forms chemical bonds. Noble gases are very stable and unreactive due to their full electron shell, making it difficult for them to form compounds with other elements. Now let's understand compounds. A compound is a substance that forms when two or more elements chemically combine, resulting in a new substance with different properties from the original elements. For a compound to form, there should be a chemical reaction between the elements.
02

Analyze the possibility of neon forming a compound with aluminum

Since neon is a noble gas and has a full valence shell, it tends not to participate in chemical reactions to form compounds. Aluminum, on the other hand, is a reactive metal with a partially-filled electron valence shell that readily engages in chemical reactions. Considering the nature of neon and aluminum, it is unlikely that they would form a compound, as neon's unreactive nature would not allow it to form a chemical bond with aluminum.
03

Conclusion

Based on our understanding of neon and its unreactive nature, we can conclude that your friend's statement is incorrect. The "neon" in neon signs is not a compound of neon and aluminum, as neon is a noble gas that rarely forms compounds with other elements due to its full valence electron shell.

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Most popular questions from this chapter

Write a balanced equation for each of the following reactions. (You may have to guess at one or more of the reaction products, but you should be able to make a reasonable guess, based on your study of this chapter.) (a) Hydrogen selenide can be prepared by reaction of an aqueous acid solution on aluminum selenide. (b) Sodium thiosulfate is used to remove excess \(\mathrm{Cl}_{2}\) from chlorine-bleached fabrics. The thiosulfate ion forms \(\mathrm{SO}_{4}{ }^{2-}\) and elemental sulfur, while \(\mathrm{Cl}_{2}\) is reduced to \(\mathrm{Cl}^{-}\). Nitrogen and the Other Group 5A Elements (Sections 22.7 and 22.8)

Write the Lewis structure for each of the following species, describe its geometry, and indicate the oxidation state of the nitrogen: (a) \(\mathrm{NH}_{4}^{+}\), (b) \(\mathrm{NO}_{2}^{-}\), (c) \(\mathrm{N}_{2} \mathrm{O}\), (d) \(\mathrm{NO}_{2}\).

Write the chemical formula for each of the following compounds, and indicate the oxidation state of nitrogen in each: (a) nitric oxide, (b) hydrazine, (c) potassium cyanide, (d) sodium nitrite, (e) ammonium chloride, (f) lithium nitride.

One method proposed for removing \(\mathrm{SO}_{2}\) from the flue gases of power plants involves reaction with aqueous \(\mathrm{H}_{2} \mathrm{~S}\). Elemental sulfur is the product. (a) Write a balanced chemical equation for the reaction. (b) What volume of \(\mathrm{H}_{2} \mathrm{~S}\) at \(27^{\circ} \mathrm{C}\) and 760 torr would be required to remove the \(\mathrm{SO}_{2}\) formed by burning \(2.0\) tons of coal containing \(3.5 \% \mathrm{~S}\) by mass? (c) What mass of elemental sulfur is produced? Assume that all reactions are \(100 \%\) efficient.

Give a reason why hydrogen might be placed along with the group lA elements of the periodic table.

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