A rock contains \(0.257 \mathrm{mg}\) of lead-206 for every milligram of
uranium-238. The half-life for the decay of uranium-238 to lead-206 is \(4.5
\times 10^{5} \mathrm{yr}\). How old is the rock?
SOLUTION
Analyze We are told that a rock sample has a certain amount of lead206 for
every unit mass of uranium-238 and asked to estimate the age of the rock.
Plan Lead-206 is the product of the radioactive decay of uranium-238. We will
assume that the only source of lead-206 in the rock is from the decay of
uranium-238, with a known half-life. To apply firstorder kinetics expressions
(Equations \(21.19\) and 21.20) to calculate the time elapsed since the rock was
formed, we first need to calculate how much initial uranium-238 there was for
every \(1 \mathrm{mg}\) that remains today.
Solve Let's assume that the rock currently contains \(1.000 \mathrm{mg}\) of
uranium-238 and therefore \(0.257 \mathrm{mg}\) of lead-206. The amount of
uranium-238 in the rock when it was first formed therefore equals \(1.000
\mathrm{mg}\) plus the quantity that has decayed to lead-206. Because the mass
of lead atoms is not the same as the mass of uranium atoms, we cannot just add
\(1.000 \mathrm{mg}\) and \(0.257 \mathrm{mg}\). We have to multiply the present
mass of lead-206 \((0.257 \mathrm{mg})\) by the ratio of the mass number of
uranium to that of lead, into which it has decayed. Therefore, the original
mass of \({ }_{92}^{239} \mathrm{U}\) was
$$
\text { Original } \begin{aligned}
{ }_{98}^{238} \mathrm{U} &=1.000 \mathrm{mg}+\frac{238}{206}(0.257
\mathrm{mg}) \\
&=1.297 \mathrm{mg}
\end{aligned}
$$
Using Equation 21.20, we can calculate the decay constant for the process from
its half-life:
$$
k=\frac{0.693}{4.5 \times 10^{9} \mathrm{yr}}=1.5 \times 10^{-10}
\mathrm{yr}^{-1}
$$
Rearranging Equation \(21.19\) to solve for time, \(t\), and substituting known
quantities gives
$$
t=-\frac{1}{k} \ln \frac{N_{t}}{N_{0}}=-\frac{1}{1.5 \times 10^{-10}
\mathrm{yr}^{-1}} \ln \frac{1.000}{1.297}=1.7 \times 10^{9} \mathrm{yr}
$$
Comment To check this result, you could use the fact that the decay of
uranium-235 to lead-207 has a half-life of \(7 \times 10^{8} \mathrm{yr}\) and
measure the relative amounts of uranium-235 and lead-207 in the rock.