Chapter 20: Problem 95
Metallic gold is collected from below the anode when crude copper metal is refined by electrolysis. Explain this behavior.
Chapter 20: Problem 95
Metallic gold is collected from below the anode when crude copper metal is refined by electrolysis. Explain this behavior.
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Get started for freeMagnesium is obtained by electrolysis of molten \(\mathrm{MgCl}_{2}\). (a) Why is an aqueous solution of \(\mathrm{MgC}_{2}\) not used in the electrolysis? (b) Several cells are connected in parallel by very large copper bars that convey current to the cells. Assuming that the cells are \(96 \%\) efficient in producing the desired products in electrolysis, what mass of \(\mathrm{Mg}\) is formed by passing a current of \(97,000 \mathrm{~A}\) for a period of \(24 \mathrm{~h}\) ?
For a spontaneous reaction \(\mathrm{A}(a q)+\mathrm{B}(a q) \longrightarrow \mathrm{A}^{-}(a q)+\) \(\mathrm{B}^{+}(\mathrm{at})\), answer the following questions: (a) If you made a voltaic cell out of this reaction, what halfreaction would be occurring at the cathode, and what halfreaction would be occurring at the anode? (b) Which half-reaction from (a) is higher in potential energy? (c) What is the sign of \(E_{\text {cell? }}^{\text {? }}\) [Section 20.3]
In the Brensted-Lowry concept of acids and bases, acid-base reactions are viewed as proton-transfer reactions. The stronger the acid, the weaker is its conjugate base. If we were to think of redox reactions in a similar way, what particle would be analogous to the proton? Would strong oxidizing agents be analogous to strong acids or strong bases? [Sections \(20.1\) and \(20.2]\)
(a) A voltaic cell is constructed with all reactants and products in their standard states. Will the concentration of the reactants increase, decrease, or remain the same as the cell operates? (b) What happens to the emf of a cell if the concentrations of the products are increased?
The cell in Figure \(20.9\) could be used to provide a measure of the \(\mathrm{pH}\) in the cathode half-cell. Calculate the \(\mathrm{pH}\) of the cathode half-cell solution if the cell emf at \(298 \mathrm{~K}\) is measured to be \(+0.684 \mathrm{~V}\) when \(\left[\mathrm{Zn}^{2+}\right]=0.30 \mathrm{M}\) and \(P_{\mathrm{H}_{2}}=0.90 \mathrm{~atm}\).
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