A voltaic cell is constructed that uses the following half-cell reactions:
$$
\begin{aligned}
\mathrm{Cu}^{*}(a q)+\mathrm{e}^{-} & \longrightarrow \mathrm{Cu}(s) \\
\mathrm{l}_{2}(s)+2 \mathrm{c}^{-} & \longrightarrow 2 \mathrm{I}^{-}(a q)
\end{aligned}
$$
The cell is operated at \(298 \mathrm{~K}\) with
\(\left[\mathrm{Cu}^{+}\right]=0.25 \mathrm{M}\) and \(\left[1^{-}\right]=3.5
\mathrm{M}\). (a) Determine \(E\) for the cell at these concentrations. (b) Which
electrode is the anode of the cell? (c) Is the answer to part (b) the same as
it would be if the cell were operated under standard conditions? (d) If
\(\left[\mathrm{Cu}^{+}\right]\)were equal to \(0.15 \mathrm{M}\), at what
concentration of I \({ }^{-}\)would the cell have zero potential?