Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In the Brensted-Lowry concept of acids and bases, acid-base reactions are viewed as proton-transfer reactions. The stronger the acid, the weaker is its conjugate base. If we were to think of redox reactions in a similar way, what particle would be analogous to the proton? Would strong oxidizing agents be analogous to strong acids or strong bases? [Sections \(20.1\) and \(20.2]\)

Short Answer

Expert verified
In redox reactions, the particle analogous to the proton is the electron. Strong oxidizing agents, which accept electrons, are analogous to strong bases in the Bronsted-Lowry concept, as they both involve the acceptance of particles (electrons or protons).

Step by step solution

01

Understand the Bronsted-Lowry concept of acids and bases

The Bronsted-Lowry concept of acids and bases states that an acid can donate a proton (H+), while a base accepts a proton. Consequently, acid-base reactions can be seen as proton-transfer reactions. The stronger an acid is, the weaker its conjugate base becomes.
02

Identify the particle analogous to the proton in redox reactions

In redox (reduction-oxidation) reactions, the key particle involved is the electron. Oxidation occurs when a species loses electrons, while reduction takes place when a species gains electrons. Therefore, the particle analogous to the proton in these reactions is the electron.
03

Understand the analogy between redox reactions and acid-base reactions

To determine if strong oxidizing agents are more similar to strong acids or strong bases, we need to understand how oxidizing and reducing agents work: - Oxidizing agents accept electrons, causing reduction. - Reducing agents donate electrons, causing oxidation. Now, we can make a comparison with the Bronsted-Lowry concept of acids and bases: - Acids donate protons. - Bases accept protons.
04

Determine if strong oxidizing agents are analogous to strong acids or strong bases

Since strong oxidizing agents accept electrons (similarly to how bases accept protons), they are analogous to strong bases in the Bronsted-Lowry concept.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redox Reactions
Redox reactions, short for reduction-oxidation reactions, are chemical processes where electrons are transferred between two substances. These reactions can be broken down into two parts: oxidation, where a substance loses electrons, and reduction, where a substance gains electrons. This transfer of electrons is fundamental to redox reactions, just as the transfer of protons is critical in the Bronsted-Lowry acid-base theory. When a species undergoes oxidation, it becomes more positive, and when it undergoes reduction, it becomes more negative. Redox reactions are all around us. They power batteries, fuel cellular respiration in our bodies, and even occur when metals rust. Understanding these reactions involves knowing which components in the reaction are oxidized (electron donors) and which are reduced (electron acceptors). In this way, redox reactions play a crucial role in various chemical and biological processes.
Proton Transfer
The concept of proton transfer is central to the Bronsted-Lowry acid-base theory. In this theory, acids are defined as proton donors, while bases are proton acceptors. This means that during an acid-base reaction, a proton (H+) is transferred from the acid to the base. The strength of an acid is often determined by its ability to donate protons, while a strong base is adept at accepting them.
  • Acids donate protons.
  • Bases accept protons.
This balance within a reaction determines the conjugate pairs formed, where every acid has a conjugate base, and vice versa. When a strong acid donates its proton, it forms a weak conjugate base. Conversely, when a strong base accepts a proton, it forms a weak conjugate acid. By examining proton transfers, chemists can predict how readily a reaction will proceed and how the resulting compounds will behave. This understanding is foundational for many chemical applications, from pharmaceuticals to industrial chemicals.
Oxidizing Agents
Oxidizing agents play a vital role in redox reactions, acting as electron acceptors. They "take" electrons from other substances, thus being reduced themselves. In a way, they are the catalysts for oxidation in other substances. This mirrors the role of bases in acid-base reactions, where bases accept protons. Oxidizing agents are crucial in various applications, especially in processes where electron transfer is necessary. Some common examples include hydrogen peroxide, potassium dichromate, and chlorine. Just as acids' strength in the Bronsted-Lowry theory is related to their ability to donate protons, the strength of an oxidizing agent is determined by its ability to accept electrons.
  • Strong oxidizing agents accept electrons easily, similar to strong bases accepting protons.
  • They cause the oxidation of other substances, thus facilitating redox reactions.
Understanding oxidizing agents is essential for mastering redox chemistry, and it helps to see the parallels in their function to familiar concepts within acid-base reactions, providing a comprehensive view of chemical processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Using the standard reduction potentials listed in Appendix E, calculate the equilibrium constant for each of the following reactions at \(298 \mathrm{~K}\) - (a) \(\mathrm{Cu}(s)+2 \mathrm{Ag}^{+}(a q) \longrightarrow \mathrm{Cu}^{2}+(a q)+2 \mathrm{Ag}(s)\) (b) \(3 \mathrm{Ce}^{4+}(a q)+\mathrm{Bi}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 3 \mathrm{Ce}^{3+}(a q)+\) \(\mathrm{BiO}^{+}(a q)+2 \mathrm{H}^{+}(a q)\) (c) \(\mathrm{N}_{2} \mathrm{H}_{5}^{+}(a q)+4 \mathrm{Fe}(\mathrm{CN})_{6}^{3-}(a q) \longrightarrow \mathrm{N}_{2}(\mathrm{~g})+\) \(5 \mathrm{H}^{+}(a q)+4 \mathrm{Fe}(\mathrm{CN})_{6}^{4}(a q)\)

In a galvanic cell the cathode is an \(\mathrm{Ag}^{+}(1.00 \mathrm{M}) / \mathrm{Ag}^{(s)}\) halfcell. The anode is a standard hydrogen electrode immersed in a buffer solution containing \(0.10 \mathrm{M}\) benzoic acid ( \(\left.\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{COOH}\right)\) and \(0.050 \mathrm{M}\) sodium benzoate \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COON} \mathrm{Na}^{+}\right)\). The measured cell voltage is \(1.030 \mathrm{~V}\). What is the \(\mathrm{p} K_{4}\) of benzoic acid?

An iron object is plated with a coating of cobalt to protect against corrosion. Does the cobalt protect iron by cathodic protection? Explain.

The hydrogen-oxygen fuel cell has a standard emf of \(1.23 \mathrm{~V}\). What advantages and disadvantages are there to using this device as a source of power compared to a \(1.55\) - \(\mathrm{V}\) alkaline battery?

A student designs an ammeter (a device that measures electrical current) that is based on the electrolysis of water into hydrogen and oxygen gases. When electrical current of unknown magnitude is run through the device for \(2.00 \mathrm{~min}, 12.3 \mathrm{~mL}\) of water-saturated \(\mathrm{H}_{2}(g)\) is collected. The temperature of the system is \(25.5^{\circ} \mathrm{C}\), and the atmospheric pressure is 768 torr. What is the magnitude of the current in amperes?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free