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A student who is in a great hurry to finish his laboratory work decides that his qualitative analysis unknown contains a metal ion from group 4 of Figure 17.23. He therefore tests his sample directly with \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\) skipping earlier tests for the metal ions in groups 1,2 , and 3. He observes a precipitate and concludes that a metal ion from group 4 is indeed present. Why is this possibly an erroneots conclusion?

Short Answer

Expert verified
The student's approach of directly testing the sample with \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\) and skipping earlier tests for metal ions in groups 1, 2, and 3 may lead to an erroneous conclusion, as the precipitate observed can also be formed due to the presence of metal ions from groups 1, 2, and 3 interacting with \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\). To obtain an accurate conclusion, it is necessary to perform appropriate tests for metal ions in groups 1 to 3 before testing for the presence of group 4 metal ions.

Step by step solution

01

Consider group 4 metal ions

Group 4 metal ions will react with \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\) and typically form precipitation. So if only group 4 metal ions were present in the sample, the student's approach might have been correct.
02

Check for possible reactions with other groups

In order to determine whether the student's approach may lead to an erroneous conclusion, we need to analyze the possibility of the precipitate formed due to the presence of metal ions from groups 1, 2, and 3 when reacting with \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\). If any of these groups produced a precipitate with \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\), the observation would not conclusively prove the presence of a group 4 metal ion in the sample.
03

Analyze the formation of precipitates with other metal ions

When analyzing the reactivity of other group metal ions with \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\), it is found that certain metal ions from groups 1, 2, and 3 may indeed also form precipitates. This means that skipping the earlier tests for these metal ions can lead to an ambiguous and possibly incorrect conclusion regarding the presence of a group 4 metal ion in the sample.
04

Identify the error in the student's approach

The student's approach of skipping earlier tests for metal ions from groups 1, 2, and 3 and directly testing the sample with \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\) can lead to an erroneous conclusion, as precipitation could also be due to the presence of other group metal ions. Therefore, it is necessary to perform the appropriate tests for the metal ions in groups 1 to 3 before testing for the presence of group 4 metal ions to obtain an accurate conclusion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Precipitation Reactions
Precipitation reactions are a cornerstone of analytical chemistry, serving as the basis for many tests used to detect specific ions in a solution. In essence, when two soluble reactants combine and form an insoluble product, we observe what is known as a precipitation reaction. The solid that emerges from the liquid mixture is the precipitate.

For instance, when a solution containing group 4 metal ions is mixed with a phosphate source such as \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\), a precipitation reaction can occur, resulting in the formation of metal phosphate salts that are not soluble in water.
  • These reactions are used to identify the presence of specific ions in a sample.
  • They rely on the solubility rules to predict which compounds form a precipitate.
  • A complete ionic equation provides a clearer picture of the ions involved in the reaction.
An understanding of the conditions under which different ions react is imperative. Without this, as the textbook exercise illustrates, a student might incorrectly identify the presence of an ion, such as a group 4 metal ion, if they disregard earlier groups which may also form precipitates with the same reagents.
Group 4 Metal Ions
Group 4 metal ions include ions such as Zr4+ and Hf4+, which are known for their reactive properties in qualitative analysis. These metal ions have a tendency to form precipitates when reacted with certain reagents, like phosphate ions, due to their specific charge and ionic radii.

  • Reactivity with certain anions like phosphate can lead to the formation of insoluble salts.
  • Understanding the chemical behavior of group 4 ions is crucial for proper identification.
  • Identification can often require a series of selective and sequential reactions, eliminating other possibilities.
If a student incorrectly jumps to the conclusion that the presence of a precipitate confirms a group 4 metal ion without considering other potential precipitating agents, they might skip essential analytical steps. This is because not only group 4 metal ions but also ions from groups 1, 2, and 3 could form similar precipitates under certain conditions, thus leading to a misidentification.
Analytical Chemistry
Analytical chemistry is a field of chemistry that focuses on the separation, identification, and quantification of chemical components in natural and artificial materials. The key objectives in analytical chemistry include developing accurate, sensitive, and precise methods of analysis.

  • It includes a wide array of techniques and instruments used to determine the composition of samples.
  • It requires a systematic approach to ensure that tests yield reliable and reproducible results.
  • Knowledge of chemical reactivity and instrumentation is fundamental.
Each analytical procedure, such as the one in our textbook exercise, demands careful planning and execution. For example, before declaring the presence of a specific ion, a chemist needs to perform tests that rule out other candidates—a practice known as selective and sequential testing. The student's error, as highlighted in the textbook solution, highlights a critical aspect of analytical chemistry: haste and assumptions can lead to incorrect conclusions, underscoring the importance of meticulous, stepwise investigation.

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Most popular questions from this chapter

\mathrm{~A}\( biochemist needs \)750 \mathrm{~mL}\( of an acetic acid-sodium acetate buffer with pH 4.50. Solid sodium acetate ( \)\left.\mathrm{CH}_{3} \mathrm{COONa}\right)\( and glacial acetic acid \)\left(\mathrm{CH}_{3} \mathrm{COOH}\right)\( are available. Glacial acetic acid is \)99 \% \mathrm{CH}_{3} \mathrm{COOH}\( by mass and has a density of \)1.05 \mathrm{~g} / \mathrm{ml}\(. If the buffer is to be \)0.15 \mathrm{M}\( in \)\mathrm{CH}_{3} \mathrm{COOH}\(, how many grams of \)\mathrm{CH}_{4} \mathrm{COONa}$ and how many milliliters of glacial acetic acid must be used?

A solution contains three anions with the following concentrations: \(0.20 \mathrm{MCrO}_{4}^{2-}, 0.10 \mathrm{MCO}_{3}^{2-}\), and \(0.010 \mathrm{M} \mathrm{Cl}^{-}\). If a dilute \(\mathrm{AgNO}_{3}\) solution is slowly added to the solution, what is the first compound to precipitate: \(\mathrm{Ag}_{2} \mathrm{CrO}_{4}\left(K_{3 p}=1.2 \times 10^{-12}\right)\). \(\mathrm{Ag}_{2} \mathrm{CO}_{3}\left(K_{\mathrm{p}}=8.1 \times 10^{-12}\right)\), or \(\mathrm{AgCl}\left(K_{\text {sp }}=1.8 \times 10^{-10}\right)\) ?

Compare the titration of a strong, monoprotic acid with a strong base to the titration of a weak, monoprotic acid with a strong base. Assume the strong and weak acid solutions initially have the same concentrations. Indicate whether the following statements are true or false. (a) More base is required to reach the equivalence point for the strong acid than the weak acid. (b) The pH at the beginning of the titration is lower for the weak acid than the strong acid. (c) The \(\mathrm{pH}\) at the equivalence point is 7 no matter which acid is titrated.

A buffer contains a weak acid, HA, and its conjugate base. The weak acid has a \(\mathrm{p} K_{a}\) of \(4.5\), and the buffier has a \(\mathrm{pH}\) of 4.3. Without doing a calculation, state which of these possibilities are correct. (a) \([\mathrm{HA}]=\left[\mathrm{A}^{-}\right]\), (b) \([\mathrm{HA}]>\left[\mathrm{A}^{-}\right]\), or (c) \([\mathrm{HA}]<\left[\mathrm{A}^{-}\right]\). [Section 17.2]

Baking soda (sodium bicarbonate, \(\mathrm{NaHCO}_{3}\) ) reacts with acids in foods to form carbonic acid \(\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right)\), which in turn decomposes to water and carbon dioxide gas. In a cake batter, the \(\mathrm{CO}_{2}(\mathrm{~g})\) forms bubbles and causes the cake to rise. (a) A rule of thumb in baking is that \(1 / 2\) teaspoon of baking soda is neutralized by one cup of sour milk. The acid component in sour milk is lactic acid, \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}\). Write the chemical equation for this neutralization reaction. (b) The density of baking soda is \(2.16 \mathrm{~g} / \mathrm{cm}^{3}\). Calculate the concentration of lactic acid in one cup of sour milk (assuming the rule of thumb applies), in units of \(\mathrm{mol} / \mathrm{L}\). (One cup \(=236.6 \mathrm{~mL}=48\) teaspoons). (c) If 1/2 teaspoon of baking soda is indeed completely neutralized by the lactic acid in sour milk, calculate the volume of carbon dioxide gas that would be produced at 1 atm pressure, in an oven set to \(350^{\circ} \mathrm{F}\).

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