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Hemoglobin plays a part in a series of equilibria involving protonation- deprotonation and oxygenation-deoxygenation. The overall reaction is approximately as follows: HbH+(aq)+O2(aq)HbO2(aq)+H+(aq) where Hb stands for hemoglobin and HbO2 for oxyhemoglobin. (a) The concentration of O2 is higher in the lungs and lower in the tissues. What effect does high [O2] have on the position of this equilibrium? (b) The normal pH of blood is 7.4. Is the blood acidic, basic, or neutral? (c) If the blood pH is lowered by the presence of large amounts of acidic metabolism products, a condition known as acidosis results. What effect does lowering blood pH have on the ability of hemoglobin to transport O2 ?

Short Answer

Expert verified
(a) A higher [O2] in the lungs shifts the equilibrium to the right, favoring the formation of oxyhemoglobin (HbO2). (b) The normal blood pH of 7.4 indicates that blood is slightly basic. (c) Lowering blood pH due to acidosis increases [H+] concentration, shifting the equilibrium to the left, reducing the formation of HbO2, and decreasing hemoglobin's ability to transport oxygen to the tissues.

Step by step solution

01

(a) Effect of Oxygen Concentration on Equilibrium.

The given reaction is: HbH+(aq)+O2(aq)HbO2(aq)+H+(aq) In the lungs, the concentration of oxygen [O2] is higher. According to Le Chatelier's Principle, if the concentration of a reactant is increased, the equilibrium will shift towards the product side to minimize the change. Therefore, a higher [O2] would shift the equilibrium to the right, favoring the formation of oxyhemoglobin (HbO2).
02

(b) Normal pH of Blood

Blood pH is a measure of the acidity or basicity of blood. A pH value of 7 is considered neutral, while values less than 7 are acidic, and values greater than 7 are basic. Since the normal pH of blood is given as 7.4, the blood is slightly basic.
03

(c) Effect of Lower Blood pH on Oxygen Transport

Acidosis is a condition in which the blood pH is lowered due to the presence of large amounts of acidic metabolic products. Lowering the blood pH means an increase in [H+] concentration. Referring to the given reaction: HbH+(aq)+O2(aq)HbO2(aq)+H+(aq) According to Le Chatelier's Principle, when the concentration of a product (H+ in this case) is increased, the equilibrium will shift towards the reactant side to minimize the change. Therefore, lowering the blood pH, the equilibrium would shift to the left, reducing the formation of oxyhemoglobin (HbO2) and decreasing the ability of hemoglobin to transport oxygen fo the tissues.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Le Chatelier's Principle
Le Chatelier's Principle is a fundamental concept in chemistry that explains how equilibrium systems respond to changes in reactant or product concentrations. It states that if a change is imposed on a system at equilibrium, the system will adjust itself in such a way as to counteract that change and restore a new equilibrium state.
This principle is particularly relevant in biological systems like the hemoglobin reaction. Hemoglobin (Hb) binds with oxygen to form oxyhemoglobin (HbO2), as described by the equation:
  • HbH+(aq)+O2(aq)HbO2(aq)+H+(aq)
In areas where oxygen concentration is high, such as in the lungs, Le Chatelier's Principle predicts that the equilibrium will shift to the right, favoring the production of more oxyhemoglobin. Conversely, in tissues where oxygen concentration is lower, the equilibrium tends to shift to the left, releasing oxygen from hemoglobin, which is crucial for oxygen delivery to tissues.
blood pH
Blood pH is an important indicator of the blood's acidity or alkalinity. A pH of 7 is considered neutral. If the pH is below 7, the blood is acidic; above 7, it is basic. Human blood typically has a pH of about 7.4, which classifies it as slightly basic.
Maintaining this pH is vital because even small changes can affect biological function. Various systems in the body work together to keep blood pH within a narrow range. This includes buffering systems, respiratory mechanisms, and renal function.
Disruptions in these systems can lead to conditions like acidosis, where the blood becomes more acidic. This can occur due to increased [H+] from metabolic by-products, which affects hemoglobin's efficiency in transporting oxygen. Understanding blood pH is critical when studying oxygen transport because hemoglobin's ability to bind and release oxygen is pH dependent.
oxygen transport
Oxygen transport in the human body is primarily facilitated by hemoglobin in the red blood cells. Hemoglobin's ability to bind or release oxygen changes depending on the surrounding environment, particularly pH and oxygen concentration.
In the lungs, where oxygen concentration is high, hemoglobin binds oxygen readily, forming oxyhemoglobin. This forms as a result of an equilibrium shift towards the right side of the reaction equation:HbH+(aq)+O2(aq)HbO2(aq)+H+(aq).
However, in tissues requiring oxygen, the concentration of oxygen is lower, and factors like lower pH due to carbon dioxide production promote the release of oxygen. This process is aided by the previously discussed blood pH and ensures that tissues receive adequate oxygen for metabolic needs. Efficient oxygen transport is crucial for supporting cellular respiration and energy production throughout the body.

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Most popular questions from this chapter

The amino acid glycine (H2 NCH2COOH) can participate in the following equilibria in water: H2 NCH2COOH+H2O H2 NCH2COO+H3O+Ka=4.3×103 H2 NCH2COOH+H2O +H3 NCH2COOH+OHKb=6.0×105 (a) Use the values of Ka and Kb to estimate the equilibrium constant for the intramolecular proton transfer to form a zwitterion: H2 NCH2COOH+H3 NCH2COO

Many moderately large organic molecules containing basic nitrogen atoms are not very soluble in water as neutral molecules, but they are frequently much more soluble as their acid salts. Assuming that pH in the stomach is 2.5, indicate whether each of the following compounds would be present in the stomach as the neutral base or in the protonated form: nicotine, Kb=7×107; caffeine, Kb=4×1014; strychnine, Kb=1×106; quinine, Kb=1.1×106.

(a) Give the conjugate base of the following Bronsted-Lowry the following Brønsted-Lowry bases: (i) SO42, (ii) CH3NH2 -

Using data from Appendix D, calculate [OH]and pH for each of the following solutions: (a) 0.105MNaF, (b) 0.035MNa2 S, (c) a mixture that is 0.045M in NaCH3COO and 0.055M in Ba(CH3COO)2.

Consider the base hydroxylamine, NH2OH. (a) What is the conjugate acid of hydroxylamine? (b) When it acts as a base, which atom in hydroxylamine accepts a proton? (c) There are two atoms in hydroxylamine that have nonbonding electron pairs that could act as proton acceptors. Use Lewis structures and formal charges ers (Section 8.5) to rationalize why one of these two atoms is a much better proton acceptor than the other.

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