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(a) What is meant by the term elementary reaction? (b) What is the difference between a unimolecular and a bimolecular elementary reaction? (c) What is a reaction mechanism? (d) What is meant by the term rate-determining step?

Short Answer

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(a) An elementary reaction is the simplest form of a chemical reaction, involving only one step with a single transition state. (b) Unimolecular elementary reactions involve a single molecule undergoing transformation (Rate = k[A]), while bimolecular reactions involve the collision of two molecules (Rate = k[A][B]). (c) A reaction mechanism is a series of elementary reactions that describe how reactants convert into products, including intermediate species and transition states. (d) The rate-determining step is the slowest step in a reaction mechanism, governing the overall reaction rate and having the highest energy transition state or activation energy.

Step by step solution

01

(a) Definition of Elementary Reaction

Elementary reactions are the simplest form of chemical reactions, involving only one step. They can be represented by a single chemical equation, in which the reactants directly transform into products with only one transition state.
02

(b) Difference between Unimolecular and Bimolecular Elementary Reactions

Unimolecular and bimolecular elementary reactions differ in the number of molecules involved in the reaction: 1. Unimolecular reactions involve a single molecule undergoing a transformation, like a rearrangement or the dissociation of a molecule into two or more products. The rate of such a reaction depends on the concentration of the reacting species, and the rate law can be expressed as Rate = k[A], where A is the reactant and k is the rate constant. 2. Bimolecular reactions involve a collision between two molecules, leading to the formation of new products. Due to the collision requirement, the rate of such a reaction depends on the concentration of both reactants, and the rate law can be expressed as Rate = k[A][B], where A and B are the reacting species and k is the rate constant.
03

(c) Definition of Reaction Mechanism

A reaction mechanism is a series of elementary reactions or steps that take place during the course of a complex chemical reaction. It provides a detailed description of how reactants are converted into products, including all the intermediate species and transition states. A reaction mechanism also helps to establish the relationship between the rate of the overall reaction and the concentrations of reactants and products.
04

(d) Definition of Rate-determining Step

The rate-determining step is the slowest step in a reaction mechanism; it governs the overall rate of the reaction. In a multi-step reaction, the slowest step is the one with the highest energy transition state, or activation energy. The rate of the reaction depends on the rate of this slowest step, and altering the conditions (e.g., temperature or concentration of reactants) of this step will have the most significant effect on the overall reaction rate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unimolecular Reaction
Understanding chemical reactions is akin to decoding the language of molecules, and unimolecular reactions offer a simplified lexicon for this complex dialogue. Imagine a molecule, all alone, yet on the brisk verge of transformation. This lone ranger, without any collision or partner in the reaction saga, rearranges itself or splits into two or more new species. Consider it as a monologue on a molecular stage.

Tracing the rate of such a soliloquy becomes a matter of observing the concentration of this single actor, the reactant. The rate equation for a unimolecular reaction reflects its simplicity: \( \text{Rate} = k[A] \), where \( k \) is the rate constant, revealing how swiftly the performance proceeds, and \( [A] \) represents the concentration of our lone reactant looking for a change.
Bimolecular Reaction
In the bustling streets of chemical interactions, bimolecular reactions are the crowd's favorite, where two molecules collide to give birth to new entities. It's a molecular duet, a dance demanding two partners to tango—distinct from the quiet solitude of unimolecular reactions.

In essence, the rate of a bimolecular reaction is spurred by the presence of both dancers: \( \text{Rate} = k[A][B] \). This formula serves as a numerical choreography where \( k \) is the rhythm of the collision and \( [A] \) and \( [B] \) are the concentrations of the reactants eager to interact. Their concentrations intertwine to determine the pace at which the products form, with the reaction moving forward as harmoniously as the steps of a well-rehearsed dance.
Reaction Mechanism
If chemical reactions are like dramatic plays, the reaction mechanism is the script detailing every act and scene. It's not just a glimpse of the finale but a moment-by-moment account of the transition from reactants to products. This narrative unfolds in a sequence of elementary reactions or steps, each showcasing individual actors and intermediates—akin to a series of short skits that, when pieced together, tell a coherent story.

These steps are punctuated by intermediate species, fleeting characters that exist temporarily before evolving into the final cast of products. Furthermore, each elementary reaction contributes to a grander rate law, an overarching expression that describes how swiftly the entire play reaches its conclusion. The script of the reaction mechanism allows chemists to predict the outcome and pace of the chemical play with scientific precision.
Rate-Determining Step
In every compelling story, there is a pivotal moment that dictates the pace of the narrative. In chemical kinetics, this critical juncture is known as the rate-determining step. Picture a marathon where one sluggish runner sets the rhythm for everyone else—this is the slowest step in a reaction mechanism, the bottleneck that holds sway over the overall rate of the chemical story.

Characterized by the highest energy peak on the reaction path—the steepest hill our marathoners must scale—the rate-determining step is influenced by the conditions surrounding it. Tweaking the temperature or adjusting the concentration can be likened to altering the course of the marathon, thereby altering the time it takes to reach the finish line. When studying complex reactions, identifying the rate-determining step is like pinpointing the climax of a tale, understanding that it directly influences how quickly the story unfolds.

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Most popular questions from this chapter

You perform a series of experiments for the reaction \(A \longrightarrow B+C\) and find that the rate law has the form rate \(=k[\mathrm{~A}]^{x}\). Determine the value of \(x\) in each of the following cases: (a) There is no rate change when \([\mathrm{A}]_{0}\) is tripled. (b) The rate increases by a factor of 9 when \([\mathrm{A}]_{0}\) is tripled. (c) When \([\mathrm{A}]_{0}\) is doubled, the rate increases by a factor of 8 .

What is the molecularity of each of the following elementary reactions? Write the rate law for each. (a) \(2 \mathrm{NO}(g) \longrightarrow \mathrm{N}_{2} \mathrm{O}_{2}(g)\) (b) \(\mathrm{H}_{2} \mathrm{C}-\mathrm{CH}_{2}(g) \longrightarrow \mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{3}(g)\) (c) \(\mathrm{SO}_{3}(g) \longrightarrow \mathrm{SO}_{2}(g)+\mathrm{O}(g)\)

Many primary amines, \(\mathrm{RNH}_{2}\), where \(\mathrm{R}\) is a carbon- containing fragment such as \(\mathrm{CH}_{3}, \mathrm{CH}_{3} \mathrm{CH}_{2}\), and so on, undergo reactions where the transition state is tetrahedral. (a) Draw a hybrid orbital picture to visualize the bonding at the nitrogen in a primary amine (just use a \(\mathrm{C}\) atom for " \(\mathrm{R}^{w}\) ). (b) What kind of reactant with a primary amine can produce a tetrahedral intermediate?

(a) The gas-phase decomposition of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}, \mathrm{SO}_{2} \mathrm{Cl}_{2}(g) \longrightarrow\) \(\mathrm{SO}_{2}(g)+\mathrm{Cl}_{2}(g)\), is first order in \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\). At \(600 \mathrm{~K}\) the halflife for this process is \(2.3 \times 10^{5} \mathrm{~s}\). What is the rate constant at this temperature? (b) At \(320^{\circ} \mathrm{C}\) the rate constant is \(2.2 \times 10^{-5} \mathrm{~s}^{-1}\). What is the half-life at this temperature?

(a) The activation energy for the isomerization of methyl isonitrile (Figure 14.7) is \(160 \mathrm{~kJ} / \mathrm{mol}\). Calculate the fraction of methyl isonitrile molecules that has an energy of \(160.0 \mathrm{~kJ}\) or greater at \(500 \mathrm{~K}\). (b) Calculate this fraction for a temperature of \(520 \mathrm{~K}\). What is the ratio of the fraction at \(520 \mathrm{~K}\) to that at \(500 \mathrm{~K} ?\)

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