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Consider the following reaction: 2NO(g)+2H2(g)N2(g)+2H2O(g) (a) The rate law for this reaction is first order in H2 and second order in NO. Write the rate law. (b) If the rate constant for this reaction at 1000 K is 6.0×104M2 s1, what is the reaction rate when [NO]=0.035M and [H2]=0.015M ? (c) What is the reaction rate at 1000 K when the concentration of NO is increased to 0.10M, while the concentration of H2 is 0.010M ? (d) What is the reaction rate at 1000 K if [NO] is decreased to 0.010M and [H2] is increased to 0.030M ?

Short Answer

Expert verified
The rate law for this reaction is Rate=k[NO]2[H2]. The reaction rates for the given concentrations are: (a) Rate=2.65Ms1 (b) Rate=6.0Ms1 (c) Rate=0.018Ms1

Step by step solution

01

Write the rate law equation

The rate law for this reaction is given as first order in H₂ and second order in NO. We can write this rate law as: Rate=k[NO]2[H2]
02

Use the given rate constant to calculate the reaction rate

The rate constant, k, is given as 6.0×104M2s1. Now we will find the reaction rate for each scenario: (a) For [NO] = 0.035 M and [H₂] = 0.015 M: Rate=k[NO]2[H2]=(6.0×104M2s1)(0.035M)2(0.015M)
03

Calculate the reaction rate for the given concentrations

Now, we will simply calculate the reaction rate for the given concentrations: (a) Rate=(6.0×104)(0.0352)(0.015)=2.65Ms1 (b) For [NO] = 0.10 M and [H₂] = 0.010 M: Rate=(6.0×104)(0.102)(0.010)=6.0Ms1 (c) For [NO] = 0.010 M and [H₂] = 0.030 M: Rate=(6.0×104)(0.0102)(0.030)=0.018Ms1 So the reaction rates for the given concentrations are: (a) Rate=2.65Ms1 (b) Rate=6.0Ms1 (c) Rate=0.018Ms1

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Kinetics
The study of reaction kinetics involves investigating the rates of chemical reactions and the mechanisms by which they occur. This field empowers students and chemists to understand how variables such as temperature, concentration, and catalysts affect the speed of reactions. In educational exercises, we typically focus on reactions progressing in a single step for simplicity; however, real-world scenarios can involve complex multi-step mechanisms. Reaction rates help predict how quickly reactants will be consumed or how soon products will form. By delving into reaction kinetics, students gain crucial insights into the controlled manipulation of industrial processes, environmental systems, and even biological pathways.
Rate Constant
The rate constant, denoted as 'k', is an essential parameter in the rate law equation, reflecting the intrinsic speed of a reaction. It is independent of the concentration of reactants but varies with temperature, as described by the Arrhenius equation. The rate constant is unique to each reaction and its specific conditions and is determined experimentally. In the given exercise, the rate constant is provided, allowing students to calculate the rate of reaction directly without needing to conduct an experiment themselves. The magnitude of 'k' can also hint at whether a reaction proceeds quickly or slowly, forming part of the foundation for understanding chemical kinetics.
Concentration Dependency
Concentration dependency is central to the concept of reaction rates, emphasizing that the rate often changes as the concentration of one or more reactants change. This association is quantified in the rate law for a reaction, which mathematically links the rate with the concentrations of reactants raised to their respective orders. The exercises provided illustrate how variations in reactant concentrations can lead to different reaction rates. Such exercises fortify a student's grasp on predicting the effects of concentration changes, a core skill in chemistry. It's also a practical aspect for real-life scenarios like diluting pollutants or optimizing the yield in industrial synthesis.
Reaction Order
Reaction order refers to the power to which the concentration of a reactant is raised in the rate law equation. It indicates how the reaction rate is affected by the concentration of that reactant. The orders are usually discovered through experiments and can be integers or fractions. In our exercise, the reaction is first order in H2 and second order in NO, thus the reaction rate changes linearly with changes in the H2 concentration but quadratically with changes in NO concentration. Understanding reaction order not only aids students in comprehending the specifics of a chemical reaction but also plays a crucial role in the design and analysis of many chemical processes.

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Most popular questions from this chapter

The gas-phase decomposition of $\mathrm{NO}_{2}, 2 \mathrm{NO}_{2}(g) \longrightarrow2 \mathrm{NO}(g)+\mathrm{O}_{2}(g),$ is studied at 383C, giving the following data:  Time (s) [NO2](M)0.00.1005.00.01710.00.009015.00.006220.00.0047 (a) Is the reaction first order or second order with respect to the concentration of NO2?(b) What is the rate constant? (c) Predict the reaction rates at the beginning of the reaction for initial concentrations of 0.200M,0.100M, and $0.050 \mathrm{M} \mathrm{NO}_{2}$.

(a) What is a catalyst? (b) What is the difference between a homogeneous and a heterogeneous catalyst? (c) Do catalysts affect the overall enthalpy change for a reaction, the activation energy, or both?

(a) What factors determine whether a collision between two molecules will lead to a chemical reaction? (b) According to the collision model, why does temperature affect the value of the rate constant? (c) Does the rate constant for a reaction generally increase or decrease with an increase in reaction temperature?

The reaction 2NO22NO+O2 has the rate constant k=0.63M1 s1. (a) Based on the units for k, is the reaction first or second order in NO2 ? (b) If the initial concentration of NO2 is 0.100M, how would you determine how long it would take for the concentration to decrease to 0.025M ?

Indicate whether each statement is true or false. (a) If you compare two reactions with similar collision factors, the one with the larger activation energy will be faster. (b) A reaction that has a small rate constant must have a small frequency factor. (c) Increasing the reaction temperature increases the fraction of successful collisions between reactants.

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